Translate each word problem to an equation or a system of equations and select a correct translation from equations A–O. A. 12 2 + 12 2 = x 2 B. x ( x + 26 ) = 180 C. 10 , 311 + 5 % x = x D. x + y = 85 , 5 x + 25 y = 13.85 E. x 2 + 4 2 = 12 2 F. 240 x − 18 = 384 x G. x + 5 % x = 10 , 311 H. x 65 + 1 = x 85 I. x 65 + x 85 = 1 J. x + y + z = 180 , y = 4 x , z = x + y − 27 K. 2 x + 2 ( x + 26 ) = 180 L. 384 x − 18 = 240 x M. x + y = 85 , 0.05 x + 0.25 y = 13.85 N. 2 x + 2 ( x + 24 ) = 240 O. 72 x − 3 + 24 x + 3 = 16 Money Borrowed . Claire borrows some money at 5% simple interest. After 1 year, $10,311 pays off her loan. How much did she originally borrow?
Translate each word problem to an equation or a system of equations and select a correct translation from equations A–O. A. 12 2 + 12 2 = x 2 B. x ( x + 26 ) = 180 C. 10 , 311 + 5 % x = x D. x + y = 85 , 5 x + 25 y = 13.85 E. x 2 + 4 2 = 12 2 F. 240 x − 18 = 384 x G. x + 5 % x = 10 , 311 H. x 65 + 1 = x 85 I. x 65 + x 85 = 1 J. x + y + z = 180 , y = 4 x , z = x + y − 27 K. 2 x + 2 ( x + 26 ) = 180 L. 384 x − 18 = 240 x M. x + y = 85 , 0.05 x + 0.25 y = 13.85 N. 2 x + 2 ( x + 24 ) = 240 O. 72 x − 3 + 24 x + 3 = 16 Money Borrowed . Claire borrows some money at 5% simple interest. After 1 year, $10,311 pays off her loan. How much did she originally borrow?
Solution Summary: The author explains how to determine the system of equations and select the correct translation from the following options.
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