Chapter 6, Problem 33E

Explanation of Solution

Executing the instruction “0001 49 00 06”:

Given instruction, 0001 49 00 06

• The value “0001” is the address of the instruction.
• The hexadecimal value “49” is an instruction, and “00 06” is the operand.
• The mnemonic for the hexadecimal value “49” is “CHARI”.
• The binary value for the hexadecimal instruction “49” is “01001001”.
• The first five bits express the meaning of the instruction.
  • “01001” – Input to the operand is character.
• So, the instruction “49” gets the character input from the user “(CHARI)”.
  • Enter the character “A” as input.
• The last three bits are used as addressing mode specifier.
  • “001” – Direct addressing mode.
    • The direct addressing mode represents the address of data in the operand.
• Hence, it loads the input value “A” to the given operand’s location “00 06”.

Address and its values

Address	Value
0006	A

Executing the instruction “0004 51 00 06”:

Given instruction, 0004 51 00 06

• The value “0004” is the address of the instruction...