Chapter 6.4, Problem 40STP

To determine

To find: Percent error of the prediction.

Answer to Problem 40STP

Percent error of prediction is $-58.33\%$

Explanation of Solution

Given information:

Number of games predicted to win $=$ Estimated value $=5$

Number of games won $=$ Actual value $=12$ .

Percent error $=\frac{A}{O}\times 100$

Where

  $A=$ Absolute value.

  $O=$ Actual value.

From given information

Number of games predicted to win $=$ Estimated value $=5$

Number of games won $=$ Actual value $=12$ .

Absolute value = Estimated value $-$ Actual value.

  $\begin{array}{l}\Rightarrow A=5-12\\ \Rightarrow A=-7\end{array}$

Therefore,

Percent error $=\frac{-7}{12}\times 100$

  $\Rightarrow$ Percent error $=\frac{-700}{12}$

  $\Rightarrow$ Percent error $=-58.33$

So, Percent error of prediction is $-58.33\%$ .