Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 6, Problem 6.3P
To determine
Find the flow rate in
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Refer to Figure 6.14. Find the flow rate in m3 /s/m length (at right angles to the crosssection shown) through the permeable soil layer given H = 3 m, H1 = 2.5 m, h = 2.8 m, L = 25 m, a = 10°, and k = 0.04 cm/s.
Find the rate of flow in m^3/sec/m (at right angles to the cross-section shown in Figure 7.33) through the permeable soil layer. Given: H 4 m, H1 2 m, h 2.75 m, S 30 m, a 14°, and k 0.075 cm/sec.
Refer to Problem 8.4. Using the flow net drawn, calculate the hydraulic uplift force at the base of the hydraulic structure per meter length (measured along the axis of the structure).8.24 For the hydraulic structure shown in Figure 8.24, draw a flow net for flow through the permeable layer and calculate the seepage loss in m3/day/m.
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Fundamentals of Geotechnical Engineering (MindTap Course List)
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- The figure below represents a system with flow in the horizontal direction. Find the value of each pressure charge, level charge, and total charge in A, B, C, D, E, F, G, plus the real and approximate velocity of water flow plotting all of the above, given that soil porosity = 0.33 and transmittance coefficient = 0.50 cm/secarrow_forwardFor the two-dimensional flow system shown below (units in meters):Compute the total flow rate under the Dam. X = 4, Y = 8. Note 1: Point A is located in the middle point of the equipotential lines. Point B is located in the middle point of the flow lines.Note 2: Assume e=0.8 (void ratio) and k=10^-3 cm/s (coeff. of permeability).Note 3: Datum is located at the bottom level of the water (right side of Dam).Note 4: Remember, the figure is drawn to scale. So, use the value of 2X+Y to estimate any dimension that you consider necessary.arrow_forward11. A channel runs almost parallel to a river as shown in the figure. The water level in the river has an elevation of 36 m. and the elevation of the channel is 33 m. The river and channel are 600 m apart and a previous formation of the average thickness of 9 m and hydraulic conductivity of 0.80 m/hr joints them together. Compute the hydraulic gradient Compute the rate of seepage flow from the river to the channel per meter width in liters per day. If the seepage velocity is 0.048 m/day, compute the void ratio of the previous medium.arrow_forward
- Find the rate of flow in m3/sec/m through the permeable soil layer. Given: H = 5.5 m, H1 = 2 m, h = 3.5 m, S = 40 m, a = 17°, and k = 0.085 cm/sec.arrow_forwardA confined aquifer has a thickness of 85 ft. An 86-in diameter well drilled to the bottom of the aquifer, as shown in fig 3-10, if the hydraulic conductivity of the aquifer is 10 ft / day, and if water is originally 170 ft deep in the well, calculate approximately the maximum rate of flow that can be pumped from the well without dewatering any part of the aquifer. Assume 1000 ft reasonable value for the radius of influence. What will be the average velocity ( Darcy velocity ) of flow in the aquifer at a distance 20 ft from the center of the well?arrow_forwardSuppose that a stable hydraulic jump forms between the two sluice gates shown in Figure 5.15. If the flow depth downstream of a sluice gate is 61% of the gate opening (yg), determine the downstream gate opening (yg2) for the following conditions: y1 = 0.61 m, Q = 15 m3/s, b = 5 m. (Hint. Assume no loss of energy through a sluice gate.)arrow_forward
- Given the coefficient k =0.05 m/s and porosity p = 48%, find thetransmissibility (T) in m/s per unit m, if the aquifer width is 1.2 m.Formula: - It is the flow rate per day thru a unit areaunder a unit hydraulic gradient For an aquifer with thickness, Band width, X:T = K*B and Ag = BXThus: Q = (T*X*S)arrow_forwardIn fig 3-5, the aquifer thickness is 10 ft, the hydraulic conductivity of the aquifer is 0.06 m/day, and the river water surface is 7m above the bottom of the aquifer. If it is necessary to maintain a water level in the trench not more than 10 m deep, at what rate must water be pumped out of a 100 m long trench? The distance between the edge of the trench and the river is 300 m. Assume all water comes from the river.arrow_forwardDetermine the slope of the channel bed, expressed in the unit of horizontal length to vertical length, given the cross-sectional area of 8 square meters, the wetted perimeter of 8 meters, a volumetric flow rate of 33.33 cubic meters per second, and a Manning's coefficient of 0.012, using the hydraulic principles and the Manning's equation for open channel flow.arrow_forward
- The depth of flow of water at a certain section of a rectangular channel 2 m wide is 0.3 m and the flow rate is 1.5 m3/sec. Determine whether a hydraulic jump will occur and if so, calculate its height and loss of energy per kg of water.arrow_forwardAn aquifer slopes away from a river, as shown in Fig. 3-7 The hydraulic conductivity of the aquifer which is 20 ft thick is known to be 0.2 ft/day. The water is 20 ft deep in the river, and the bottom of the trench is 30 ft below the bottom of the river and 600 ft away from the edge of the river. The trench is 40 ft deep. Will water flow out of the trench without pumping? If so, what will be the rate of flow?arrow_forwardFor a typical sand and gravel aquifer, estimate the one-year travel distance for water when the hydraulic gradient is 0.0003 m/m.arrow_forward
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