a. Answer The length of playground is x − 15 . Explanation Given: Area of playground is a = x 2 − 30 x + 225 Calculation: a = x 2 − 30 x + 225 = x 2 − 30 x + 225 = x 2 − 2 ( x ) ( 15 ) + 15 2 a 2 − 2 a b + b 2 = ( a − b ) 2 x 2 − 2 ( x ) ( 15 ) + 15 2 = ( x − 15 ) 2 Area = ( s i d e ) 2 Compare the area ( s i d e ) 2 = ( x − 15 ) 2 side = x − 15 Thus the length of playground is x − 15 . b. To determine Write an expression for the perimeter of the playground. Answer The perimeter of the playground is 4 x − 60 . Explanation Given: Given area is a = x 2 − 30 x + 225 Calculation: In part a we find side of square. Perimeter of square is 4 × side Perimeter = 4 ( x − 15 ) Perimeter = 4 x − 60 Thus the perimeter is 4 x − 60 .

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015

1st Edition

ISBN: 9781680331141

Author: HOUGHTON MIFFLIN HARCOURT

Publisher: Houghton Mifflin Harcourt

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Question

Chapter 7.7, Problem 26E

To determine

Write a polynomial that represents the side length of the playground.

Expert Solution

Answer to Problem 26E

The length of playground is x−15 .

Explanation of Solution

Given:

Area of playground is a=x2−30x+225

Calculation:a=x2−30x+225

=x2−30x+225=x2−2(x)(15)+152a2−2ab+b2=(a−b)2x2−2(x)(15)+152=(x−15)2

Area =(side)2

Compare the area

(side)2=(x−15)2side=x−15

Thus the length of playground is x−15 .

To determine

Write an expression for the perimeter of the playground.

Expert Solution

Answer to Problem 26E

The perimeter of the playground is 4x−60 .

Explanation of Solution

Given:

Given area is a=x2−30x+225

Calculation:In part a we find side of square.

Perimeter of square is 4× side

Perimeter =4(x−15)

Perimeter =4x−60

Thus the perimeter is 4x−60 .

Chapter 7.7, Problem 25E

Chapter 7.7, Problem 27E

Chapter 7 Solutions

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015

Ch. 7.1 - Prob. 1E Ch. 7.1 - Prob. 2E Ch. 7.1 - Prob. 3E Ch. 7.1 - Prob. 4E Ch. 7.1 - Prob. 5E Ch. 7.1 - Prob. 6E Ch. 7.1 - Prob. 7E Ch. 7.1 - Prob. 8E Ch. 7.1 - Prob. 9E Ch. 7.1 - Prob. 10E

Ch. 7.1 - Prob. 11E Ch. 7.1 - Prob. 12E Ch. 7.1 - Prob. 13E Ch. 7.1 - Prob. 14E Ch. 7.1 - Prob. 15E Ch. 7.1 - Prob. 16E Ch. 7.1 - Prob. 17E Ch. 7.1 - Prob. 18E Ch. 7.1 - Prob. 19E Ch. 7.1 - Prob. 20E Ch. 7.1 - Prob. 21E Ch. 7.1 - Prob. 22E Ch. 7.1 - Prob. 23E Ch. 7.1 - Prob. 24E Ch. 7.1 - Prob. 25E Ch. 7.1 - Prob. 26E Ch. 7.1 - Prob. 27E Ch. 7.1 - Prob. 28E Ch. 7.1 - Prob. 29E Ch. 7.1 - Prob. 30E Ch. 7.1 - Prob. 31E Ch. 7.1 - Prob. 32E Ch. 7.1 - Prob. 33E Ch. 7.1 - Prob. 34E Ch. 7.1 - Prob. 35E Ch. 7.1 - Prob. 36E Ch. 7.1 - Prob. 37E Ch. 7.1 - Prob. 38E Ch. 7.1 - Prob. 39E Ch. 7.1 - Prob. 40E Ch. 7.1 - Prob. 41E Ch. 7.1 - Prob. 42E Ch. 7.1 - Prob. 43E Ch. 7.1 - Prob. 44E Ch. 7.1 - Prob. 45E Ch. 7.1 - Prob. 46E Ch. 7.1 - Prob. 47E Ch. 7.1 - Prob. 48E Ch. 7.1 - Prob. 49E Ch. 7.1 - Prob. 50E Ch. 7.1 - Prob. 51E Ch. 7.1 - Prob. 52E Ch. 7.1 - Prob. 53E Ch. 7.1 - Prob. 54E Ch. 7.1 - Prob. 55E Ch. 7.1 - Prob. 56E Ch. 7.1 - Prob. 57E Ch. 7.1 - Prob. 58E Ch. 7.1 - Prob. 59E Ch. 7.1 - Prob. 60E Ch. 7.1 - 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