For Exercises 43–56, write the standard form of an equation of an ellipse subject to the given conditions. (See Example 5)
Vertices:
Foci:
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- Exercises 45–48 give equations for parabolas and tell how many units up or down and to the right or left each parabola is to be shifted. Find an equation for the new parabola, and find the new vertex, focus, and directrix.arrow_forwardFor Exercises 43–48, the equation represents a conic section (nondegenerative case). a. Identify the type of conic section. (See Example 6) b. Graph the equation on a graphing utility. 43. 4x – 4xy + 5y – 20 = 0 44. 6x + 4V3xy + 2y - 18x + 18V3y – 72 = 0 45. 2x – 6xy + 3y² - 4x + 12y – 9 = 0 46. 5x – 3xy + 2y – 6 = 0 47. 4x + 8xy + 4y – 2x – 5y – 2 = 0 48. 4x? + 8V3xy + 3y + 2x – 12y – 6 = 0arrow_forwardIn Exercises 3–16, find the coordinates of the vertices and foci of the given ellipses. Sketch each curve.arrow_forward
- Exercises 49–52 give equations for ellipses and tell how many units up or down and to the right or left each ellipse is to be shifted. Find an equation for the new ellipse, and find the new foci, vertices, and center.arrow_forwardExercises 27–34 give equations for hyperbolas. Put each equation instandard form and find the hyperbola’s asymptotes. Then sketch thehyperbola. Include the asymptotes and foci in your sketch.27. x2 - y2 = 1 28. 9x2 - 16y2 = 14429. y2 - x2 = 8 30. y2 - x2 = 431. 8x2 - 2y2 = 16 32. y2 - 3x2 = 333. 8y2 - 2x2 = 16 34. 64x2 - 36y2 = 2304arrow_forwardFor Exercises 13–22, a. Identify the center. b. Identify the vertices. c. Identify the foci. d. Write equations for the asymptotes. e. Graph the hyperbola. (See Examples 1-2) 13. 16 y? = 1 25 14. 25 y? = 1 36 y² 15. 4 = 1 36 y? 16. 9. = 1 49 17. 25y - 81x = 2025 18. 49y? 16x = 784 19. - 5x? + 7y² = -35 20. –7x + 1ly = -77 21. 25 16y 1 4x? 22. 81 16y? 1 49 225arrow_forward
- Exercises 45–48 give equations for parabolas and tell how many units up or down and to the right or left each parabola is to be shifted. Find an equation for the new parabola, and find the new vertex, focus, and directrix. 45. y2 = 4x, 46. x2 = 8y, right 1, down 7 47. x2 = 6y, left 2, down 3 48. y2 = -12x, right 4, up 3 left 3, down 2arrow_forwardIn Exercises 17–30, find the equations of the parabolas satisfying the given conditions. The vertex of each is at the origin.arrow_forwardIn Exercises 1–8, find the eccentricity of the ellipse. Then find and graph the ellipse’s foci and directrices.arrow_forward
- For Exercises 79–82, write the standard form of an equation of the ellipse subject to the following conditions. 79. Center: (0, 0); Eccentricity: ; Major axis vertical of length 34 units 80. Center: (0, 0); Eccentricity: ; Major axis vertical of length 82 units 81. Foci: (0, – 1) and (8, – 1); Eccentricity: 82. Foci: (0, – 1) and (-6, –1); Eccentricity:arrow_forwardExercises 53–54 give equations for hyperbolas and tell how many units up or down and to the right or left each hyperbola is to be shifted. Find an equation for the new hyperbola, and find the new center, foci, vertices, and asymptotes. 53. x2/4-y2/5=1 right 2, up 2 54. x2/16-y2/9=1 left 2, down 1arrow_forwardFor Exercises 67–70, identify the equation as representing an ellipse or a hyperbola, and match the equation with the graph. (x – 5)² 67. (y + 2)² = 1 (x – 5)? 68. (y + 2)? = 1 49 36 36 49 (x - 5)? 69. (y + 2)² = 1 (y + 2)² = 1 (x - 5)? 49 36 70. 49 36 А. В. С. D. 15 12 41 6 -6-4-2 4 6 8 10 12 14 4 6 8 10 12 14 -6 -4 2. 4 6 8 10l 12 14 -6 1k 15 18 21 -6arrow_forward
- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage