Fundamentals of Geotechnical Engineering (MindTap Course List)
Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 6, Problem 6.14P
To determine

Find the equivalent hydraulic conductivity for flow in the horizontal direction (kH(eq)).

Find the ratio of (kV(eq)kH(eq)).

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2. A confined aquifer has a thickness of 85 ft. An 86-in diameter well drilled to the bottom of the aquifer, as shown in fig 3-10, if the hydraulic conductivity of the aquifer is 10 ft / day, and if water is originally 170 ft deep in the well, calculate approximately the maximum rate of flow that can be pumped from the well without dewatering any part of the aquifer. Assume 1000 ft reasonable value for the radius of influence. What will be the average velocity ( Darcy velocity ) of flow in the aquifer at a distance 20 ft from the center of the well?
Solve for the ratio of equivalent hydraulic conductivity with the following given: h1 = 2 m h2 = 2.5 m h3 = 1.8 m h4 = 0.9 m k1 = 1.5E-3 cm/sec k2 = 2.2E-4 cm/sec k3 = 1.6E-4 cm/sec k4 = 4.0E-4 cm/sec What is the ratio of equivalent hydraulic conductivity?
Estimate the equivalent hydraulic conductivity for flow in the horizontal direction. Also calculate the ratio of kv(eq)/kH(eq). Suppose that k1 = 15 x10^-4 cm/s, k2= 5.0x10^-4 cm/s, k3= 3.0 x10^-4 cm/s, k4= 2.0 x10^-4 cm/s, H1= 1.0 m, H2 = 2.0 m, H3 =1.5 m, H4 =1.0m. kH(eq) = kV(eq)/kH(eq)=
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Fundamentals of Geotechnical Engineering (MindTap...
Civil Engineering
ISBN:9781305635180
Author:Braja M. Das, Nagaratnam Sivakugan
Publisher:Cengage Learning