21ST CENT AST EBK W/SW5&WKBK >BI<
21ST CENT AST EBK W/SW5&WKBK >BI<
6th Edition
ISBN: 9780393433050
Author: Kay
Publisher: NORTON
bartleby

Videos

Question
Book Icon
Chapter 7, Problem 32QP

(a)

To determine

The total mass of all the planets in the Solar System in terms of Earth masses.

(a)

Expert Solution
Check Mark

Answer to Problem 32QP

The total mass of all the planets in the Solar System in terms of Earth masses is 446.66MEarth_.

Explanation of Solution

Write the expression for the sum of the mass of the eight planets in our Solar System,

  Mtotal=MMercury+MVenus+MEarth+MMars+MJupiter+MSaturn+MUranus+MNeptune        (I)

Here, Mtotal is the mass of the eight planets in our Solar System, MMercury is the mass of the Mercury in terms of Earth masses, MVenus is the mass of the Venus in terms of Earth masses, MEarth is the mass of the Earth in terms of Earth masses, MMars is the mass of the Mars in terms of Earth masses, MJupiter is the mass of the Jupiter in terms of Earth masses, MSaturn is the mass of the Saturn in terms of Earth masses, MUranus is the mass of the Uranus in terms of Earth masses and MNeptune is the mass of the Neptune in terms of Earth masses.

Conclusion:

Substitute 0.055Earthmasses for MMercury, 0.815Earthmasses for MVenus, 1.00Earthmass for  MEarth, 0.107Earthmasses for MMars, 317.83Earthmasses for MJupiter, 95.16Earthmasses for MSaturn, 14.54Earthmasses for MUranus and 17.15Earthmasses for MNeptune in (I) to find Mtotal,

  Mtotal=(0.055+0.815+1.00+0.107+317.83+95.16+14.54+17.15)Earthmasses=446.66Earthmasses=446.66MEarth

Therefore, the total mass of all the planets in the Solar System in terms of Earth masses is 446.66MEarth_.

(b)

To determine

The fraction of that total planetary mass is Jupiter.

(b)

Expert Solution
Check Mark

Answer to Problem 32QP

The fraction of that total planetary mass is Jupiter is 71.16%_.

Explanation of Solution

Write the expression for the fraction of that total planetary mass is Jupiter.

    F=MJupiterMtotal×100%        (II)

Here, F is the fraction of that total planetary mass is Jupiter.

Conclusion:

Substitute 317.83MEarth for MJupiter and 446.66MEarth for Mtotal in above equation.

    F=317.83MJupiter446.66MEarth×100%=0.7116×100%=71.16%

Therefore, the fraction of that total planetary mass is Jupiter is 71.16%_.

(c)

To determine

The fraction of that total planetary mass is Earth.

(c)

Expert Solution
Check Mark

Answer to Problem 32QP

The fraction of that total planetary mass is Earth is 0.22%_.

Explanation of Solution

Write the expression for the fraction of that total planetary mass is Earth.

    FEarth=MEarthMtotal×100%        (II)

Here, FEarth is the fraction of that total planetary mass is Earth.

Conclusion:

Substitute 1.00MEarth for MJupiter and 446.66MEarth for Mtotal in above equation.

    F=1.00MJupiter446.66MEarth×100%=0.0022×100%=0.22%

Therefore, the fraction of that total planetary mass is Earth is 0.22%_.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Procedure  Table 11.1 presents Djup and Pday for the major Jovian satellites. First use these data and the equation above to calculate Jupiter’s mass in kilograms (kg). Enter your results in the table for each satellite. Next calculate the average Jupiter mass (Mjup, av) and enter the result in the table. Finally, calculate the percent difference (PD) using Mjup, av and the standard value for Jupiter’s mass (1.9 X 1027 kg). In the calculation of PD you can ignore 1027 because it will appear in both numerator and denominator. ________________________________________________________ Table 11.1 Calculated values for Jupiter’s Mass Satellite               Djup       Pday         Mjup Io                       2.95       1.77 Europa              4.69        3.55 Ganymede        7.50        7.15 Callisto           13.15       16.7 __________________________________________________________ Average Jupiter Mass =                              Percent Difference =
1. The diameter of the Sun is equal to 1.392*10^9 m, and the distance from the Sun to Saturnis equal to 9.5 AU. Suppose you want to build an exact scale model of the solar system,and you are using a volleyball with average diameter of 21 cm to represent the Sun. a) In your scale model, how far away would Saturn be from the Sun? Give your answer inmeters.b) The actual diameter of Saturn is 116,460 km. What would be Saturn’s diameter in yourscale model? Give your answer in centimeters.
Which of the following statements accurately describes our current understanding of the solar system? a. There are no metals in the solar system beyond Jupiter and its orbit. b. Terrestrial worlds are so small because their large atmospheres were stripped away in time by Jupiter. c. Jupiter and Saturn are made of strictly a combination of hydrogen and helium, and both objects lack a planetary core. d. Various ices can contribute to the mass of planetary cores if we are at a great enough distance from the sun.
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
The Solar System
Physics
ISBN:9781305804562
Author:Seeds
Publisher:Cengage
Text book image
Foundations of Astronomy (MindTap Course List)
Physics
ISBN:9781337399920
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning
Text book image
The Solar System
Physics
ISBN:9781337672252
Author:The Solar System
Publisher:Cengage
Text book image
Astronomy
Physics
ISBN:9781938168284
Author:Andrew Fraknoi; David Morrison; Sidney C. Wolff
Publisher:OpenStax
Text book image
Horizons: Exploring the Universe (MindTap Course ...
Physics
ISBN:9781305960961
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning
Text book image
Stars and Galaxies
Physics
ISBN:9781305120785
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning
Kepler's Three Laws Explained; Author: PhysicsHigh;https://www.youtube.com/watch?v=kyR6EO_RMKE;License: Standard YouTube License, CC-BY