Chapter 7.3, Problem 61E

To determine

To write: the form of the partial function decomposition of the rational expression and check result algebraically by combining fractions and check result graphically by using a graphing utility to graph the rational expression and the partial fraction in the same viewing window.

Answer to Problem 61E

  $\frac{2x-3}{{(x-1)}^2}=\frac{2}{(x-1)}-\frac{-1}{{(x-1)}^2}$ .

Explanation of Solution

Given information: Given rational function is $\frac{2x-3}{{(x-1)}^2}.$

Calculation:

Given function is,

  $\frac{2x-3}{{(x-1)}^2}=\frac{2x-3}{{(x-1)}^2}.$ Factor out denominator.

Divide a different variable by each of these components.

  $\begin{array}{l}\frac{2x-3}{{(x-1)}^2}.=\frac{A}{(x-1)}+\frac{B}{{(x-1)}^2}.\\ \frac{2x-3}{{(x-1)}^2}=\frac{A(x-1)+B}{{(x-1)}^2}.\\ \frac{2x-3}{{(x-1)}^2}=\frac{Ax-A+B}{{(x-1)}^2}.\end{array}$

Since both sides are in standard form, can equate the coefficients to come up with a system of equations.

  $\begin{array}{c}A=\mathrm{2...........}(1)\\ -A+B=-3.\\ B=-3+A=-3+2=-1.\\ B=-\mathrm{1............}(2)\\ .\end{array}$

Recombine to check algebraically.

  $\begin{array}{l}\frac{2}{(x-1)}+\frac{-1}{{(x-1)}^2}=\frac{2x-2-1}{{(x-1)}^2}=\frac{2x-3}{{(x-1)}^2}.\\ \frac{2x-3}{{(x-1)}^2}=\frac{2}{(x-1)}-\frac{-1}{{(x-1)}^2}.\end{array}$

Graph of the original function and the partial fraction decomposition is given below.

  

The graph of the original expression and the partial fraction are shown above. They all share the same asymptote.