EBK PRODUCTION AND OPERATIONS ANALYSIS
7th Edition
ISBN: 8220102480681
Author: Olsen
Publisher: WAVELAND
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Question
Chapter 7.3, Problem 12P
a)
Summary Introduction
Interpretation: the probability of no customers in two mins.
Concept introduction:Poisson arrivals are a reasonably good assumption for unscheduled systems. Further if there is a mix of many different types of jobs the exponential distribution can be realistic for service times. Otherwise it tends to be too variable of a distribution.
b)
Summary Introduction
Interpretation: probability of exactly two customers in a minute.
Concept introduction:Poisson arrivals are a reasonably good assumption for unscheduled systems. Further if there is a mix of many different types of jobs the exponential distribution can be realistic for service times. Otherwise it tends to be too variable of a distribution
c)
Summary Introduction
Interpretation:probability of exactly five customers in threeminutes
Concept introduction:Poisson arrivals are a reasonably good assumption for unscheduled systems. Further if there is a mix of many different types of jobs the exponential distribution can be realistic for service times. Otherwise it tends to be too variable of a distribution
d)
Summary Introduction
Interpretation:probability of no more than two customers in fiveminutes
Concept introduction:Poisson arrivals are a reasonably good assumption for unscheduled systems. Further if there is a mix of many different types of jobs the exponential distribution can be realistic for service times. Otherwise it tends to be too variable of a distribution
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The following data has been collected on the number of customers seen to arriveto a museum in a succession of 5-minute intervals: 5, 1, 3, 7, 5, 5, 6, 7, 5, 7, 4, 8, 1,5, 2, 3, and 5. Estimate the squared coefficient of variation of the arrival process. Ifthis data was known to come from a Poisson process, what would be your estimateof l, the rate of customer arrivals?
What is the answer in this number 2?
Customer arrive at one-window drive in bank according to Poisson distribution with mean 10 per hour. Service time per customer is exponential with mean 5 minutes. There are three spaces in front of the window, including the car being served. Other arriving cars can wait outside these three spaces.
A. What is the probability that an arriving customer can enter one of these three spaces?
B. What is the probability that an arriving customer is expected to wait outside the three spaces.
C.How long is an arriving customer expected to wait before starting service.
Chapter 7 Solutions
EBK PRODUCTION AND OPERATIONS ANALYSIS
Ch. 7.1 - Prob. 1PCh. 7.1 - Prob. 2PCh. 7.1 - Prob. 3PCh. 7.1 - Prob. 4PCh. 7.1 - Prob. 5PCh. 7.1 - Prob. 6PCh. 7.1 - Prob. 7PCh. 7.2 - Prob. 8PCh. 7.2 - Prob. 9PCh. 7.2 - Prob. 10P
Ch. 7.3 - Prob. 11PCh. 7.3 - Prob. 12PCh. 7.3 - Prob. 13PCh. 7.3 - Prob. 14PCh. 7.3 - Prob. 15PCh. 7.3 - Prob. 16PCh. 7.3 - Prob. 18PCh. 7.4 - Prob. 19PCh. 7.4 - Prob. 21PCh. 7.4 - Prob. 22PCh. 7.4 - Prob. 23PCh. 7.5 - Prob. 24PCh. 7.5 - Prob. 25PCh. 7.5 - Prob. 26PCh. 7.5 - Prob. 27PCh. 7.8 - Prob. 28PCh. 7.8 - Prob. 29PCh. 7.8 - Prob. 30PCh. 7.8 - Prob. 32PCh. 7.8 - Prob. 34PCh. 7.8 - Prob. 35PCh. 7.8 - Prob. 36PCh. 7 - Prob. 38APCh. 7 - Prob. 39APCh. 7 - Prob. 40APCh. 7 - Prob. 41APCh. 7 - Prob. 42APCh. 7 - Prob. 43APCh. 7 - Prob. 44APCh. 7 - Prob. 45APCh. 7 - Prob. 46AP
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