(a)
Interpretation:
The regio and stereoselectivity observe when
Concept Introduction:
Consider elimination reaction where
The product of the elimination reaction is depends upon the β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective and the products are called as regiochemical outcomes.
If there are two different β-protons at a β-position of alkyl halide, then on the basis of stereoselectivity the trans-isomer is favored over cis-isomer.
Syn addition: When two substituents are added over double or triple bond on same side of the compound simultaneously is called syn addition.
Syn elimination: When two substituents bonded in same side of a compound gets cleaved from the substance simultaneously then the elimination is called syn elimination.
(b)
Interpretation:
The regio and stereoselectivity observe when
Concept Introduction:
Consider elimination reaction where alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.
The product of the elimination reaction is depends upon the β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective and the products are called as regiochemical outcomes.
If there are two different β-protons at a β-position of alkyl halide, then on the basis of stereoselectivity the trans-isomer is favored over cis-isomer.
Syn addition: When two substituents are added over double or triple bond on same side of the compound simultaneously is called syn addition.
Syn elimination: When two substituents bonded in same side of a compound gets cleaved from the substance simultaneously then the elimination is called syn elimination.
(c)
Interpretation:
The regio and stereoselectivity observe when
Concept Introduction:
Consider elimination reaction where alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide.
The product of the elimination reaction is depends upon the β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective and the products are called as regiochemical outcomes.
If there are two different β-protons at a β-position of alkyl halide, then on the basis of stereoselectivity the trans-isomer is favored over cis-isomer.
Syn addition: When two substituents are added over double or triple bond on same side of the compound simultaneously is called syn addition.
Syn elimination: When two substituents bonded in same side of a compound gets cleaved from the substance simultaneously then the elimination is called syn elimination.
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Chapter 6 Solutions
OWLv2 with MindTap Reader, 1 term (6 months) Printed Access Card for Brown/Iverson/Anslyn/Foote's Organic Chemistry, 8th Edition
- An unknown compound A of molecular formula C10H18O reacts with H2SO4 to form two compounds (B and C)of molecular formula C10H16. B and C both react with H2 in the presence of Pd-C to form decalin. Ozonolysis of B forms D, and ozonolysis of C forms a diketone E of molecular formula C10H16O2. Identify the structures of compounds A, B, C, and E.arrow_forward(a) Give an acceptable name for each compound, (b) Draw the organic products formed when A or B is treated with each reagent: [1] H3O+; [2] −OH, H2O; [3] CH3CH2CH2MgBr (excess), then H2O; [4] LiAlH4, then H2O.arrow_forwardGive reasons for the following :(i) Ethyl iodide undergoes SN2 reaction faster than ethyl bromide.(ii) (±) 2-Butanol is optically inactive.(iii) C—X bond length in halobenzene is smaller than C—X bond length in CH3—X.arrow_forward
- 5-Hydroxyhexanal forms a six-membered cyclic hemiacetal, which predominates at equilibrium in aqueous solution. (a) Draw a structural formula for this cyclic hemiacetal. (b) How many stereoisomers are possible for 5-hydroxyhexanal? (c) How many stereoisomers are possible for this cyclic hemiacetal? (d) Draw alternative chair conformations for each stereoisomer and label groups axial or Also predict which of the alternative chair conformations for each stereoisomer is more stable.arrow_forwardRank the compounds in each group according to their reactivity toward electrophilic substitution: (a) Chlorobenzene, o-dichlorobenzene, benzene (b) p-Bromonitrobenzene, nitrobenzene, phenol (c) Fluorobenzene, benzaldehyde, o-dimethylbenzenearrow_forward11:43 Q1. (a) (c) (d) (b) Two stereoisomers of but-2-ene are formed when 2-bromobutane reacts with ethanolic potassium hydroxide. (i) Explain what is meant by the term stereoisomers. Library Name and outline a mechanism for the reaction of 2-bromo-2-methylpropane with ethanolic potassium hydroxide to form the alkene 2-methylpropene, (CH3)2C=CH₂ Name of mechanism Mechanism (ii) Draw the structures and give the names of the two stereoisomers of but-2-ene. Stereoisomer 1 Name (iii) Name this type of stereoisomerism. Select Name Stereoisomer 2 When 2-bromo-2-methylpropane reacts with aqueous potassium hydroxide, 2-methylpropan-2-ol is formed as shown by the following equation. CH3 H₂C-C-CH3 + KOH Br Page 2 of 14 CH3 H3C-C-CH3 + KBr ОН State the role of the hydroxide ions in this reaction. Write an equation for the reaction that occurs when CH3CH₂CH₂CH₂Br reacts with an excess of ammonia. Name the organic product of this reaction. Equation Name of product 9,284 Photos, 1,166 Videos For You…arrow_forward
- (a) How will you convert:(i) Benzene to acetophenone (ii) Propanone to 2-Methylpropan-2-ol(b) Give reasons :(i) Electrophilic substitution in benzoic acid takes place at meta position.(ii) Carboxylic acids are higher boiling liquids than aldehydes, ketones and alcohols of comparable molecular masses.(iii) Propanal is more reactive than propanone in nucleophilic addition reactions.arrow_forwardCompound A has molecular formula C7H15B.. Treatment of compound A with sodium ethoxide yields only one elimination product (compound B) and no substitution products. When compound B is treated with dilute sulfuric acid, compound C is obtained, which has molecular formula C7H160. Draw the structures of compounds A, B, and C.arrow_forwardRank the compounds in each group according to their reactivity towardelectrophilic substitution.(a) Chlorobenzene, o-dichlorobenzene, benzene(b) p-Bromonitrobenzene , nitrobenzene, phenol(c) Fluorobenzene, benzaldehyde, a-xylene(d) Benzonitrile, p-methylbenzonitr ile,p-methoxybenzonitrilearrow_forward
- Compound F may be synthesised by the method attached: When 2-chloropropane treated with NaOH and 1-chloropropane treated with NaOH separately produce two different functional groups. Provide both reactions and explain the two different functional groups produced.arrow_forwardTreatment of compound A (C8H17Br) with NaOCH2CH3 affords two constitutional isomers B and C. Ozonolysis of B affords CH2=O and (CH3CH2CH2)2C=O. Ozonolysis of C affords CH3CH2CH2COCH3 and CH3CH2CHO. What is the structure of A?arrow_forwardHow many rings and π(pi) bonds are contained in compound A and draw one possible structure for this compound A. Compound A has molecular formula C6H10 and is hydrogenated to a compound having molecular formula C6H12arrow_forward