APPLIED STATISTICS IN BUSINESS AND ECO
APPLIED STATISTICS IN BUSINESS AND ECO
5th Edition
ISBN: 9781260229509
Author: DOANE
Publisher: MCG
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter 6.4, Problem 23SE

In the Ardmore Hotel, 20 percent of the customers pay by American Express credit card. (a) Of the next 10 customers, what is the probability that none pay by American Express? (b) At least two? (c) Fewer than three? (d) What is the expected number who pay by American Express? (e) Find the standard deviation. (f) Construct the probability distribution (using Excel or Appendix A). (g) Make a graph of its PDF, and describe its shape.

(a)

Expert Solution
Check Mark
To determine

Find the probability that no one will pay by American Express.

Answer to Problem 23SE

The probability for none of them pay by American express out of 10 customers is 0.1074.

Explanation of Solution

Calculation:

The given information is that in Ardmore hotel, the customers pay by American express credit card is nearly 20%.

Binomial Distribution:

The random variable X denotes the number of successes in trail of n.

The PDF of the distribution is,

P(X=x)=n!x!(nx)!πx(1π)nx

Here n denotes the number of trails and π denotes the value of the probability for success.

In the given situation, the random variable X variable denotes the number of customers, the value of n is 10 and the value of π is 0.20.

The probability for no one pay by American express card in next 10 customers is P(X=0).

Software procedure:

Step-by-step software procedure to obtain probability value using EXCEL software is as follows:

  • Open an EXCEL file.
  • In cell A1, enter the formula “=BINOM.DIST(0,10,0.20,0)”
  • Output using EXCEL software is given below:

APPLIED STATISTICS IN BUSINESS AND ECO, Chapter 6.4, Problem 23SE , additional homework tip  1

From the output, the value of P(X=0) is 0.1074.

Thus, the probability for none of them pay by American express out of 10 customers is 0.1074.

(b)

Expert Solution
Check Mark
To determine

Find the probability that at least two customers will pay by American Express.

Answer to Problem 23SE

The probability that at least two customers will pay by American Express is 0.6242.

Explanation of Solution

Calculation:

The probability for at least two customers pay by American express card in next 10 customers is,

P(X2)=1P(X1).

Probability = 1– BINOM.DIST(x, n, probability, cumulative)

Software procedure:

Step-by-step software procedure to obtain probability value using EXCEL software is as follows:

  • Open an EXCEL file.
  • In cell A1, enter the formula “=BINOM.DIST(1,10,0.20,1)”
  • Output using EXCEL software is given below:

APPLIED STATISTICS IN BUSINESS AND ECO, Chapter 6.4, Problem 23SE , additional homework tip  2

From the output, the value of P(X1) is 0.3758.

Then the value of P(X2) is,

P(X2)=10.3758=0.6242

Thus, the probability for at least 2 customers will pay by American express out of 10 customers is 0.6242.

(c)

Expert Solution
Check Mark
To determine

Find the probability that fewer than 3 customers will pay by American Express.

Answer to Problem 23SE

The probability that fewer than 3 customers will pay by American Express is 0.6778.

Explanation of Solution

Calculation:

The probability for fewer than 3 customers pay by American express card in next 10 customers is,

P(X<3)=P(X2).

Software procedure:

Step-by-step software procedure to obtain probability value using EXCEL software is as follows:

  • Open an EXCEL file.
  • In cell A1, enter the formula “=BINOM.DIST(2,10,0.20,1)”
  • Output using EXCEL software is given below:

APPLIED STATISTICS IN BUSINESS AND ECO, Chapter 6.4, Problem 23SE , additional homework tip  3

From the output, the value of P(X<3) is 0.6778.

Thus, the probability for fewer than 3 customers will pay by American express out of 10 customers is 0.6778.

(d)

Expert Solution
Check Mark
To determine

Find the expected number of customers will by American express.

Answer to Problem 23SE

The expected number of customers will by American express is 2.

Explanation of Solution

Calculation:

The formula for expected value is,

μ=nπ

The expected number of customers is,

μ=nπ=10×0.20=2

Thus, the expected number of customers pay by American express is 2.

(e)

Expert Solution
Check Mark
To determine

Find the standard deviation.

Answer to Problem 23SE

The standard deviation is 1.2649.

Explanation of Solution

Calculation:

The formula for standard deviation is,

σ=nπ(1π)

Calculate the standard deviation is,

σ=10×0.20(10.20)=10×0.20(0.80)=1.6=1.2649

Thus, the standard deviation is 1.2649.

(f)

Expert Solution
Check Mark
To determine

Construct the probability distribution.

Explanation of Solution

Calculation:

Construct the probability distribution:

Software procedure:

Step by step procedure to obtain probability distribution by using MegaStat software is as follows:

  • Open an EXCEL file, Go to Add-ins, select MegaStat.
  • Choose Probability, select the Discrete probability distributions.
  • In Binomial, enter number of trails as 10 and probability occurrence as 0.2.
  • Click on Ok.
  • Output using EXCEL software is given below:

APPLIED STATISTICS IN BUSINESS AND ECO, Chapter 6.4, Problem 23SE , additional homework tip  4

(g)

Expert Solution
Check Mark
To determine

Draw the graph for PDF and shape of the distribution.

Answer to Problem 23SE

The distribution shape is right-skewed.

Explanation of Solution

Calculation:

Shape of the distribution:

Symmetric distribution:

When the left and right sides of the distribution are approximately equal or mirror images of each other, then it is symmetric distribution. For this distribution, mean and standard deviation are useful. For a symmetric distribution, mean=median=mode.

Right skewed distribution:

If the tail of the distribution is elongated towards the right, then it is a right-skewed distribution. It is also called as positively skewed. For right skewed, mean>median>mode.

Left-skewed distribution:

If the tail of the distribution is elongated towards the left, then it is a left-skewed distribution. It is also called as negatively skewed. For left skewed, mean <median<mode.

Graph of the probability distribution:

Software procedure:

Step by step procedure to obtain probability distribution by using MegaStat software is as follows:

  • Open an EXCEL file, Go to Add-ins, select MegaStat.
  • Choose Probability, select the Discrete probability distributions.
  • In Binomial, enter number of trails as 10 and probability occurrence as 0.2.
  • Select Display graph.
  • Click on Ok.
  • Output using EXCEL software is given below:

APPLIED STATISTICS IN BUSINESS AND ECO, Chapter 6.4, Problem 23SE , additional homework tip  5

Observation:

From the output, the tail of the distribution is elongated towards the right.

Thus, the distribution shape is right-skewed.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 6 Solutions

APPLIED STATISTICS IN BUSINESS AND ECO

Ch. 6.3 - Prob. 11SECh. 6.3 - Prob. 12SECh. 6.4 - List the X values that are included in each...Ch. 6.4 - Write the probability of each italicized event in...Ch. 6.4 - Find the mean and standard deviation for each...Ch. 6.4 - Prob. 16SECh. 6.4 - Calculate each binomial probability: a. X = 5, n =...Ch. 6.4 - Calculate each binomial probability: a. X = 2, n =...Ch. 6.4 - Prob. 19SECh. 6.4 - Prob. 20SECh. 6.4 - Prob. 21SECh. 6.4 - Calculate each binomial probability: a. Fewer than...Ch. 6.4 - In the Ardmore Hotel, 20 percent of the customers...Ch. 6.4 - Historically, 5 percent of a mail-order firms...Ch. 6.4 - At a Noodles Company restaurant, the probability...Ch. 6.4 - J.D. Power and Associates says that 60 percent of...Ch. 6.4 - Prob. 27SECh. 6.4 - Police records in the town of Saratoga show that...Ch. 6.5 - Find the mean and standard deviation for each...Ch. 6.5 - Find the mean and standard deviation for each...Ch. 6.5 - Calculate each Poisson probability: a. P(X = 6), ...Ch. 6.5 - Prob. 32SECh. 6.5 - Calculate each compound event probability: a. P(X ...Ch. 6.5 - Calculate each compound event probability: a. P(X ...Ch. 6.5 - Prob. 35SECh. 6.5 - Prob. 36SECh. 6.5 - According to J.D. Power and Associates 2006...Ch. 6.5 - At an outpatient mental health clinic, appointment...Ch. 6.5 - The average number of items (such as a drink or...Ch. 6.5 - (a) Why might the number of yawns per minute by...Ch. 6.5 - Prob. 41SECh. 6.5 - Prob. 42SECh. 6.5 - Prob. 43SECh. 6.5 - Prob. 44SECh. 6.5 - The probability that a passenger's bag will be...Ch. 6.6 - (a) State the values that X can assume in each...Ch. 6.6 - ABC Warehouse has eight refrigerators in stock....Ch. 6.6 - A statistics textbook chapter contains 60...Ch. 6.6 - Fifty employee travel expense reimbursement...Ch. 6.6 - A medical laboratory receives 40 blood specimens...Ch. 6.6 - Prob. 51SECh. 6.6 - Two hundred employee travel expense reimbursement...Ch. 6.6 - A law enforcement agency processes 500 background...Ch. 6.6 - Four hundred automobiles arc to be inspected for...Ch. 6.7 - Find each geometric probability. a. P(X = 5) when ...Ch. 6.7 - In the Ardmore Hotel. 20 percent of the guests...Ch. 6.7 - Prob. 57SECh. 6.8 - The height of a Los Angeles Lakers basketball...Ch. 6.8 - The height of a Los Angeles Lakers basketball...Ch. 6.8 - Prob. 60SECh. 6.8 - Prob. 61SECh. 6 - Define (a) random process, (b) random variable,...Ch. 6 - Without using formulas, explain the meaning of (a)...Ch. 6 - What is the difference between a PDF and a CDF?...Ch. 6 - (a) What are the two parameters of a uniform...Ch. 6 - (a) Describe a Bernoulli experiment and give two...Ch. 6 - Prob. 6CRCh. 6 - (a) What are the parameters of a Poisson...Ch. 6 - In the binomial and Poisson models, why is the...Ch. 6 - (a) When are we justified in using the Poisson...Ch. 6 - Prob. 10CRCh. 6 - When are we justified in using (a) the Poisson...Ch. 6 - Name a situation when we would need the (a)...Ch. 6 - What do Rules 1 and 2 say about transforming a...Ch. 6 - What do Rules 3 and 4 say about sums of several...Ch. 6 - In Rule 5, what does the covariance measure? What...Ch. 6 - The probability that a 30-year-old white male will...Ch. 6 - Prob. 63CECh. 6 - Prob. 64CECh. 6 - Prob. 66CECh. 6 - In a certain year, on average 10 percent of the...Ch. 6 - The probability that an American CEO can transact...Ch. 6 - In a certain Kentucky Fried Chicken franchise,...Ch. 6 - In a certain Kentucky Fried Chicken franchise,...Ch. 6 - Write the Excel binomial formula for each...Ch. 6 - Tired of careless spelling and grammar, a company...Ch. 6 - Prob. 73CECh. 6 - Prob. 74CECh. 6 - Prob. 75CECh. 6 - Write the Excel formula for each Poisson...Ch. 6 - A small feeder airline knows that the probability...Ch. 6 - Although television HDTV converters are tested...Ch. 6 - Prob. 79CECh. 6 - There is a 70 percent chance that an airline...Ch. 6 - Lunch customers arrive at a Noodles Company...Ch. 6 - In a major league baseball game, the average is...Ch. 6 - Prob. 83CECh. 6 - In a recent year, potentially dangerous commercial...Ch. 6 - At an outpatient mental health clinic, appointment...Ch. 6 - Prob. 86CECh. 6 - Prob. 87CECh. 6 - Past insurance company audits have found that 2...Ch. 6 - Prob. 89CECh. 6 - In Northern Yellowstone Lake, earthquakes occur at...Ch. 6 - On New Yorks Verrazano Narrows bridge, traffic...Ch. 6 - Leaks occur in a pipeline at a mean rate of 1 leak...Ch. 6 - Prob. 93CECh. 6 - The probability is .03 that a passenger on United...Ch. 6 - Prob. 95CECh. 6 - On average, 2 percent of all persons who are given...Ch. 6 - Prob. 97CECh. 6 - Prob. 99CECh. 6 - The probability that a bakery customer will order...Ch. 6 - Prob. 101CECh. 6 - For patients aged 81 to 90, the probability is .07...Ch. 6 - Prob. 103CECh. 6 - Prob. 104CECh. 6 - Prob. 105CECh. 6 - The Rejuvo Corp. manufactures granite countertop...Ch. 6 - Prob. 107CECh. 6 - Prob. 108CECh. 6 - Prob. 109CECh. 6 - Prob. 110CECh. 6 - Malaprop Ltd. sells two products. Daily sales of...
Knowledge Booster
Background pattern image
Statistics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
  • Text book image
    College Algebra
    Algebra
    ISBN:9781337282291
    Author:Ron Larson
    Publisher:Cengage Learning
    Text book image
    College Algebra
    Algebra
    ISBN:9781938168383
    Author:Jay Abramson
    Publisher:OpenStax
Text book image
College Algebra
Algebra
ISBN:9781337282291
Author:Ron Larson
Publisher:Cengage Learning
Text book image
College Algebra
Algebra
ISBN:9781938168383
Author:Jay Abramson
Publisher:OpenStax
Continuous Probability Distributions - Basic Introduction; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=QxqxdQ_g2uw;License: Standard YouTube License, CC-BY
Probability Density Function (p.d.f.) Finding k (Part 1) | ExamSolutions; Author: ExamSolutions;https://www.youtube.com/watch?v=RsuS2ehsTDM;License: Standard YouTube License, CC-BY
Find the value of k so that the Function is a Probability Density Function; Author: The Math Sorcerer;https://www.youtube.com/watch?v=QqoCZWrVnbA;License: Standard Youtube License