The distance d from P 1 = ( 3 , − 4 ) and P 2 = ( − 2 , 1 ) .

Question

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Answer 1

Question

Chapter 7.4, Problem 1AYP

To determine

To find: The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ .

Expert Solution & Answer

Answer to Problem 1AYP

Solution:

The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ is $5 \sqrt{2}$ .

Explanation of Solution

Given:

$P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$

Calculation:

Distance between these two points $d = \sqrt{{(3 - (- 2))}^{2} + {(- 4 - 1)}^{2}} = \sqrt{50} = 5 \sqrt{2}$ .

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Answer 2

Question

Chapter 7.4, Problem 1AYP

To determine

To find: The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ .

Expert Solution & Answer

Answer to Problem 1AYP

Solution:

The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ is $5 \sqrt{2}$ .

Explanation of Solution

Given:

$P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$

Calculation:

Distance between these two points $d = \sqrt{{(3 - (- 2))}^{2} + {(- 4 - 1)}^{2}} = \sqrt{50} = 5 \sqrt{2}$ .

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Answer 3

Question

Chapter 7.4, Problem 1AYP

To determine

To find: The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ .

Expert Solution & Answer

Answer to Problem 1AYP

Solution:

The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ is $5 \sqrt{2}$ .

Explanation of Solution

Given:

$P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$

Calculation:

Distance between these two points $d = \sqrt{{(3 - (- 2))}^{2} + {(- 4 - 1)}^{2}} = \sqrt{50} = 5 \sqrt{2}$ .

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Answer 4

Question

Chapter 7.4, Problem 1AYP

To determine

To find: The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ .

Expert Solution & Answer

Answer to Problem 1AYP

Solution:

The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ is $5 \sqrt{2}$ .

Explanation of Solution

Given:

$P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$

Calculation:

Distance between these two points $d = \sqrt{{(3 - (- 2))}^{2} + {(- 4 - 1)}^{2}} = \sqrt{50} = 5 \sqrt{2}$ .

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Answer 5

Chapter 7.4, Problem 1AYP

To determine

To find: The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ .

Expert Solution & Answer

Answer to Problem 1AYP

Solution:

The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ is $5 \sqrt{2}$ .

Explanation of Solution

Given:

$P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$

Calculation:

Distance between these two points $d = \sqrt{{(3 - (- 2))}^{2} + {(- 4 - 1)}^{2}} = \sqrt{50} = 5 \sqrt{2}$ .

Answer 6

Chapter 7.4, Problem 1AYP

To determine

To find: The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ .

Expert Solution & Answer

Answer to Problem 1AYP

Solution:

The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ is $5 \sqrt{2}$ .

Explanation of Solution

Given:

$P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$

Calculation:

Distance between these two points $d = \sqrt{{(3 - (- 2))}^{2} + {(- 4 - 1)}^{2}} = \sqrt{50} = 5 \sqrt{2}$ .

Answer 7

Chapter 7.4, Problem 1AYP

To determine

To find: The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ .

Answer 8

Expert Solution & Answer

Answer to Problem 1AYP

Solution:

The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ is $5 \sqrt{2}$ .

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given:

$P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$

Calculation:

Distance between these two points $d = \sqrt{{(3 - (- 2))}^{2} + {(- 4 - 1)}^{2}} = \sqrt{50} = 5 \sqrt{2}$ .

Answer 12

Ch. 7.2 - Prob. 1AYP Ch. 7.2 - Prob. 2AYP Ch. 7.2 - Prob. 3AYP Ch. 7.2 - Prob. 4AYP Ch. 7.2 - Prob. 5AYP Ch. 7.2 - Prob. 6CV Ch. 7.2 - Prob. 7CV Ch. 7.2 - Prob. 8CV Ch. 7.2 - Prob. 9CV Ch. 7.2 - Prob. 10CV

The distance d from P 1 = ( 3 , − 4 ) and P 2 = ( − 2 , 1 ) .

To find: The distance d from P 1 = ( 3, −4 ) and P 2 = ( −2, 1 ) .

Answer to Problem 1AYP

Explanation of Solution

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Chapter 7 Solutions

To find: The distance $d$ from $P_{1} = (3, - 4)$ and $P_{2} = (- 2, 1)$ .