Chapter 6.7, Problem 9MRE

To determine

Simplify the given equation.

Answer to Problem 9MRE

  $\frac{y^2+3y-7}{y-2}$

Explanation of Solution

Given information:

Given: $y+3+\frac{2y-1}{y-2}$

Calculation:

Here, we have:

  $\begin{array}{l}\to y+3+\frac{2y-1}{y-2}\\ \to y+3+\frac{2y-1}{y-2}=\frac{y+3}{1}+\frac{2y-1}{y-2}\\ \to \frac{\left(y+3\right)\left(y-2\right)}{\left(y-2\right)}+\frac{2y-1}{y-2}\\ \to \frac{y^2+y-6}{y-2}+\frac{2y-1}{y-2}\\ \to \frac{y^2+y-6+2y-1}{y-2}\\ \to \frac{y^2+3y-7}{y-2}\end{array}$

Hence, the required answer is $\frac{y^2+3y-7}{y-2}$ .