A Transition to Advanced Mathematics
A Transition to Advanced Mathematics
8th Edition
ISBN: 9781285463261
Author: Douglas Smith, Maurice Eggen, Richard St. Andre
Publisher: Cengage Learning
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Chapter 6.3, Problem 8E

(a)

To determine

To find: the order of element 3 in the group (4,+) .

(a)

Expert Solution
Check Mark

Answer to Problem 8E

The order of the element 3 of the group (4,+) is 4.

Explanation of Solution

Concept used:

The order of an element ‘a’ of an additive group is defined as the least positive integer n such that na=0 , where 0 is the identity element in the additive group.

Calculation:

Consider the group (4,+) .

  4={0,1,2,3,4}

Now, for the element 3 of the group (4,+) .

  1(3)=3=3(mod4)2(3)=6=2(mod4)3(3)=9=1(mod4)4(3)=12=0(mod4)

Thus, the order of the element 3 of the group (4,+) is 4.

(b)

To determine

To find: the order of element 3 in the group (5,+) .

(b)

Expert Solution
Check Mark

Answer to Problem 8E

The order of the element 3 of the group (5,+) is 5.

Explanation of Solution

Concept used:

The order of an element ‘a’ of an additive group is defined as the least positive integer n such that na=0 , where 0 is the identity element in the additive group.

Calculation:

Consider the group (5,+) .

  5={0,1,2,3,4,5}

Now, for the element 3 of the group (5,+) .

  1(3)=3=3(mod5)2(3)=6=1(mod5)3(3)=9=4(mod5)4(3)=12=2(mod5)5(3)=15=0(mod5)

Thus, the order of the element 3 of the group (5,+) is 5.

(c)

To determine

To find: the order of element 3 in the group (6,+) .

(c)

Expert Solution
Check Mark

Answer to Problem 8E

The order of the element 3 of the group (6,+) is 2.

Explanation of Solution

Concept used:

The order of an element ‘a’ of an additive group is defined as the least positive integer n such that na=0 , where 0 is the identity element in the additive group.

Calculation:

Consider the group (6,+) .

  6={0,1,2,3,4,5,6}

Now, for the element 3 of the group (6,+) .

  1(3)=3=3(mod6)2(3)=6=0(mod6)3(3)=9=3(mod6)4(3)=12=0(mod6)5(3)=15=3(mod6)6(3)=18=0(mod6)

Thus, the order of the element 3 of the group (6,+) is 2.

(d)

To determine

To find: the order of element 3 in the group (8,+) .

(d)

Expert Solution
Check Mark

Answer to Problem 8E

The order of the element 3 of the group (8,+) is 8.

Explanation of Solution

Concept used:

The order of an element ‘a’ of an additive group is defined as the least positive integer n such that na=0 , where 0 is the identity element in the additive group.

Calculation:

Consider the group (8,+) .

  8={0,1,2,3,4,5,6,7,8}

Now, for the element 3 of the group (8,+) .

  1(3)=3=3(mod8)2(3)=6=6(mod8)3(3)=9=1(mod8)4(3)=12=4(mod8)5(3)=15=7(mod8)6(3)=18=2(mod8)7(3)=21=5(mod8)8(3)=24=0(mod8)

Thus, the order of the element 3 of the group (8,+) is 8.

(e)

To determine

To find: the order of element 3 in the group (9,+) .

(e)

Expert Solution
Check Mark

Answer to Problem 8E

The order of the element 3 of the group (9,+) is 3.

Explanation of Solution

Concept used:

The order of an element ‘a’ of an additive group is defined as the least positive integer n such that na=0 , where 0 is the identity element in the additive group.

Calculation:

Consider the group (9,+) .

  9={0,1,2,3,4,5,6,7,8,9}

Now, for the element 3 of the group (9,+) .

  1(3)=3=3(mod9)2(3)=6=6(mod9)3(3)=9=0(mod9)4(3)=12=3(mod9)5(3)=15=6(mod9)6(3)=18=0(mod9)7(3)=21=3(mod9)8(3)=24=6(mod9)9(3)=27=0(mod9)

Thus, the order of the element 3 of the group (9,+) is 3.

(f)

To determine

To find: the order of element 3 in the group (5,·) .

(f)

Expert Solution
Check Mark

Answer to Problem 8E

The order of the element 3 of the group (5,·) is 4.

Explanation of Solution

Concept used:

The order of an element ‘a’ of a multiplicative group is defined as the least positive integer n such that an=1 , where 1 is the identity element in the multiplicative group.

Calculation:

Consider the group (5,·) .

  5={1,2,3,4}

Now, for the element 3 of the group (5,·) .

  31=3=3(mod5)32=9=4(mod5)33=27=2(mod5)34=81=1(mod5)

Thus, the order of the element 3 of the group (5,·) is 4.

(g)

To determine

To find: the order of element 3 in the group (7,·) .

(g)

Expert Solution
Check Mark

Answer to Problem 8E

The order of the element 3 of the group (7,·) is 6.

Explanation of Solution

Concept used:

The order of an element ‘a’ of a multiplicative group is defined as the least positive integer n such that an=1 , where 1 is the identity element in the multiplicative group.

Calculation:

Consider the group (7,·) .

  7={1,2,3,4,5,6}

Now, for the element 3 of the group (7,·) .

  31=3=3(mod7)32=9=2(mod7)33=27=6(mod7)34=81=4(mod7)35=243=5(mod7)36=729=1(mod7)

Thus, the order of the element 3 of the group (7,·) is 6.

(h)

To determine

To find: the order of element 3 in the group (11,·) .

(h)

Expert Solution
Check Mark

Answer to Problem 8E

The order of the element 3 of the group (11,·) is 5.

Explanation of Solution

Concept used:

The order of an element ‘a’ of a multiplicative group is defined as the least positive integer n such that an=1 , where 1 is the identity element in the multiplicative group.

Calculation:

Consider the group (11,·) .

  11={1,2,3,4,5,6,7,8,9,10}

Now, for the element 3 of the group (11,·) .

  31=3=3(mod11)32=9=9(mod11)33=27=5(mod11)34=81=4(mod11)35=243=1(mod11)36=729=3(mod11)37=2187=9(mod11)

Thus, the order of the element 3 of the group (11,·) is 5.

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Chapter 6 Solutions

A Transition to Advanced Mathematics

Ch. 6.1 - Prob. 11ECh. 6.1 - Prob. 12ECh. 6.1 - Prob. 13ECh. 6.1 - Prob. 14ECh. 6.1 - Prob. 15ECh. 6.1 - Prob. 16ECh. 6.2 - Show that each of the following algebraic...Ch. 6.2 - Prob. 2ECh. 6.2 - Prob. 3ECh. 6.2 - Prob. 4ECh. 6.2 - Prob. 5ECh. 6.2 - Prob. 6ECh. 6.2 - Prob. 7ECh. 6.2 - Prob. 8ECh. 6.2 - Prob. 9ECh. 6.2 - Prob. 10ECh. 6.2 - Prob. 11ECh. 6.2 - Prob. 12ECh. 6.2 - Prob. 13ECh. 6.2 - Prob. 14ECh. 6.2 - Prob. 15ECh. 6.2 - Prob. 16ECh. 6.2 - Prob. 17ECh. 6.2 - Prob. 18ECh. 6.3 - Prob. 1ECh. 6.3 - Prob. 2ECh. 6.3 - Prob. 3ECh. 6.3 - Prob. 4ECh. 6.3 - Prob. 5ECh. 6.3 - Prob. 6ECh. 6.3 - Prob. 7ECh. 6.3 - Prob. 8ECh. 6.3 - Prob. 9ECh. 6.3 - Prob. 10ECh. 6.3 - Prob. 11ECh. 6.3 - Prob. 12ECh. 6.3 - Prob. 13ECh. 6.3 - Prove that for every natural number m greater than...Ch. 6.3 - Prove that every subgroup of a cyclic group is...Ch. 6.3 - Prob. 16ECh. 6.3 - Prob. 17ECh. 6.4 - Prob. 1ECh. 6.4 - Prob. 2ECh. 6.4 - Prob. 3ECh. 6.4 - Prob. 4ECh. 6.4 - Prob. 5ECh. 6.4 - Prob. 6ECh. 6.4 - Prob. 7ECh. 6.4 - Prob. 8ECh. 6.4 - Prob. 9ECh. 6.4 - Prob. 10ECh. 6.4 - Prob. 11ECh. 6.4 - Prob. 12ECh. 6.4 - Prob. 13ECh. 6.4 - Prob. 14ECh. 6.4 - Prob. 15ECh. 6.4 - Prob. 16ECh. 6.4 - Is S3 isomorphic to 6,+? Explain.Ch. 6.4 - Prove that the relation of isomorphism is an...Ch. 6.4 - Prob. 19ECh. 6.4 - Prob. 20ECh. 6.5 - Prob. 1ECh. 6.5 - Prob. 2ECh. 6.5 - Prob. 3ECh. 6.5 - Prob. 4ECh. 6.5 - Prob. 5ECh. 6.5 - Prob. 6ECh. 6.5 - Prob. 7ECh. 6.5 - Prob. 8ECh. 6.5 - Prob. 9ECh. 6.5 - Prob. 10ECh. 6.5 - Prob. 11ECh. 6.5 - Prob. 12ECh. 6.5 - Prob. 13ECh. 6.5 - Prob. 14ECh. 6.5 - Prob. 15E
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