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Chapter 6 Solutions
Single Variable Calculus: Early Transcendentals & Student Solutions Manual, Single Variable for Calculus: Early Transcendentals & MyLab Math -- Valuepack Access Card Package
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- Stan and Ollie work on the integral 2x(x2+2)dx. Stan lets u=x2+2 and proceeds to get 2x(x2+2)dx=u22+C=(x2+2)22+C Ollie multiplies out the function under the integral and gets (2x3+4x)dx=x42+2x2=ex3+C How can they both be right.?arrow_forwardUse substitution to find each indefinite integral. 6x2(2x3+7)32dxarrow_forwardYOUR TURN Suppose x are y are both functions of t and x3+2xy+y2=1. If x=1, y=2, and dxdt=6, then find dydt.arrow_forward
- Calculus For The Life SciencesCalculusISBN:9780321964038Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.Publisher:Pearson Addison Wesley,Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage
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