EBK BIOLOGY
EBK BIOLOGY
4th Edition
ISBN: 8220102797376
Author: BROOKER
Publisher: YUZU
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Chapter 6, Problem 3TY
Summary Introduction

Introduction: The equilibrium constant of a particular chemical reaction can be defined as a value of reaction quotient of a reaction at the level of chemical equilibrium. It can be denoted by Keq.

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Question 23 An enzyme has a single active site at which it can bind and hydrolyze either X or Y but the enzyme cannot bind X and Y at the same time. Which of the following statements are TRUE? Multiple answers: Multiple answers are accepted for this question Select one or more answers and submit. For keyboard navigation... SHOW MORE V The Km for X will be affected if Y is present in the reaction mixture. a Y is a competitive inhibitor of X. The Km for X will increase. d. The V for X will be affected if Y is present in the reaction mixture. max pH dependence of Vmax reflects the ionization state of catalytic site e residues. Consider the following: X and Y are methanol (poisonous) and ethanol respectively. If the Km for X = 0.01 M and the Km for Y = 0.001 M then 0.01 M Y is 10 times the concentration of Y required for 0.5 Vmax. Addition of an enzyme to a chemical reaction increases the ratio of g products to reactants (Keg).
For the following first-order liquid-phase reversible reaction, where initially only reactant A is present: k₁ AR, k2 Equilibrium constant: K 1) Express the equilibrium conversion rate, Xe, using K, and demonstrate that Xe can be determined using thermodynamic data. 2) Show how the rate constants kl and k2 can be determined experimentally.
What are the benefits of measuring the initial rate of a reaction Vå for use in kinetic studies? (This is a multi-select question). [ES] can be measured accurately. changes in [S] are negligible, so the value of [S] is known. changes in Km are negligible, so Km can be treated as a constant. V₁ = Vmax. --> A negligible amount of product has formed, so that the back reaction P -- need not be considered. ES
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