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The inverse forms of the results in Problem 49 in Exercises 7.1 are
In Problems 45 and 46 use the Laplace transform and these inverses to solve the given initial-value problem.
y″ − 2y′ + 5y = 0, y(0) = 1, y′(0) = 3
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Chapter 7 Solutions
FIRST CRSE.IN DIFF.EQUAT..-ACCESS
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