Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN: 9780547587776
Author: HOLT MCDOUGAL
Publisher: HOLT MCDOUGAL
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Question
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Chapter 7.5, Problem 25E

i.

To determine

To calculate the percentof change in number of pairs of footwear from the year 1996 to 2000 .

i.

Expert Solution
Check Mark

Answer to Problem 25E

The percent of change in number of pairs of footwear from the year 1996 to 2000 is

about 50.8% .

Explanation of Solution

Given information:

Consider, the graph provided in the question,

  Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 7.5, Problem 25E , additional homework tip  1

The pairs of footwear manufactured in the year 1996 is 196.0 millions .

The pairs of footwear manufactured in the year 1997 is 190.1 millions .

The pairs of footwear manufactured in the year 1998 is 163.2 millions .

The pairs of footwear manufactured in the year 1999 is 120.9 millions .

The pairs of footwear manufactured in the year 2000 is 96.5 millions .

Formula used:

  Percent of change, p%=Amount of increase or decreaseOriginal amount

Calculation:

The decrease in number of pairs of footwear from the year 1996 to 2000 is:

  =196.096.5=99.5 millions

Therefore,

Percent of change in number of pairs of footwear is:

  p%=99.5196.0                              [Substitute]p%0.5077=50.8%              [Divide. Then write decimal as a percent]

Conclusion:

Hence,

The percent of change in number of pairs of footwear from the year 1996 to 2000

is about 50.8% .

ii.

To determine

To compare in which year did the number of pairs of footwear decreases the most from previous year and what was the approximate percent of change.

ii.

Expert Solution
Check Mark

Answer to Problem 25E

The decrease in number of pairs of footwear in the year 1999 from the previous year is 42.3 millions which is maximum as compared to others and

The percent of change is about 25.9% .

Explanation of Solution

Given information:

Consider, the graph provided in the question,

  Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 7.5, Problem 25E , additional homework tip  2

The pairs of footwear manufactured in the year 1996 is 196.0 millions .

The pairs of footwear manufactured in the year 1997 is 190.1 millions .

The pairs of footwear manufactured in the year 1998 is 163.2 millions .

The pairs of footwear manufactured in the year 1999 is 120.9 millions .

The pairs of footwear manufactured in the year 2000 is 96.5 millions .

Formula used:

  Percent of change, p%=Amount of increase or decreaseOriginal amount

Calculation:

The decrease in number of pairs of footwear in 1997 from the year 1996 is:

  =196.0190.1=5.9 millions

The decrease in number of pairs of footwear in 1998 from the year 1997 is:

  =190.1163.2=26.9 millions

The decrease in number of pairs of footwear in 1999 from the year 1998 is:

  =163.2120.9=42.3 millions

The decrease in number of pairs of footwear in 2000 from the year 1999 is:

  =120.996.5=24.4 millions

The decrease in number of pairs of footwear in 1999 from the previous year is 42.3 millions which is the most as compared to others.

Therefore,

Percent of change in number of pairs of footwear is:

  p%=42.3163.2                                [Substitute]p%0.2591=25.9%                 [Divide. Then write decimal as a percent]

Conclusion:

Hence,

The decrease in number of pairs of footwear in the year 1999 from the previous year is 42.3 millions which is maximum as compared to others and the percent of change is about 25.9% .

iii.

To determine

To conclude and explain from the graph that the footwear manufactures are making less money.

iii.

Expert Solution
Check Mark

Answer to Problem 25E

No, it cannot be concluded from the graph that manufacturers are making less money from 1996 to 2000 since the graph does not indicate the amount that is made per pair of shoes. Also, it is possible that the decrease might be because the manufacturers are having the shoes made for them outside of the United States.

Explanation of Solution

Given information:

Consider, the information provided in the expression,

  Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 7.5, Problem 25E , additional homework tip  3

The pairs of footwear manufactured in the year 1996 is 196.0 millions .

The pairs of footwear manufactured in the year 1997 is 190.1 millions .

The pairs of footwear manufactured in the year 1998 is 163.2 millions .

The pairs of footwear manufactured in the year 1999 is 120.9 millions .

The pairs of footwear manufactured in the year 2000 is 96.5 millions .

Conclusion and Explanation:

No, it cannot be concluded from the graph that manufacturers are making less money from 1996 to 2000 since the graph does not indicate the amount that is made per pair of shoes. Also, it is possible that the decrease might be because the manufacturers are having the shoes made for them outside of the United States.

Chapter 7 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 7.1 - Prob. 2ECh. 7.1 - Prob. 3ECh. 7.1 - Prob. 4ECh. 7.1 - Prob. 5ECh. 7.1 - Prob. 6ECh. 7.1 - Prob. 7ECh. 7.1 - Prob. 8ECh. 7.1 - Prob. 9ECh. 7.1 - Prob. 10ECh. 7.1 - Prob. 11ECh. 7.1 - Prob. 12ECh. 7.1 - Prob. 13ECh. 7.1 - Prob. 14ECh. 7.1 - Prob. 15ECh. 7.1 - Prob. 16ECh. 7.1 - Prob. 17ECh. 7.1 - Prob. 18ECh. 7.1 - Prob. 19ECh. 7.1 - Prob. 20ECh. 7.1 - Prob. 21ECh. 7.1 - Prob. 22ECh. 7.1 - Prob. 23ECh. 7.1 - Prob. 24ECh. 7.1 - Prob. 25ECh. 7.1 - Prob. 26ECh. 7.1 - Prob. 27ECh. 7.1 - Prob. 28ECh. 7.1 - Prob. 29ECh. 7.1 - Prob. 30ECh. 7.1 - Prob. 31ECh. 7.1 - Prob. 32ECh. 7.1 - Prob. 33ECh. 7.1 - Prob. 34ECh. 7.1 - Prob. 35ECh. 7.1 - Prob. 36ECh. 7.1 - Prob. 37ECh. 7.1 - Prob. 38ECh. 7.1 - Prob. 39ECh. 7.1 - Prob. 40ECh. 7.1 - Prob. 41ECh. 7.1 - Prob. 42ECh. 7.1 - Prob. 43ECh. 7.1 - Prob. 44ECh. 7.1 - Prob. 45ECh. 7.1 - Prob. 46ECh. 7.1 - Prob. 47ECh. 7.1 - Prob. 48ECh. 7.1 - Prob. 49ECh. 7.1 - Prob. 50ECh. 7.1 - Prob. 51ECh. 7.1 - Prob. 52ECh. 7.1 - Prob. 53ECh. 7.1 - Prob. 54ECh. 7.1 - 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Prob. 28ECh. 7.3 - Prob. 29ECh. 7.3 - Prob. 30ECh. 7.3 - Prob. 31ECh. 7.3 - Prob. 32ECh. 7.3 - Prob. 33ECh. 7.3 - Prob. 34ECh. 7.3 - Prob. 35ECh. 7.3 - Prob. 36ECh. 7.3 - Prob. 37ECh. 7.3 - Prob. 38ECh. 7.3 - Prob. 39ECh. 7.3 - Prob. 40ECh. 7.3 - Prob. 41ECh. 7.3 - Prob. 42ECh. 7.3 - Prob. 43ECh. 7.3 - Prob. 44ECh. 7.3 - Prob. 45ECh. 7.3 - Prob. 46ECh. 7.3 - Prob. 47ECh. 7.3 - Prob. 48ECh. 7.3 - Prob. 49ECh. 7.3 - Prob. 50ECh. 7.3 - Prob. 51ECh. 7.3 - Prob. 52ECh. 7.3 - Prob. 53ECh. 7.3 - Prob. 54ECh. 7.3 - Prob. 55ECh. 7.3 - Prob. 56ECh. 7.3 - Prob. 57ECh. 7.3 - Prob. 58ECh. 7.3 - Prob. 59ECh. 7.3 - Prob. 60ECh. 7.3 - Prob. 61ECh. 7.3 - Prob. 62ECh. 7.3 - Prob. 63ECh. 7.3 - Prob. 64ECh. 7.3 - Prob. 65ECh. 7.3 - Prob. 66ECh. 7.3 - Prob. 67ECh. 7.3 - Prob. 68ECh. 7.3 - Prob. 69ECh. 7.3 - Prob. 70ECh. 7.3 - Prob. 71ECh. 7.4 - Prob. 1CCh. 7.4 - Prob. 2CCh. 7.4 - Prob. 3CCh. 7.4 - Prob. 4CCh. 7.4 - Prob. 5CCh. 7.4 - Prob. 1ECh. 7.4 - Prob. 2ECh. 7.4 - Prob. 3ECh. 7.4 - Prob. 4ECh. 7.4 - Prob. 5ECh. 7.4 - 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Prob. 9ECh. 7.5 - Prob. 10ECh. 7.5 - Prob. 11ECh. 7.5 - Prob. 12ECh. 7.5 - Prob. 13ECh. 7.5 - Prob. 14ECh. 7.5 - Prob. 15ECh. 7.5 - Prob. 16ECh. 7.5 - Prob. 17ECh. 7.5 - Prob. 18ECh. 7.5 - Prob. 19ECh. 7.5 - Prob. 20ECh. 7.5 - Prob. 21ECh. 7.5 - Prob. 22ECh. 7.5 - Prob. 23ECh. 7.5 - Prob. 24ECh. 7.5 - Prob. 25ECh. 7.5 - Prob. 26ECh. 7.5 - Prob. 27ECh. 7.5 - Prob. 28ECh. 7.5 - Prob. 29ECh. 7.5 - Prob. 30ECh. 7.5 - Prob. 31ECh. 7.5 - Prob. 32ECh. 7.5 - Prob. 33ECh. 7.5 - Prob. 34ECh. 7.5 - Prob. 35ECh. 7.5 - Prob. 36ECh. 7.5 - Prob. 37ECh. 7.5 - Prob. 38ECh. 7.5 - Prob. 39ECh. 7.5 - Prob. 40ECh. 7.5 - Prob. 41ECh. 7.6 - Prob. 1CCh. 7.6 - Prob. 2CCh. 7.6 - Prob. 3CCh. 7.6 - Prob. 4CCh. 7.6 - Prob. 1ECh. 7.6 - Prob. 2ECh. 7.6 - Prob. 3ECh. 7.6 - Prob. 4ECh. 7.6 - Prob. 5ECh. 7.6 - Prob. 6ECh. 7.6 - Prob. 7ECh. 7.6 - Prob. 8ECh. 7.6 - Prob. 9ECh. 7.6 - Prob. 10ECh. 7.6 - Prob. 11ECh. 7.6 - Prob. 12ECh. 7.6 - Prob. 13ECh. 7.6 - Prob. 14ECh. 7.6 - Prob. 15ECh. 7.6 - Prob. 16ECh. 7.6 - Prob. 17ECh. 7.6 - 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Prob. 28ECh. 7.7 - Prob. 29ECh. 7.7 - Prob. 30ECh. 7.7 - Prob. 31ECh. 7.7 - Prob. 32ECh. 7.7 - Prob. 33ECh. 7.7 - Prob. 34ECh. 7.7 - Prob. 35ECh. 7.7 - Prob. 36ECh. 7.7 - Prob. 37ECh. 7 - Prob. 1PSQCh. 7 - Prob. 2PSQCh. 7 - Prob. 3PSQCh. 7 - Prob. 4PSQCh. 7 - Prob. 5PSQCh. 7 - Prob. 6PSQCh. 7 - Prob. 7PSQCh. 7 - Prob. 8PSQCh. 7 - Prob. 9PSQCh. 7 - Prob. 1MCQCh. 7 - Prob. 2MCQCh. 7 - Prob. 3MCQCh. 7 - Prob. 4MCQCh. 7 - Prob. 5MCQCh. 7 - Prob. 6MCQCh. 7 - Prob. 7MCQCh. 7 - Prob. 8MCQCh. 7 - Prob. 9MCQCh. 7 - Prob. 10MCQCh. 7 - Prob. 11MCQCh. 7 - Prob. 12MCQCh. 7 - Prob. 13MCQCh. 7 - Prob. 14MCQCh. 7 - Prob. 15MCQCh. 7 - Prob. 16MCQCh. 7 - Prob. 17MCQCh. 7 - Prob. 18MCQCh. 7 - Prob. 19MCQCh. 7 - Prob. 20MCQCh. 7 - Prob. 21MCQCh. 7 - Prob. 22MCQCh. 7 - Prob. 1CRCh. 7 - Prob. 2CRCh. 7 - Prob. 3CRCh. 7 - Prob. 4CRCh. 7 - Prob. 5CRCh. 7 - Prob. 6CRCh. 7 - Prob. 7CRCh. 7 - Prob. 8CRCh. 7 - Prob. 9CRCh. 7 - Prob. 10CRCh. 7 - Prob. 11CRCh. 7 - Prob. 12CRCh. 7 - Prob. 13CRCh. 7 - Prob. 14CRCh. 7 - 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