The electric force between a proton and an electron
- a. is weaker than the gravitational force between them
- b. is equal in strength to the gravitational force between them
- c. is stronger than the gravitational force between them
- d. is any of these, depending on the distance between the proton and the electron
To choose: The correct option from the given options.
Answer to Problem 6MC
The correct option is “c. is stronger than the gravitational force between them”.
Explanation of Solution
Given data:
From the given data, it is required to compare the electric force acts between a proton and an electron with respect to the gravitational force acts between them.
Formula used:
Refer to the equation (2-20) in the textbook, and modify the expression for gravitation force acts between the proton and the electron by Newton’s law of gravity as follows.
Here,
Refer to the equation (6-1) in the textbook, and modify the expression for electric force acts between the proton and the electron by Coulomb’s law as follows.
Here,
Consider the distance
Consider the proton’s mass
Calculation of gravitational force acts between the proton and the electron
Substitute
Simplify the expression as follows.
Calculation of electric force acts between the proton and the electron
Substitute
Simplify the expression as follows.
From equation (3), and (4), the force in equation (3) is very much less than the force in equation (4).
Therefore, the electric force acts between the electron and the proton is stronger than the gravitation force acts between the electron and the proton. Thus, the option c is an adequate option.
Since, the electric force acts between the electron and the proton is given as weaker than the gravitational force acts between them in option a, the option a is incorrect answer.
Since, the electric force acts between the electron and the proton is given as equal to the gravitational force acts between them in option b, the option b is incorrect answer.
From the analysis, the only option c is the correct choice. Therefore, the option d is absolutely incorrect.
Conclusion:
Hence, the correct option is “c. is stronger than the gravitational force between them”.
Want to see more full solutions like this?
Chapter 6 Solutions
Package: Loose Leaf The Physical Universe With Connect Access Card
- A certain five cent coin contains 5.00 g of nickel. What fraction of the nickel atoms’ electrons, removed and placed 1.00 m above it, would support the weight of this coin? The atomic mass of nickel is 53.7, and each nickel atom contains 28 electrons and 28 protonsarrow_forward(a) Common transparent tape becomes charged when pulled from a dispenser. If one piece is placed above another, the repulsive force can be great enough to support the top piece’s weight. Assuming equal point charges (only an approximation), calculate the magnitude of the charge if electrostatic force is great enough to support the weight of a mg piece of tape held 1.00 cm above another. (b) Discuss whether the magnitude of this charge is consistent with what is typical of static electricity.arrow_forwardConstruct Your Own Problem Consider identical spherical conducting space ships in deep space where gravitational fields from other bodies are negligible compared to the gravitational attraction between the ships. Construct a problem in which you place identical excess charges on the space ships to exactly counter their gravitational attraction. Calculate the amount of excess charge needed. Examine whether that charge depends on the distance between the centers of the ships, the masses of the ships, or any other factors. Discuss whether this would be an easy, difficult, or even impossible thing to do in practice.arrow_forward
- Compare the law of charges and the law of poles.arrow_forwardWhat is the strength of the electric field between two parallel conducting plates separated by 1.00 cm and having a potential difference (voltage) between them of 1 .50 104 V ?arrow_forwardTwo equal positive charges are placed equidistant on either side of another positive charge. What would the middle positive charge experience? (8.1) (a) a net force to the right (b) a net force to the left (c) a zero net forcearrow_forward
- Compute the electric force acting between the electron and the proton in a hydrogen atom. The radius of the smallest orbit of the electron around the proton is about m.arrow_forwardIn the Millikan oil-drop experiment illustrated in Figure 15.21, an atomizer (a sprayer with a fine nozzle) is used to introduce many tiny droplets of oil between two oppositely charged parallel metal plates. Some of the droplets pick up one or more excess electrons. The charge on the plates is adjusted so that the electric force on the excess electrons exactly balances the weight of the droplet. The idea is to look for a droplet dial has the smallest electric force and assume it has only one excess electron. This strategy lets the observer measure the charge on the electron. Suppose we are using an electric field of 3 104 N/C. The charge on one electron is about 1.6 1019 C. Estimate the radius of an oil drop of density 858 kg/m5 for which its weight could be balanced by the electric force of this field on one electron. (Problem 42 is courtesy of E.F. Redish. For more problems of this type, visit www.physics.umd.cdu/pcrg/.)arrow_forwardRocket observations show that dust particles in Earths upper atmosphere are often electrically charged. (a) Find the distance separating two dust particles if each has a charge of +e and the Coulomb force between them has magnitude 1.00 1014 N. (b) Calculate the mass of one of the dust panicles if this Coulomb force would accelerate it at 4.50 108 m/s2. (In the upper atmosphere, effects from other nearby charges typically result in a small net force and acceleration.)arrow_forward
- Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegePrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning