a. Explanation Given: Rate of revenue value is R ' ( t ) = 5000 e − 0.2 t . Constant rate is $ 676 / w k . Calculation: Consider the following function that represents the rate of revenue: R ' ( t ) = 5000 e − 0.2 t And, the rate of campaign expenses is $ 676 per week. Assume that for t = t 0 weeks, the rate of revenue exceeds the rate of cost. That is, 5000 e − 0.2 t 0 > 676 e − 0 b. To determine To find: the net earnings generated by the campaign during the period of time determined in part a. (c) To determine To interpret: the net earnings in part b

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Question

Chapter 6.6, Problem 21PS

To determine

To find: the number of weeks the rate of revenue exceeding the rate of cost.

To determine

To find:the net earnings generated by the campaign during the period of time determined in part a.

(c)

To determine

To interpret:the net earnings in part b

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Chapter 6.6, Problem 20PS

Chapter 6.6, Problem 22PS

Chapter 6 Solutions

Calculus

Ch. 6.1 - Prob. 1PS Ch. 6.1 - Prob. 2PS Ch. 6.1 - Prob. 3PS Ch. 6.1 - Prob. 4PS Ch. 6.1 - Prob. 5PS Ch. 6.1 - Prob. 6PS Ch. 6.1 - Prob. 7PS Ch. 6.1 - Prob. 8PS Ch. 6.1 - Prob. 9PS Ch. 6.1 - Prob. 10PS

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The surface area and volume of cone, cylinder, prism and pyramid; Author: AtHome Tuition;https://www.youtube.com/watch?v=SlaQmaJCOt8;License: Standard YouTube License, CC-BY

the number of weeks the rate of revenue exceeding the rate of cost.

Solution Summary: The author calculates that the rate of revenue exceeds the cost for 10weeks. The net earnings generated by the campaign during the period of time determined in part a.

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To find: the number of weeks the rate of revenue exceeding the rate of cost.

To find:the net earnings generated by the campaign during the period of time determined in part a.

To interpret:the net earnings in part b

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Chapter 6 Solutions