STEEL DESIGN W/ ACCESS
6th Edition
ISBN: 9781337761499
Author: Segui
Publisher: CENGAGE L
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Question
Chapter 7, Problem 7.6.4P
To determine
(a)
The single-shear and slip-critical design strength using LRFD and ASD method.
To determine
(b)
The conclusion from the table.
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a. Prepare a table showing values of Group A bolt shear strength and slip-critical strength for bolt diameters of 1⁄2 inch to 11⁄2 inches in increments of 1⁄8 inch. Assume Class A surfaces and that threads are in the plane of shear. Your table should have the following form:
b. What conclusions can you draw from this table?
Topic:Welded Connection - Civil Engineering -Steel Design
*Use latest NSCP/NSCP 2015 formula to solve this problem
*Please use hand written to solve this problem
A 150 mm x 90 mm x 12 mm angular section is welded to a gusset plate as shown. Area of the angle is 2736 sq.mm, allowable shear Fv is 150MPa, Allowable tensile stress Ft = 0.6Fy with Fy = 250 MPa.
Questions:
a) Design force P
b) Total required length of weld
using 12 mm fillet weld
c) Value of “b”
Topic:Bolted Steel Connection - Civil Engineering -Steel Design
*Use latest NSCP/NSCP 2015 formula to solve this problem
*Please use hand written to solve this problem
A 12.5 mm x150 mm plate is connected to
a gusset plate having a thickness of 9.5
mm.Diameter of bolt = 20 mm
Both the tension member and the gusset
plate are of A 36 steel. Fy = 248 MPa, FU = 400 MPa.
Shear stress of bolt Fnv = 300MPa.
Questions:
a.Determine the shear strength of the connection.
b.Determine the bearing strength of the connection.
c. Determine the block shear strength of the connection.
Chapter 7 Solutions
STEEL DESIGN W/ ACCESS
Ch. 7 - Prob. 7.3.1PCh. 7 - Prob. 7.3.2PCh. 7 - Prob. 7.4.1PCh. 7 - Prob. 7.4.2PCh. 7 - Prob. 7.4.3PCh. 7 - Prob. 7.4.4PCh. 7 - Prob. 7.4.5PCh. 7 - Prob. 7.4.6PCh. 7 - Prob. 7.6.1PCh. 7 - Prob. 7.6.2P
Ch. 7 - Prob. 7.6.3PCh. 7 - Prob. 7.6.4PCh. 7 - Prob. 7.6.5PCh. 7 - Prob. 7.6.6PCh. 7 - Prob. 7.7.1PCh. 7 - Prob. 7.7.2PCh. 7 - Prob. 7.7.3PCh. 7 - Prob. 7.8.1PCh. 7 - Determine the adequacy of the hanger connection in...Ch. 7 - Prob. 7.9.1PCh. 7 - Prob. 7.9.2PCh. 7 - Prob. 7.9.3PCh. 7 - Prob. 7.9.4PCh. 7 - Prob. 7.9.5PCh. 7 - Prob. 7.11.1PCh. 7 - Prob. 7.11.2PCh. 7 - Prob. 7.11.3PCh. 7 - Prob. 7.11.4PCh. 7 - Prob. 7.11.5PCh. 7 - Prob. 7.11.6PCh. 7 - Prob. 7.11.7PCh. 7 - Prob. 7.11.8PCh. 7 - Prob. 7.11.9PCh. 7 - Prob. 7.11.10P
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- The Aluminum plates below are connected by two 3/4" diameter bolts. What is the shear stress in the bolts given the load applied?arrow_forwardThe plate shown is 8 in wide and 1/2 in thick. The bolts are 7/8 in. The smallest net area (An) of this bolted plate is equal to:arrow_forwardQuestion j=169" R=2.1" ;f 4- 2.81 d $ 100 08 96 07 h £=0.5" * # >P d=7.3" Material is ASTM A36. Plate is fixed 511 by 4 screws of {"$. using the information provided, calculate the ultimate stress (factored by LRFD) for shear fracture and tensile rupture of block pattern passing through points the shear 3-10-9-4..arrow_forward
- Two plates are held together by 3, 23 mm diameter bolts. If a 11 kN load is applied to the plates in shear, what is the shear stress in the bolts in MPa? Type your answer...arrow_forward2. A steel plate is 360 mm wide and 20 mm thick with four bolts hole into the place as shown in the figure. Compute the following: a. Critical net area required by the NSCP specs. b. Max. critical net area required by the NSP specs. Note that, Max. net area is 85% of the critical net area c. Capacity of the joint if the allowable tensile stress is 0.75Fy. Use A36 steel Fy=248 MPa 90m²m 90 mm 90mm 45 45mm In my comin P Scanned with CamScanner CSarrow_forwardA bolted lap joint is shown in the figure below. The bolts are 19mm in diameter. Effective diameter of the holes is 23mm. The plates are 12 mm thick, x1 = 33 mm, x2 = 76 mm, x3 = 50 mm. Yield strength of plate, Fy = 248 MPa Ultimate tensile strength of plate, Fu = 400 MPa Using allowable strength design: 1. Find the safe load “P” based on gross area yielding. 2. Find the safe load “P” based on net area rupture. 3. Find the safe load “P” based on block sheararrow_forward
- Topic:Welded Connection - Civil Engineering -Steel Design *Use latest NSCP/NSCP 2015 formula to solve this problem *Use attached formula picture for block shear *Please use hand written to solve this problem A channel is used as a tension member with the web of the channel welded to a 9.5 mm thick gusset plate as shown in the figure. The tension member is subjected to the following axial loads. Use LRFD Service dead load = 200 kN Wind load = 276 kN Service live load = 260 kN For channel: Fy = 345 MPa For gusset plate: Fy = 248 MPa Fu = 400 MPa Size of E 70 electrodes = 4 mm Ultimate tensile strength of E 70 electrodes = 480; Fw = 0.6(480) Questions : a) Determine the design factored tensile force. b) Determine the length of longitudinal welds "L". c) Determine the block shear strength of the gusset plate.arrow_forwardDifferentiate how to test welded from tension joints.arrow_forwardShow 5 failures. Show step by step solution. Steel Type: Cross section flat bar PL 12.7 x 165 with an area of 2095.5 mm2 Textbook reference Handbook of steel construction.arrow_forward
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