9th Edition

ISBN: 9781307573022

Author: CENGEL

Publisher: MCG/CREATE

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Chapter 6.11, Problem 43P

A food refrigerator is to provide a 15,000-kJ/h cooling effect while rejecting 22,000 kJ/h of heat. Calculate the COP of this refrigerator.

FIGURE P6–43

Chapter 6.11, Problem 43P, A food refrigerator is to provide a 15,000-kJ/h cooling effect while rejecting 22,000 kJ/h of heat.

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Chapter 6.11, Problem 42P

Chapter 6.11, Problem 44P

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Chapter 6 Solutions

THERMODYNAMICS-SI ED. EBOOK >I<

Ch. 6.11 - A mechanic claims to have developed a car engine...Ch. 6.11 - Describe an imaginary process that violates both...Ch. 6.11 - Describe an imaginary process that satisfies the...Ch. 6.11 - Describe an imaginary process that satisfies the...Ch. 6.11 - An experimentalist claims to have raised the...Ch. 6.11 - Consider the process of baking potatoes in a...Ch. 6.11 - Prob. 7P Ch. 6.11 - What are the characteristics of all heat engines?Ch. 6.11 - What is the KelvinPlanck expression of the second...Ch. 6.11 - Is it possible for a heat engine to operate...

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A food refrigerator is to provide a 15,000-kJ/h cooling effect while rejecting 22,000 kJ/h of heat. Calculate the COP of this refrigerator. FIGURE P6–43

Solution Summary: The author writes the expression for the rate of conversation of energy principle for air-conditioner.

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