Interpretation:
The final volume and mass of liquid water should be deduced based on the given initial and final condition of steam
Concept Introduction:
- For a two-phase liquid-vapor equilibrium mixture the specific volume (V), enthalpy (H) and entropy (S) are given as:
Final mass of liquid water = 0.377 kg
Final volume of liquid water = 0.00378 m3
Given:
Volume of vessel V = 0.15 m3
Initial Temperature of saturated steam =
Final temperature =
Explanation:
Based on the steam tables at Temperature =
Specific volume of liquid, vf = 0.001091 m3/kg
Specific volume of vapor, vg = 0.39248 m3/kg
Again from the steam tables, at Temperature =
Specific volume of liquid, vf = 0.001004 m3/kg
Specific volume of vapor, vg = 32.879 m3/kg
Calculation:
Step 1:
Calculate the final mass of liquid water
In the initial state, the total mass is equivalent to the mass of the vapor
The total volume V = 0.15 m3
Specific volume of vapor, vg = 0.39248 m3/kg
Step 2:
Calculate final volume of liquid water
Thus,
The final mass of liquid water = 0.377 kg
The final volume of liquid water = 0.00378 m3
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Chapter 6 Solutions
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