Essentials of Genetics (9th Edition) - Standalone book
9th Edition
ISBN: 9780134047799
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Chapter 8, Problem 20PDQ
A phage-infected bacterial culture was subjected to a series of dilutions, and a plaque assay was performed in each case, with the following results. What conclusion can be drawn in the case of each dilution?
| Dilution Factor | Assay Results | |
| (a) | 104 | All bacteria lysed |
| (b) | 106 | 14 plaques |
| (c) | 108 | 0 plaques |
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Students have asked these similar questions
In a plaque assay, a phage has undergone _________ cycle when plaques are observed on the agar lawn post- incubation. What is the answer on the blank?
Which of the following is TRUE when one assay bacteriophage titers? You should:
a) first mix the phages with a live bacterial culture and then pour the mixture on the agar plate
b) directly add the phage dilution onto the surface of an agar plate
c) add tryptic soy broth to the phage dilution and incubate overnight
d) incubate a phage solution with live bacterial cells for several minutes. You must add soft agar to the mixture before pouring the content on the agar plate
You have conducted serial 10-fold dilutions and measured the cfu (colony forming units) of a Streptococcus pneumoniae culture and also the pfu (plaque forming units) of a phage (virus) that infects the bacteria. You counted 5 cfu in a 0.4 ml sample of a 106 dilution of the bacterial sample. You then counted 50 plaque-forming units (pfu) in a 0.25 ml sample of a 108 diluted sample of the phage culture. What are the cfu/ml of the S. pneumoniae and pfu/ml of the phage cultures before dilution?
5 x 106 cfu/ml and 2 x 109 pfu/ml
4 x 107 CFU/ml and 2 x 109 PFU/ml
1.25 x 108 cfu/ml and 10 x 1010 pfu/ml
1.25 x 107 cfu/ml and 2 x 1010 pfu/ml
Chapter 8 Solutions
Essentials of Genetics (9th Edition) - Standalone book
Ch. 8 -
CASE STUDY | To treat or not to treat
A...Ch. 8 - CASE STUDY | To treat or not to treat A...Ch. 8 - Prob. 3CSCh. 8 - Prob. 4CSCh. 8 - HOW DO WE KNOW? In this chapter, we have focused...Ch. 8 -
CONCEPT QUESTION
2. Review the Chapter Concepts...Ch. 8 -
3. Distinguish among the three modes of...Ch. 8 - With respect to F+ and F- bacterial matings, (a)...Ch. 8 - List all of the differences between F+ × F– and...Ch. 8 - Describe the basis for chromosome mapping in the...
Ch. 8 - Why are the recombinants produced from an Hfr × F–...Ch. 8 - Describe the origin of F' bacteria and...Ch. 8 -
9. Describe the mechanism of transformation.
Ch. 8 - .
10. The bacteriophage genome consists primarily...Ch. 8 - Prob. 11PDQCh. 8 - In the plaque assay, what is the precise origin of...Ch. 8 -
13. In the plaque assay, exactly what makes up a...Ch. 8 - A plaque assay is performed beginning with 1.0 mL...Ch. 8 -
15. Describe the difference between the lytic...Ch. 8 - Prob. 16PDQCh. 8 -
17. Explain the observations that led Zinder and...Ch. 8 -
18. Describe the execution of and rationale...Ch. 8 - If a single bacteriophage infects one E. coli cell...Ch. 8 - A phage-infected bacterial culture was subjected...
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- What is an advantage of using an ELISA instead of a protein microarray to study a proteome? What is a disadvantage?arrow_forward1- Why was the T4 and E.coli mixed together in top agar and then poured on the plate instead of just spreading the two together with a glass spreader on the plate? 2- When doing the titration and isolation of the T4 phage, E.coli diluted for you to 10e7 cells/ml. why was a diluted culture used? 3- After doing the titration of T4 phage, you find your dilution plates are all TNTC. how could this have happened? 4- Could you isolate phages that infect E.coli from raw sewerage? explain.arrow_forwardA high cell density culture of recombinant E. coli was carried out according to the following strategy:-Step 1: single batch with exponential growth until 98% conversion of the substrate, starting from V0= 4.0 L, S0=50 g/L/ X0= 1.0 g/LStep 2: batch fed with exponential flow (SF-800 g/L, μ= 0.1 h-1) until reaching X= 50.9 g/L;Step 3: batch fed with constant flow (F= 0.1 L/h) for 4 hours (induction phase with IPTG)Note: consider that the quasi-steady state is reached in both fed-batch stages.Extra data: YX/S = 0.4 gx/gs; μmax= 0.25 h-1; Ks== 1.0 g/L a) What was the cell concentration reached at the end of step 1?b) For step 3, considering that the substrate concentration in the feed was 1/4 of that used in step 2, what was the concentration of cells reached at the end of step 3?C) In terms of cell productivity, which of the three phases of cultivation was the most productive?arrow_forward
- A plaque assay is performed beginning with 1 mL of a solution containing bacteriophages. This solution is serially diluted three times by combining 0.1 mL of each sequential dilution with 9.9 mL of liquid medium. Then 0.1 mL of the final dilution is plated in the plaque assay and yields 17 plaques. What is the initial density of bacteriophages in the original 1 mL?arrow_forwardA plaque assay is performed beginning with 1 mL of a solution containing bacteriophages. This solution is serially diluted 4 times by combining 0.1 mL of each sequential dilution with 9.9 mL of liquid medium. Then 0.1 mL of the final dilution is plated in the plaque assay and yields 21 plaques. What is the initial density of bacteriophages in the original 1 mL? Recall that initial phage density = (plaque number/mL) ×× (dilution factor).arrow_forwardPetri dish. Explain in your own words how bacteria are grown to form the sample for the antibiotic resistance test?arrow_forward
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