Two blocks collide on a frictionless surface. After the collision, the blocks stick together. Block A has a mass M and is initially moving to the right at speed v. Block B has a mass 2M and is initially at rest. System C is composed of both blocks, (a) Draw a force diagram for each block at an instant during the collision, (b) Rank the magnitudes of the horizontal forces in your diagram. Explain your reasoning, (c) Calculate the change in momentum of block A, block B, and system C. (d) Is kinetic energy conserved in this collision? Explain your answer. (This problem is courtesy of Edward F. Redish. For more such problems, visit http://www.physics.umd.edu/perg.)
Trending nowThis is a popular solution!
Chapter 6 Solutions
COLLEGE PHYSICS,V.2
Additional Science Textbook Solutions
Mathematical Methods in the Physical Sciences
Lecture- Tutorials for Introductory Astronomy
Integrated Science
College Physics
Sears And Zemansky's University Physics With Modern Physics
Fundamentals Of Physics - Volume 1 Only
- Can i get help with these problemsarrow_forwardCan i get help with these problemsarrow_forwardDetermine the speed of the block with mass mmm = 2.90 kgkg after the collision. Express your answer to three significant figures and include the appropriate units. Part B Determine the speed of the block with mass MMM = 7.50 kgkg after the collision. Express your answer to three significant figures and include the appropriate units. Part C Determine what distance along the incline will the smaller mass climb back after the collision. Express your answer to three significant figures and include the appropriate units.arrow_forward
- A bullet of mass mb is fired horizontally with speed vi at a wooden block of mass mw resting on a frictionless table. The bullet hits the block and becomes completely embedded within it. After the bullet has come to rest within the block, the block, with the bullet in it, is traveling at speed vf . Part A Which of the following best describes this collision? Hint 1. Types of collisions An inelastic collision is a collision in which kinetic energy is not conserved. In a partially inelastic collision, kinetic energy is lost, but the objects colliding do not stick together. From this information, you can infer what completely inelastic and elastic collisions are. ANSWER: Correct Part B Which of the following quantities, if any, are conserved during this collision? Hint 1. When is kinetic energy conserved? Kinetic energy is conserved only in perfectly elastic collisions. ANSWER: perfectly elastic partially inelastic perfectly inelastic Correct Part C What is the speed of the…arrow_forwardCan you show me how to solve c?arrow_forwardThe height of a ball is thrown straight up sith a certain force is a function of the time (t) from which it is released given by f(t)=-0.5gt2+40t (where g is a constant determined by gravity). a. How does the value of t at which the height of the ball is at a maximum depend on the parameter g? b. Use your answer to part (a) to describe how maximum height changes as the parameter g changes. c. Use the envelope theorem to answer pare (b) directly. d. On the Earth g=32, but this value varies somewhat around the globe. If two locations had gravitational constants that differed by 0.1, what would be the difference in the maximum height of a ball tossed in the two places?arrow_forward
- An astronaut of mass 230 kg including his suit and jet pack wants to acquire a velocity of 2.2 m/s to move back toward his space shuttle. Part A Assuming the jet pack can eject gas with a velocity of 37 m/s, what mass of gas will need to be ejected? Express your answer to two significant figures and include the appropriate units. Submit THU HA Value Request Answer < Return to Assignment Units Provide Feedback!arrow_forwardPlease show all workarrow_forwardPlease answer situation5 .Please kindly show clear and complete solutions.thank youarrow_forward
- A ball of mass 0.472 kg moving east (+x direction) with a speed of 3.80 m/sm/s collides head-on with a 0.236 kg ball at rest. Assume that the collision is perfectly elastic. Part A What is the speed of the 0.472-kg ball after the collision? Express your answer to three significant figures and include the appropriate units. v1=_____________ Part B What is the speed of the 0.236-kg ball after the collision? Express your answer to three significant figures and include the appropriate units. v1=______________arrow_forwardA 0.060-kg tennis ball, moving with a speed of 4.1 m/s, has a head-on collision with a 0.10-kg ball initially moving in the same direction at a speed of 3.5 m/s. Part A Assuming a perfectly elastic collision, determine the speed of each ball after the collision. Enter your answers numerically separated by a comma. Express your answers using two significant figures. VG| ΑΣΦ Vtonnis ball Submit Vball = Request Answer www ? m/sarrow_forwardA locomotive engine of mass 1.80*10^5kg starts from rest on horizontal train tracks. The locomotive takes 25 minutes (1500 seconds) to reach maximum speed. The graph in the attached image shows the net external force acting on the locomotive as a function of time. a. Calculate the final speed of the locomotive at the end of the 25 minutes. Show calculations and provide explanations, referencing the graph. b. While coasting down the tracks, the locomotive collides with train car A which was at rest and has a mass of 3.70*10^3kg. After the collision, train car A now travels at 66.4m/s. Calculate the velocity of the locomotive after the collision. c. Train car A continues down the track for 400m where it collides with train car B in such a way that the two cars travel together along the track. The mass of car B is 7.40*10^3kg. The speed of car A just before the collision is 66.4m/s. Calculate the velocity of the car A and car B combination as it continues down the track.arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning