Chapter 6.3, Problem 101E

To determine

To find: The vertical and horizontal component of velocity.

Answer to Problem 101E

  $v_x=70\cos {40}^{\circ }\approx 53.6\text{ ft/s}$

  $v_y=70\sin {40}^{\circ }\approx 45\text{ ft/s}$

  $53.6\text{i}+45\text{j}$

Explanation of Solution

Given: A ball is thrown with an initial velocity of 70 feet per second, at an angle of ${40}^{\circ }$ with the horizontal as shown in figure.

  

The velocity of ball is 70 feet per seconds and makes angle ${40}^{\circ }$ with positive direction of x -axis.

Horizontal component of velocity, $v_x=70\cos {40}^{\circ }\approx 53.6\text{ ft/s}$

Vertical component of velocity, $v_y=70\sin {40}^{\circ }\approx 45\text{ ft/s}$

Hence, the vector form of velocity is Horizontal component of velocity, $53.6\text{i}+45\text{j}$