ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM
7th Edition
ISBN: 9781319403959
Author: ATKINS
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Question
Chapter 7, Problem 7.1E
(a)
Interpretation Introduction
Interpretation:
The product formed with larger activation energy has to be given.
(b)
Interpretation Introduction
Interpretation:
The temperature (high or low) at which the kinetic control predominates has to be given.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Which of the following are always true of reactions that are
energetically favorable under standard conditions?
Choice 1 of 5:
Their standard free energy change is equal to zero.
Choice 2 of 5:
At equilibrium, the product of the concentration of the products is
greater than the product of the concentration of the reactants.
Choice 3 of 5:
They may be energetically UN-favorable under non-standard
conditions.
Choice 4 of 5:
They will proceed at a rapid rate even in the absence of a catalyst.
Choice 5 of 5:
Their change in enthalpy is smaller than the change in entropy.
Benzene is one of the compounds used as octane enhancers in unleaded gasoline. It is manufactured by the catalytic
conversion of acetylene to benzene:
3C2H2 (8) C6H6 (8).
Which value of Kwould make this reaction most useful commercially? K 0.01, K1, or K 10. Explain your answer.
Draw the energy diagram (energy verses course of reaction curve) for the reaction
4 PH3 + 2 H2 + 9 O2 <–> 2 P2O5 + 8 H2O(liq) + 25 kJ
Chapter 7 Solutions
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM
Ch. 7 - Prob. 7A.1ASTCh. 7 - Prob. 7A.1BSTCh. 7 - Prob. 7A.2ASTCh. 7 - Prob. 7A.2BSTCh. 7 - Prob. 7A.3ASTCh. 7 - Prob. 7A.3BSTCh. 7 - Prob. 7A.4ASTCh. 7 - Prob. 7A.4BSTCh. 7 - Prob. 7A.1ECh. 7 - Prob. 7A.2E
Ch. 7 - Prob. 7A.3ECh. 7 - Prob. 7A.4ECh. 7 - Prob. 7A.7ECh. 7 - Prob. 7A.8ECh. 7 - Prob. 7A.9ECh. 7 - Prob. 7A.10ECh. 7 - Prob. 7A.11ECh. 7 - Prob. 7A.12ECh. 7 - Prob. 7A.13ECh. 7 - Prob. 7A.14ECh. 7 - Prob. 7A.15ECh. 7 - Prob. 7A.16ECh. 7 - Prob. 7A.17ECh. 7 - Prob. 7A.18ECh. 7 - Prob. 7B.1ASTCh. 7 - Prob. 7B.1BSTCh. 7 - Prob. 7B.2ASTCh. 7 - Prob. 7B.2BSTCh. 7 - Prob. 7B.3ASTCh. 7 - Prob. 7B.3BSTCh. 7 - Prob. 7B.4ASTCh. 7 - Prob. 7B.4BSTCh. 7 - Prob. 7B.5ASTCh. 7 - Prob. 7B.5BSTCh. 7 - Prob. 7B.1ECh. 7 - Prob. 7B.2ECh. 7 - Prob. 7B.3ECh. 7 - Prob. 7B.4ECh. 7 - Prob. 7B.5ECh. 7 - Prob. 7B.6ECh. 7 - Prob. 7B.7ECh. 7 - Prob. 7B.8ECh. 7 - Prob. 7B.9ECh. 7 - Prob. 7B.10ECh. 7 - Prob. 7B.13ECh. 7 - Prob. 7B.14ECh. 7 - Prob. 7B.15ECh. 7 - Prob. 7B.16ECh. 7 - Prob. 7B.17ECh. 7 - Prob. 7B.18ECh. 7 - Prob. 7B.19ECh. 7 - Prob. 7B.20ECh. 7 - Prob. 7B.21ECh. 7 - Prob. 7B.22ECh. 7 - Prob. 7C.1ASTCh. 7 - Prob. 7C.1BSTCh. 7 - Prob. 7C.2ASTCh. 7 - Prob. 7C.2BSTCh. 7 - Prob. 7C.1ECh. 7 - Prob. 7C.2ECh. 7 - Prob. 7C.3ECh. 7 - Prob. 7C.4ECh. 7 - Prob. 7C.5ECh. 7 - Prob. 7C.6ECh. 7 - Prob. 7C.7ECh. 7 - Prob. 7C.8ECh. 7 - Prob. 7C.9ECh. 7 - Prob. 7C.11ECh. 7 - Prob. 7C.12ECh. 7 - Prob. 7D.1ASTCh. 7 - Prob. 7D.1BSTCh. 7 - Prob. 7D.2ASTCh. 7 - Prob. 7D.2BSTCh. 7 - Prob. 7D.1ECh. 7 - Prob. 7D.2ECh. 7 - Prob. 7D.3ECh. 7 - Prob. 7D.5ECh. 7 - Prob. 7D.6ECh. 7 - Prob. 7D.7ECh. 7 - Prob. 7D.8ECh. 7 - Prob. 7E.1ASTCh. 7 - Prob. 7E.1BSTCh. 7 - Prob. 7E.1ECh. 7 - Prob. 7E.2ECh. 7 - Prob. 7E.3ECh. 7 - Prob. 7E.4ECh. 7 - Prob. 7E.5ECh. 7 - Prob. 7E.6ECh. 7 - Prob. 7E.7ECh. 7 - Prob. 7E.8ECh. 7 - Prob. 7E.9ECh. 7 - Prob. 1OCECh. 7 - Prob. 7.1ECh. 7 - Prob. 7.2ECh. 7 - Prob. 7.3ECh. 7 - Prob. 7.4ECh. 7 - Prob. 7.5ECh. 7 - Prob. 7.6ECh. 7 - Prob. 7.7ECh. 7 - Prob. 7.9ECh. 7 - Prob. 7.11ECh. 7 - Prob. 7.14ECh. 7 - Prob. 7.15ECh. 7 - Prob. 7.17ECh. 7 - Prob. 7.19ECh. 7 - Prob. 7.20ECh. 7 - Prob. 7.23ECh. 7 - Prob. 7.25ECh. 7 - Prob. 7.26ECh. 7 - Prob. 7.29ECh. 7 - Prob. 7.30ECh. 7 - Prob. 7.31E
Knowledge Booster
Similar questions
- Trimethylamine, (CH3)3N, is a common reagent. It interacts readily with diborane gas, B₂H6. The latter dissociates to BH3 and this forms a complex with the amine, (CH3)3N→BH3. The reaction between trimethylamine and borane is shown. CH3 CH3 H CH3-N : + B-H CH3-N B-H CH3 H CH3 H Is the BH3 fragment a Lewis acid or a Lewis base? To decide this, answer the following questions: H a Which of the following is a definition of a Lewis acid? proton donor electron pair acceptor proton acceptor electron pair donorarrow_forwardDiscuss the conditions needed to have a reaction with gaseous reagents and gaseous products so that The value of Kp increases with increasing temperature The value of ΔG° increases with increasing temperature The value of k increases with increasing temperature The conversion of one of the reagents increases with increasing pressurearrow_forwardA kinetically-controlled process describes a reaction that. O generates the most stable product O generates the product whose formation requires the smallest energy of activation O generates the product requiring the fewest steps O generates the product formed at the slowest rate O generates the product favored at high temperaturesarrow_forward
- What is the reaction mechanism and what are the major products of this reaction?arrow_forwardGiven the following reactions 2NO → N2 + O2 ΔH = -180 kJ 2NO + O2 → 2NO2 ΔH = -112 kJarrow_forwardORGANIC CHEMISTRY - PERICYCLIC REACTIONS Draw the mechanism, explain the stereochemistry of the products, indicate the type of reaction.arrow_forward
- Determine the Kc of the following reaction: AB4(g) + B2C(g) ⇌ AC2(g) + B2(g) Kp = 21/62500arrow_forwardCalculate the free energy for the following reaction, given the following data: CO2 O2 AG° 394 kJ -> %3D 2 C,H6 15 O2 → 12 CO2 + 6 H20 AG° -6399 kJ %3D H2 2 O2 H2O AG°= -237 kJ -> 6 C 3 H2 CH6 AG°pxn +arrow_forward7.Predict the kinetic and the thermodynamic products for the following reaction. HCI kinetic thermodynamicarrow_forward
- The G° for conversion of “axial” fluorocyclohexane to “equatorial” fluorocyclohexane at 25 °C is -0.25 kcal>mol. Calculate the percentage of fluorocyclohexane molecules that have the fluoro substituent in an equatorial position at equilibrium.arrow_forwardFor each of the following processes predict the sign of AS for the reaction. In other words, will AS sys be positive (an increase in entropy) or negative (a decrease in entropy)? AS sys is expected to be positive (an increase in entropy) because one molecule is converted into two molecules. AS sys is expected to be negative (a decrease in entropy) because a cyclic compound is converted into acyclic compounds. O AS sys is expected to be positive (an increase in entropy) because an acyclic compound is converted into cyclic compounds. O AS sys is expected to be negative (a decrease in entropy) because two molecules are converted into one molecule.arrow_forward4. Ag catalyst ? H2C=CH2 + O2 250 °Carrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning