(a)
To write: a system of linear equations in which one equation represents the amount of final mixture required and the other represents the percent of acid in the final mixture.
(a)
Answer to Problem 80E
The system of linear equations in which one equation represents the amount of final mixture required and the other represents the percent of acid in the final mixture are:
Explanation of Solution
Given information:
Thirty liters of an
Let
Calculation:
The equation represents the amount of final mixture required is:
And
The equation represents the percent of acid in the final mixture is:
Therefore, the system of linear equations can be written as:
(b)
To plot: a system of linear equations on graph using graphing utility.
(b)
Answer to Problem 80E
The solution of system of linear equations using graphing utility is:
Explanation of Solution
Given information:
Thirty liters of an
Let
Calculation:
The system of linear equations in which one equation represents the amount of final mixture required and the other represents the percent of acid in the final mixture are:
Plot the given system of linear equations using graphing utility:
Therefore,the solution of system of linear equations using graphing utility is:
(c)
To state:what will happen to
(c)
Answer to Problem 80E
When the amount of
Explanation of Solution
Given information:
Thirty liters of an
Let
Calculation:
The equation represents the percent of acid in the final mixture is:
Analyze the above equation by table method, put different values of
24 | |
23 | |
8 |
From the table, it is clear that when the amount of
(d)
To solve: a system of linear equations and determine the amount of each solution to obtained the specified concentration of the final mixture.
(d)
Answer to Problem 80E
Explanation of Solution
Given information:
Thirty liters of an
Let
Calculation:
Since, the system of linear equations can be written as:
Solve equation (1) and (2) by elimination method:
Calculate the value of
Therefore,
Chapter 7 Solutions
Precalculus with Limits: A Graphing Approach
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