An ionic bond is formed between a cation A + and an anion B - Based on Coulomb's law E α Q 1 × Q 2 d how would the energy of the ionic bond be affected by the following changes: (a) doubling the radius of A + , (b) tripling the charge on A + , (c) doubling the charges on A + and B - , (d) decreasing the radii of A + and B - - to half their original values?
An ionic bond is formed between a cation A + and an anion B - Based on Coulomb's law E α Q 1 × Q 2 d how would the energy of the ionic bond be affected by the following changes: (a) doubling the radius of A + , (b) tripling the charge on A + , (c) doubling the charges on A + and B - , (d) decreasing the radii of A + and B - - to half their original values?
Solution Summary: The author explains that Coulomb's law states that energy is directly proportional to the force of attraction between the ions.
An ionic bond is formed between a cation
A
+
and an anion
B
-
Based on Coulomb's law
E
α
Q
1
×
Q
2
d
how would the energy of the ionic bond be affected by the following changes: (a) doubling the radius of
A
+
, (b) tripling the charge on
A
+
, (c) doubling the charges on
A
+
and
B
-
, (d) decreasing the radii of
A
+
and
B
-
- to half their original values?
Wouldn't the charge of [Ru(H2O)3(CN)3] be +1 because Br would have a charge of -1?
An experiment was conducted to determine the Cl - Cl bond energy in chlorine. It was determined the minimum energy required to break a Cl - Cl bond was 3.90 x 10-19 J. According to these experimental results, what is the Cl - Cl bond energy (in kJ/mol)?
As seen in the table, compounds containing an integer ratio of elements depend on how many cations combine with how many anions to form a stable compound. For example, in table 1, to form a NaCl compound, first Na ionizes from the Na+ cation which is having +1 positive charge, which will lose 1 electron, it is having +1 charge, this electron then goes to Cl and it will change to Cl- anion by gaining the electron, so here 1:1 ratio charge which means 1 Na+ combines with 1 Cl-1 to form NaCl. So here integer ratio is 1:1 for this sodium chloride compound. As listed in table 2, Mg(OH)2, the integer ratio is 1:2 which means, Mg is a neutral atom that loses 2 electrons and forms an Mg+2 cation, which combines with OH which gains 1 electron to form OH- anion, So here Mg2+ can combine with 2 OH- anion, so they both combine to form Mg(OH)2 which has integer ratio as 1:2 . Thus, atom forms as ions by losing or gaining electrons and combines together in whole number ratio to form stable…
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Calorimetry Concept, Examples and Thermochemistry | How to Pass Chemistry; Author: Melissa Maribel;https://www.youtube.com/watch?v=nSh29lUGj00;License: Standard YouTube License, CC-BY