Explanation Given: The height and square basea box: h = 3 m b = 2 m Density at height y is f ( y ) = 1000 − 100 y k g / m 3 Calculation: It is known that that the work done is W = ∫ y 1 y 2 F ( y ) d y . Here the equation is V = ( b , b ) ∂ h Mass is the product of volume and density. then m = p ⋅ V p = f ( y ) = ( 1000 − 100 ) kg/m 3 And the force is F = m g Now mass and force of the structure is m = ( 1000 − 100 y ) × 4 × ∂ h F = ( 1000 − 100 y ) × 4 × ∂ h × ( 9.81 ) The work done is W = ∫ 0 h ( F ( x ) y ) y d y W = ∫ 0 h ( 1000 − 100 y ) 4 ( 9

4th Edition

ISBN: 9781319308858

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 6.5, Problem 16E

To determine

To calculate:

the work against gravity required to build a box.

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Chapter 6.5, Problem 15E

Chapter 6.5, Problem 17E

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The Deligne Dam on the Cayley River is built so that the wall facing the water is shaped like the region above the curve y=0.8x2 and below the line y=240. (Here, distances are measured in meters.) The water level is 32 meters below the top of the dam. Find the force exerted on the dam by water pressure. Water has a density of 1000 kg/m3, and the acceleration due to gravity is 9.8 m/sec2. Force = _________ in newtons Using integral application: Context from my notes: In fluid without motion, the pressure P at depth h is P=w*h, where w is the fluid's weight - density. Fluid force on a constant - depth surface: F = p*A = w*h*A, where A stands for area of the surface. I keep getting an absurd number and don't know what I am doing wrong exactly. Thank you in advance for the help.

The Deligne Dam on the Cayley River is built so that the wall facing the water is shaped like the region above the curve y 0.3x² and below the line y 180. (Here, distances are measured in meters.) The water level is 36 meters below the top of the dam. Find the force (in Newtons) exerted on the dam by water pressure. (Water has a density of 1000kg/m³, and the acceleration of gravity is 9.8m/sec².) Answer:

Chapter 6 Solutions

CALCULUS:EARLY TRANS.(LL)-W/ACCESS

Ch. 6.1 - Prob. 1PQ Ch. 6.1 - Prob. 2PQ Ch. 6.1 - Prob. 3PQ Ch. 6.1 - Prob. 4PQ Ch. 6.1 - Prob. 5PQ Ch. 6.1 - Prob. 6PQ Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E

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the work against gravity required to build a box.

Solution Summary: The author calculates the work against gravity required to build a box. The equation is V=(b,b)partial h

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To calculate: the work against gravity required to build a box.

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Chapter 6 Solutions

To calculate:

the work against gravity required to build a box.