Statistics: The Art and Science of Learning From Data, Books a la Carte Edition (4th Edition)
4th Edition
ISBN: 9780133860825
Author: Alan Agresti, Christine A. Franklin, Bernhard Klingenberg
Publisher: PEARSON
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Chapter 8, Problem 126CP
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You want to obtain a sample to estimate a population proportion. Based on previous evidence, you believe the population proportion is approximately ˆp=22%p^=22%. You would like to be 99% confident that your esimate is within 1.5% of the true population proportion. How large of a sample size is required?
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You want to obtain a sample to estimate a population proportion. Based on previous evidence, you believe the population proportion is approximately ˆpp^ = 60%`. You would like to be 95% confident that your esimate is within 2% of the true population proportion. How large of a sample size is required?
Chapter 8 Solutions
Statistics: The Art and Science of Learning From Data, Books a la Carte Edition (4th Edition)
Ch. 8.1 - Health care A study dealing with health care...Ch. 8.1 - Video on demand A recent study from Nielsen...Ch. 8.1 - Projecting winning candidate News coverage during...Ch. 8.1 - Believe in hell? Using the General Social Survey...Ch. 8.1 - Government spying In 2014, news reports worldwide...Ch. 8.1 - Game apps The Google Play app store for...Ch. 8.1 - Nutrient effect on growth rate Researchers are...Ch. 8.1 - Believe in heaven? When a GSS asked 1326 subjects,...Ch. 8.1 - Feel lonely often? The GSS has asked On how many...Ch. 8.1 - CI for loneliness Refer to the previous exercise....
Ch. 8.2 - Putin A Gallup poll of 2000 Russians taken between...Ch. 8.2 - Flu shot In a clinical study (the same as...Ch. 8.2 - How green are you? When the 2000 GSS asked...Ch. 8.2 - Make industry help environment? When the 2006 GSS...Ch. 8.2 - Favor death penalty In the 2012 General Social...Ch. 8.2 - Oppose death penalty Refer to the previous...Ch. 8.2 - Stem cell research A Harris poll of a random...Ch. 8.2 - z-score and confidence level Which z-score is used...Ch. 8.2 - Believe in ghosts A Harris poll of a random sample...Ch. 8.2 - Stem cell research and religion In Exercise 8.18,...Ch. 8.2 - Fear of breast cancer A recent survey of 1000...Ch. 8.2 - Chicken breast In a 2014 Consumer Reports article...Ch. 8.2 - Same-sex marriage A national survey by the Pew...Ch. 8.2 - Exit poll predictions A national television...Ch. 8.2 - Exit poll with smaller sample In the previous...Ch. 8.2 - Simulating confidence intervals Repeat the...Ch. 8.2 - Simulating confidence intervals with poor coverage...Ch. 8.3 - Females ideal number of children The 2012 General...Ch. 8.3 - Males ideal number of children Refer to the...Ch. 8.3 - Using t-table Using Table B, the web app, software...Ch. 8.3 - Anorexia in teenage girls A study6 compared...Ch. 8.3 - Talk time on smartphones One feature smartphone...Ch. 8.3 - Heights of seedlings Exercise 8.7 reported heights...Ch. 8.3 - Buy it now Example 6 mentioned closing prices for...Ch. 8.3 - Time spent on e-mail When the GSS asked n = 1050...Ch. 8.3 - Grandmas using e-mail For the question about...Ch. 8.3 - Prob. 38PBCh. 8.3 - Prob. 39PBCh. 8.3 - Political views The General Social Survey asks...Ch. 8.3 - Prob. 41PBCh. 8.3 - Prob. 42PBCh. 8.3 - Effect of confidence level Find the margin of...Ch. 8.3 - Prob. 44PBCh. 8.3 - Number of children For the question, How many...Ch. 8.3 - Prob. 46PBCh. 8.4 - South Africa study The researcher planning the...Ch. 8.4 - Binge drinkers A study at the Harvard School of...Ch. 8.4 - Prob. 49PBCh. 8.4 - Prob. 50PBCh. 8.4 - Prob. 51PBCh. 8.4 - Farm size An estimate is needed of the mean...Ch. 8.4 - Prob. 53PBCh. 8.4 - Prob. 54PBCh. 8.4 - Prob. 55PBCh. 8.4 - Prob. 56PBCh. 8.4 - Prob. 57PBCh. 8.4 - Prob. 58PBCh. 8.5 - Why bootstrap? Explain the purpose of using the...Ch. 8.5 - Estimating variability Refer to Example 11 about...Ch. 8.5 - Bootstrap interval for the mean In 2014, the...Ch. 8.5 - Prob. 62PBCh. 8 - Unemployed college grads The U.S Bureau of the...Ch. 8 - Prob. 64CPCh. 8 - Prob. 65CPCh. 8 - Born again A poll of a random sample of n = 2000...Ch. 8 - Life after death The variable POSTLIFE in the 2012...Ch. 8 - Prob. 68CPCh. 8 - Prob. 69CPCh. 8 - Prob. 70CPCh. 8 - Prob. 71CPCh. 8 - Wife supporting husband Consider the statement...Ch. 8 - Legalize marijuana? The General Social Survey has...Ch. 8 - Prob. 74CPCh. 8 - Streaming A Harris Poll of 2300 U.S. adults...Ch. 8 - Prob. 76CPCh. 8 - Prob. 77CPCh. 8 - Grandpas using e-mail When the GSS asked in 2012,...Ch. 8 - Prob. 79CPCh. 8 - Prob. 80CPCh. 8 - Fuel efficiency The government website...Ch. 8 - Prob. 82CPCh. 8 - Prob. 83CPCh. 8 - Prob. 84CPCh. 8 - Prob. 85CPCh. 8 - Prob. 86CPCh. 8 - Prob. 87CPCh. 8 - Revisiting mountain bikes Use the Mountain Bike...Ch. 8 - Prob. 89CPCh. 8 - Prob. 90CPCh. 8 - Prob. 91CPCh. 8 - Prob. 92CPCh. 8 - Working mother In response to the statement on a...Ch. 8 - Miami spring break For a trip to Miami, Florida,...Ch. 8 - Prob. 95CPCh. 8 - Prob. 96CPCh. 8 - Prob. 97CPCh. 8 - Prob. 98CPCh. 8 - Prob. 99CPCh. 8 - Prob. 100CPCh. 8 - Kicking accuracy A football coach decides to...Ch. 8 - Prob. 103CPCh. 8 - Prob. 104CPCh. 8 - Prob. 106CPCh. 8 - Width of a confidence interval Why are confidence...Ch. 8 - Prob. 108CPCh. 8 - Prob. 109CPCh. 8 - Prob. 110CPCh. 8 - Prob. 111CPCh. 8 - Prob. 112CPCh. 8 - Prob. 113CPCh. 8 - Prob. 114CPCh. 8 - Prob. 115CPCh. 8 - Prob. 116CPCh. 8 - Prob. 117CPCh. 8 - Prob. 118CPCh. 8 - Prob. 119CPCh. 8 - Prob. 120CPCh. 8 - Prob. 121CPCh. 8 - Prob. 122CPCh. 8 - Prob. 123CPCh. 8 - Why called degrees of freedom? You know the sample...Ch. 8 - Prob. 125CPCh. 8 - Prob. 126CPCh. 8 - Median as point estimate When the population...
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- You want to obtain a sample to estimate a population proportion. Based on previous evidence, you believe the population proportion is approximately p^=67%. You would like to be 90% confident that your esimate is within 5% of the true population proportion. How large of a sample size is required?Do not round mid-calculation.arrow_forwardYou want to obtain a sample to estimate a population proportion. Based on previous evidence, you believe the population proportion is approximately ˆp=35%p^=35%. You would like to be 90% confident that your esimate is within 1% of the true population proportion. How large of a sample size is required? You are interested in estimating the the mean weight of the local adult population of female white-tailed deer (doe). From past data, you estimate that the standard deviation of all adult female white-tailed deer in this region to be 27 pounds. What sample size would you need to in order to estimate the mean weight of all female white-tailed deer, with a 96% confidence level, to within 5 pounds of the actual weight? (Use Excel to find the appropriate critical value and round to 3 decimal places.)arrow_forwardTwo companies manufacture a rubber material in- tended for use in an automotive application. The part will be subjected to abrasive wear in the field application, so we decide to compare the material produced by each company in a test. Twenty-five samples of material from each company are tested in an abrasion test, and the amount of wear after 1000 cycles is observed. For company 1, the sample mean and standard de- viation of wear are = 20 milligrams/1000 cycles and s = 2 milligrams/1000 cycles, while for company 2 we obtain = 15 milligrams/1000 cycles and s, = 8 milligrams/1000 cycles. Find a 95% confidence interval on the difference in mean wear µ, - Hz. Assume each population is normally distributed but that their variances are not equal. What is the lower bound? Three decimal placesarrow_forward
- The proportion of Americans who have frequent migraines is 15.2% according to the CDC. An acupuncturist claims that her treatment can reduce this figure significantly. A random sample of 594 Americans is administered the acupuncturists treatment and 71 report experiencing migraines. What is the sample proportion? (Round to 2 decimal places) ˆpp^=______arrow_forwardBlood pressure is 127.58 sample of 41 males,, 35-44 in age.. blood pressure of 5.76. Find 95% co fidence intervalarrow_forwardIn a random sample of size 58, 29 people say they generally get less than 8 hours of sleep a night. Calculate the point estimates ˆpp^ and ˆqq^.arrow_forward
- There are two samples of children taken from a population. In the first sample, mean of age of 20 children is 8.5 years with standard deviation 3 years. In the second sample mean of age of 30 children is 7 years with standard deviation 2 years. If we combine these samples, what are the mean and the standard deviation of the combined sample? Age in which sample is more spread and why? Show your work by using formula and use 1 decimal place.arrow_forwardA random variable of 7 independent observation of a normal variable gave Ex = 35.9 Ex2 = 186.19 E(x-x)2 = 2.074 Calculate The sample mean The sample variance A 90% confidence interval for the population meanarrow_forwardMultiple Choice. Choose the letter of the correct answer. Write the letter of your answer before the number (2pts.) I. 1. This is the single value used to represent the parameter interest. a. Interval estimatearrow_forward
- The formula for estimating the number of people, nn, that need to be surveyed in order to have a specified margin of error with a specified level of confidence for the average age of first kiss is given by n=z^2*stdDev^2/E^2 where z=2.266 depends on the level of confidence, stdDev is the standard deviation and E is the margin of error. How many people need to be surveyed if the standard deviation is 1.939 years and the margin of error is 0.122 years.n = (Please always round your answer up to the smallest whole number that is greater than or equal to your answer.)arrow_forwardYou want to obtain a sample to estimate a population proportion. Based on previous evidence, you believe the population proportion is approximately ˆp=90%p^=90%. You would like to be 99.5% confident that your esimate is within 1.5% of the true population proportion. How large of a sample size is required? I must have tried this question and ones similiar to it a dozen times. Can you break this down for me so I understand I'm doing wrong? Thank you!arrow_forwardIn a particular county, the population proportion of residents were born in the county is 0.7. Consider the sampling distribution of ?̂ p^ = the sample proportion of residents in a sample of ?=200n=200 who were born in the county. Note that (0.7)(1−0.7)200‾‾‾‾‾‾‾‾‾‾‾‾‾√=0.0324037034920393(0.7)(1−0.7)200=0.0324037034920393 NOTE: Your answers below should be entered as proportions (not percentages). Do not round during intermediate steps. If you round an answer, make sure you do so correctly and keep at least three decimal places. (a) The mean of the sampling distribution of ?̂ p^ is: (b) The standard deviation of the sampling distribution of ?̂ p^ is:arrow_forward
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