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MindTap Engineering for Das/Sobhan's Principles of Geotechnical Engineering, SI Edition, 9th Edition, [Instant Access], 2 terms (12 months)
9th Edition
ISBN: 9781305971264
Author: Braja M. Das; Khaled Sobhan
Publisher: Cengage Learning US
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Question
Chapter 6, Problem 6.9P
(a)
To determine
The dry unit weight of compaction in the field.
(b)
To determine
The relative compaction in the field.
(c)
To determine
Compare the relative compaction in the field with the required relative compaction.
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Solve a and b
Show your solution, formula and given
H.W
The detailed results of a standard Proctor test on a soil classified as CL-ML and group name silty clay with sand are
shown in the table below. Determine the maximum dry unit weight and optimum water content.
Diameter of mould = 4 in.
Height of mould = 4.584 in.
Volume of mould = 1/30 ft3.
Weight of mould. M = 4.45 lb.
Unit weight data
Water content data
Weight of wet soil
and mold (Ibs)
Mass of can and
dry soil (grams)
Mass of can and
Mass of can
wet soil (grams)
(grams)
M.
M.
м.
7.32
114.92
111.48
155.08
46.50
7.57
163.12
46.43
7.68
190.43
178.64
46.20
46.50
7.74
193.13
178.24
7.65
188.77
171.58
46.10
Chapter 6 Solutions
MindTap Engineering for Das/Sobhan's Principles of Geotechnical Engineering, SI Edition, 9th Edition, [Instant Access], 2 terms (12 months)
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- A hydrometer test was conducted on the material passing sieve No, 200 and the results are listed in the table below, The results of sieve analysis on the soil showed that the percentage passing No. 4 was 90 % and that passing No. 200 was 20 %. Estimate the clay size fraction in the soil. Table : Results of hydrometer test diameter (mm) 0.0700 0.0400 0.0150 0.0020 % finer (combined) 19 finer 95 80 16 65 13 45 0.0010 30 6 Select one:arrow_forwardA liquid limit test on a clay was performed with the following results. The natural water content of the clay is 38% and plastic limit is 21%. Number of Blows 6 12 20 28 32 Water content (%) 52.5 47.1 42.3 38.6 37.5 What is the liquidity index of this clay? (Use Interpolation) Group of answer choices 0.895 0.96 1.08 0.90 Please answer this asap. For upvote. Thanksarrow_forwardA given soil sample is taken from the field by Bubba Lesh for compaction testing. Before compaction, he finds the void ratio, degree of saturation and moisture content. Then, Bubba Lesh compacts the soil sample through a modified proctor test. No water is added. Explain how the following values change from the uncompacted case to the compacted case (increases, decreases, or remains the same) and a statement describing why: a) Void Ratio (10) b) Degree of Saturation (10) c) Moisture Content (10)arrow_forward
- 3. please answer correctly and show solutionsarrow_forward1. The results of a standard Proctor test are given in the following table. a. Determine the maximum dry unit weight of compaction and the optimum moisture content, given that the Proctor mold volume is 1/30 ft³. b. Determine the void ratio and the degree of saturation at the optimum moisture content given G₁= 2.68. Trial no. 1234567 Weight of moist soil in the mold (lb) 3.92 4.12 4.29 4.37 4.45 4.35 4.20 Moisture content (%) 5.0 7.5 10.0 12.5. 15 17.5 20.0arrow_forwardThe following results were obtained from a liquid limit test on a soil using a liquid limit device. The in-situ water content of this clay is 38% and the plastic limit is 20%. (Note: show the semi-log graph for the determination of the LL) Determine the following: (a) Liquid Limit of the soil, (b) Plasticity Index of the soil, and (c) Liquidity Index of the soil (d) shrinkage limit using the plasticity chartarrow_forward
- The results of a standard Proctor test are given in the following table. Given: Mold volume 1/30 ft' and Gs = 2.69. Determine the void ratio and the degree of saturation at the optimum moisture content. Weight of moist soil Moisture in the mold (lb) Trial no. content (%) 1 3.7 8.6 2 4.15 10.6 4.69 12.5 4 4.62 14.9 5 4.02 16.7 6. 3.63 18.3arrow_forwardb. A soil layer with a moisture content of 10 percent and a unit weight of 16.5 KN per cubic meter has a decrease in volume by 10 percent after compaction. Find the dry specific weight of the soil. Please solve question (b) I have the answer of Question (a)if you need information please use the question a. given data: a. The moisture content of the soil specimen is 20%, and the total weight is 300 gr. Calculate thevoid ratio and degree of saturation if the total volume was 180 cm3. (Gs = 2.5)arrow_forwardAn ASTM D 854 test was done on a sand. The data are shown below. Calculate the specific gravity. Mass of pychnometer = 46.1 grams Mass of pychnometer and dry soil = 67.4 grams Mass of pychnometer, dry soil and water = 157.7 grams Mass of pychnometer and water = 140.9 gramsarrow_forward
- A sample of gray silty clay has a mass of 126 kg. Laboratory tests results give a moist density(ρ) of 2.05 g/cm3, a specific gravity of solids (Gs) of 2.67, and a moisture content (w) of 14.7%.First determine all entries in the phase diagram. Then determine the void ratio (e), the porosity(n), the degree of saturation (S), the dry density (ρd), the dry unit weight (γd), and the moistunit weight (γ).arrow_forwardProblem Set 2: 4. A sample of gray silty clay has a mass of 126 kg. Laboratory tests results give a moist density (p) of 2.05 g/cm³, a specific gravity of solids (G,) of 2.71, and a moisture content (w) of 15.7%. First determine all entries in the phase diagram. Then determine the void ratio (e), the porosity (n), the degree of saturation (S), the dry density (Pa), the dry unit weight (ya), and the moist unit weight (y). Draw the Phase diagram.arrow_forwardA compaction test was conducted in the laboratory and the following information was obtained: • The weight of the compacted soil specimen (including the mold) was determined to be 3815 • The volume of the mold = 1/30 ft³ (944 cm³) • The weight of the mold = 2050 g • The water content in the soil was determined to be 9.1% Find the dry unit weight of the soil (in units of kN/m³).arrow_forward
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