Chapter 6.1, Problem 14OE

To determine

To find: The real roots of the given equation.

Answer to Problem 14OE

The real roots of the given equation are $1\text{ and }-1$ .

Explanation of Solution

Given:

The given equation is

  $x^2=1$

Calculation:

The given expression can be simplified as follows.

  $\begin{array}{l}{x}^2=1\\ x=\sqrt{1}\\ x=\pm 1\\ x=1\text{ and }-1\end{array}$

Any number measurable on the number line whether positive, negative, and decimal or in fractions is called the real number. The real numbers consist of zero also.

Here, $1\text{ and }-1$ are the real number.

Therefore, the real roots of the given equation are $1\text{ and }-1$ . The number $1\text{ and }-1$ are the real number.