EBK FOUNDATIONS OF COLLEGE CHEMISTRY
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781118930144
Author: Willard
Publisher: JOHN WILEY+SONS INC.
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Chapter 7, Problem 27PE

(a)

Interpretation Introduction

Interpretation:

The percent composition of the compound sodium bromide has to be given.

(a)

Expert Solution
Check Mark

Answer to Problem 27PE

The percent composition of sodium is 22.33%.

The percent composition of bromine is 77.66%.

Explanation of Solution

Given,

The atomic mass of sodium atom =23g

The atomic mass of bromine atom =80g

The molecular weight of NaBr=23+80=103g

The percent composition for each element can be calculated as,

The percent composition of sodium =(23g103g)×100=22.33%

The percent composition of sodium is 22.33%.

The percent composition of bromine =(80g103)×100=77.66%

The percent composition of bromine is 77.66%.

(b)

Interpretation Introduction

Interpretation:

The percent composition of the compound KHCO3  has to be given.

(b)

Expert Solution
Check Mark

Answer to Problem 27PE

The percent composition of Potassium is 39.06%.

The percent composition of Hydrogen is 1.007%.

The percent composition of Carbon is 12.00%.

The percent composition of Oxygen is 47.95%.

Explanation of Solution

Given,

The atomic mass of potassium atom =39.10g

The atomic mass of hydrogen atom =1.008g

The atomic mass of oxygen atom =16g

The atomic mass of carbon atom =12.01g

The molecular weight of KHCO3=39.10g+1.008g+12g+3×16g

The molecular weight of KHCO3=100.1g

The percent composition for each element can be calculated as,

The percent composition of Potassium =(39.10g100.1g)×100=39.06%

The percent composition of Potassium is 39.06%.

The percent composition of Hydrogen =(1.008g100.1g)×100=1.007%

The percent composition of Hydrogen is 1.007%.

The percent composition of Carbon =(12.01g100.1g)×100=12.00%

The percent composition of Carbon is 12.00%.

The percent composition of Oxygen =(48.00g100.1g)×100=47.95%

The percent composition of Oxygen is 47.95%.

(c)

Interpretation Introduction

Interpretation:

The percent composition of the compound FeCl3 has to be given.

(c)

Expert Solution
Check Mark

Answer to Problem 27PE

The percent composition of Iron is 34.43%.

The percent composition of Chlorine is 65.56%.

Explanation of Solution

Given,

The atomic mass of iron atom =55.85g

The atomic mass of chlorine atom =35.45g

The molecular weight of FeCl3=55.85+3×35.45=162.2g

The percent composition for each element can be calculated as,

The percent composition of iron =(55.85g162.2g)×100=34.43%

The percent composition of iron is 34.43%.

The percent composition of Chlorine =(106.35g162.2g)×100=65.56%

The percent composition of Chlorine is 65.56%.

(d)

Interpretation Introduction

Interpretation:

The percent composition of the compound SiCl4 has to be given.

(d)

Expert Solution
Check Mark

Answer to Problem 27PE

The percent composition of Silicon is 16.53%.

The percent composition of Chlorine is 83.46%.

Explanation of Solution

Given,

The atomic mass of silicon atom =28.09g

The atomic mass of chlorine atom =35.45g

The molecular weight of SiCl4=28.09g+4×35.45g=169.9g

The percent composition for each element can be calculated as,

The percent composition of Silicon =(28.09g169.9g)×100=16.53%

The percent composition of Silicon is 16.53%.

The percent composition of Chlorine =(141.8g169.9g)×100=83.46%

The percent composition of Chlorine is 83.46%.

(e)

Interpretation Introduction

Interpretation:

The percent composition of the compound Al2(SO3)3 has to be given.

(e)

Expert Solution
Check Mark

Answer to Problem 27PE

The percent composition of aluminium is 15.77%.

The percent composition of sulfur is 28.12%.

The percent composition of oxygen is 56.11%.

Explanation of Solution

Given,

The atomic mass of aluminium atom =26.98g

The atomic mass of sulfur atom =32g

The atomic mass of oxygen atom =16g

The molecular weight of Al2(SO3)3=2×26.98+3×(32+3×16)=342.2g

The percent composition for each element can be calculated as,

The percent composition of aluminium =(53.96g342.2g)×100=15.77%

The percent composition of aluminium is 15.77%.

The percent composition of sulfur =(96.21g342.2g)×100=28.12%

The percent composition of sulfur is 28.12%.

The percent composition of oxygen =(192g342.2g)×100=56.11%

The percent composition of oxygen is 56.11%.

(f)

Interpretation Introduction

Interpretation:

The percent composition of the compound AgNO3 has to be given.

(f)

Expert Solution
Check Mark

Answer to Problem 27PE

The percent composition of Ag is 63.51%.

The percent composition of nitrogen is 8.246%.

The percent composition of oxygen is 28.25%.

Explanation of Solution

Given,

The atomic mass of Ag atom =107.9g

The atomic mass of nitrogen atom =14.01g

The atomic mass of oxygen atom =16g

The molecular weight of AgNO3=107.9+14.01+48=169.9g

The percent composition for each element can be calculated as,

The percent composition of Ag=(107.9g169.9g)×100=63.51%

The percent composition of Ag is 63.51%.

The percent composition of nitrogen =(14.01g169.9g)×100=8.246%

The percent composition of nitrogen is 8.246%.

The percent composition of oxygen =(48g169.9g)×100=28.25%

The percent composition of oxygen is 28.25%.

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Chapter 7 Solutions

EBK FOUNDATIONS OF COLLEGE CHEMISTRY

Ch. 7.4 - Prob. 7.11PCh. 7.5 - Prob. 7.12PCh. 7 - Prob. 1RQCh. 7 - Prob. 2RQCh. 7 - Prob. 3RQCh. 7 - Prob. 4RQCh. 7 - Prob. 5RQCh. 7 - Prob. 6RQCh. 7 - Prob. 7RQCh. 7 - Prob. 8RQCh. 7 - Prob. 9RQCh. 7 - Prob. 10RQCh. 7 - Prob. 11RQCh. 7 - Prob. 12RQCh. 7 - Prob. 13RQCh. 7 - Prob. 14RQCh. 7 - Prob. 15RQCh. 7 - Prob. 17RQCh. 7 - Prob. 18RQCh. 7 - Prob. 19RQCh. 7 - Prob. 1PECh. 7 - Prob. 2PECh. 7 - Prob. 3PECh. 7 - Prob. 4PECh. 7 - Prob. 5PECh. 7 - Prob. 6PECh. 7 - Prob. 7PECh. 7 - Prob. 8PECh. 7 - Prob. 9PECh. 7 - Prob. 10PECh. 7 - Prob. 11PECh. 7 - Prob. 12PECh. 7 - Prob. 13PECh. 7 - Prob. 14PECh. 7 - Prob. 15PECh. 7 - Prob. 16PECh. 7 - Prob. 17PECh. 7 - Prob. 18PECh. 7 - Prob. 19PECh. 7 - Prob. 20PECh. 7 - Prob. 21PECh. 7 - Prob. 22PECh. 7 - Prob. 25PECh. 7 - Prob. 26PECh. 7 - Prob. 27PECh. 7 - Prob. 28PECh. 7 - Prob. 29PECh. 7 - Prob. 30PECh. 7 - Prob. 31PECh. 7 - Prob. 32PECh. 7 - Prob. 33PECh. 7 - Prob. 34PECh. 7 - Prob. 35PECh. 7 - Prob. 36PECh. 7 - Prob. 37PECh. 7 - Prob. 38PECh. 7 - Prob. 39PECh. 7 - Prob. 40PECh. 7 - Prob. 41PECh. 7 - Prob. 42PECh. 7 - Prob. 43PECh. 7 - Prob. 44PECh. 7 - Prob. 45PECh. 7 - Prob. 46PECh. 7 - Prob. 47PECh. 7 - Prob. 48PECh. 7 - Prob. 49PECh. 7 - Prob. 50PECh. 7 - Prob. 51PECh. 7 - Prob. 52PECh. 7 - Prob. 53AECh. 7 - Prob. 54AECh. 7 - Prob. 55AECh. 7 - Prob. 56AECh. 7 - Prob. 57AECh. 7 - Prob. 58AECh. 7 - Prob. 59AECh. 7 - Prob. 60AECh. 7 - Prob. 61AECh. 7 - Prob. 62AECh. 7 - Prob. 63AECh. 7 - Prob. 64AECh. 7 - Prob. 65AECh. 7 - Prob. 66AECh. 7 - Prob. 67AECh. 7 - Prob. 68AECh. 7 - Prob. 69AECh. 7 - Prob. 70AECh. 7 - Prob. 71AECh. 7 - Prob. 72AECh. 7 - Prob. 73AECh. 7 - Prob. 74AECh. 7 - Prob. 75AECh. 7 - Prob. 76AECh. 7 - Prob. 77AECh. 7 - Prob. 78AECh. 7 - Prob. 79AECh. 7 - Prob. 80AECh. 7 - Prob. 81AECh. 7 - Prob. 82AECh. 7 - Prob. 83AECh. 7 - Prob. 84AECh. 7 - Prob. 88AECh. 7 - Prob. 89CECh. 7 - Prob. 90CE
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