Chapter 8, Problem 22E

Interpretation Introduction

(a)

Interpretation:

The mass of sodium is to be calculated.

Concept introduction:

A mole is the amount of substance that has Avogadro’s number of particles $\left(\text{6}\text{.02}\times {\text{10}}^{\text{23}}\right)$. Mathematically, the mole is the ratio of the mass and the molecular mass of the substances.

$\text{Mole}=\frac{\text{Mass}}{\text{Molecular mass}}$

One mole of atom or molecule is equal to $\text{6}\text{.02}\times {\text{10}}^{\text{23}}$ particles.

Answer to Problem 22E

The mass of sodium is $3.82\times {\text{10}}^{-\text{23}}\text{g}/\text{atom}$.

Explanation of Solution

The mass of sodium is calculated by the formula shown below.

$\text{Mass}=M_{\text{Na}}\times \frac{\text{1}\text{mole}}{\text{6}\text{.023}\times {\text{10}}^{\text{23}}\text{atom}}$ …(1)

Where,

• $M_{\text{Na}}$ is molar mass of sodium.

The value of molar mass of sodium is $\text{23}\text{g}/\text{mol}$.

Substitute the value of molar mass of sodium in equation (1).

$\begin{array}{rll}\text{Mass}& =& M_{\text{Na}}\times \frac{\text{1}\text{mole}}{\text{6}\text{.023}\times {\text{10}}^{\text{23}}\text{atom}}\\ & =& \text{23}\text{g}/\text{mole}\times \frac{\text{1}\text{mole}}{\text{6}\text{.023}\times {\text{10}}^{\text{23}}\text{atom}}\\ & =& \frac{\text{23}}{\text{6}\text{.023}}\times {\text{10}}^{-\text{23}}\text{g}/\text{atom}\\ & =& 3.82\times {\text{10}}^{-\text{23}}\text{g}/\text{atom}\end{array}$

Conclusion

The mass of sodium is $3.82\times {\text{10}}^{-\text{23}}\text{g}/\text{atom}$.

Interpretation Introduction

(b)

Interpretation:

The mass of germanium is to be calculated

Concept introduction:

A mole is the amount of substance that has Avogadro’s number of particles $\left(\text{6}\text{.02}\times {\text{10}}^{\text{23}}\right)$. Mathematically, the mole is the ratio of the mass and the molecular mass of the substances.

$\text{Mole}=\frac{\text{Mass}}{\text{Molecular mass}}$

One mole of atom or molecule is equal to $\text{6}\text{.02}\times {\text{10}}^{\text{23}}$ particles.

Answer to Problem 22E

The mass of germanium is $12.06\times {\text{10}}^{-\text{23}}\text{g}/\text{atom}$.

Explanation of Solution

The mass of germanium is calculated by the formula shown below.

$\text{Mass}=M_{\text{Ge}}\times \frac{\text{1}\text{mole}}{\text{6}\text{.023}\times {\text{10}}^{\text{23}}\text{atom}}$ …(1)

Where,

• $M_{\text{Ge}}$ is molar mass of germanium.

The value of molar mass of germanium is $\text{72}\text{.64}\text{g}/\text{mol}$.

Substitute the value of molar mass of germanium in equation (1).

$\begin{array}{rll}\text{Mass}& =& M_{\text{Ge}}\times \frac{\text{1}\text{mole}}{\text{6}\text{.023}\times {\text{10}}^{\text{23}}\text{atom}}\\ & =& \text{72}\text{.64}\text{g}/\text{mol}\times \frac{\text{1}\text{mole}}{\text{6}\text{.023}\times {\text{10}}^{\text{23}}\text{atom}}\\ & =& \frac{\text{72}\text{.64}}{\text{6}\text{.023}}\times {\text{10}}^{-\text{23}}\text{g}/\text{atom}\\ & =& 12.06\times {\text{10}}^{-\text{23}}\text{g}/\text{atom}\end{array}$

Conclusion

The mass of germanium is $12.06\times {\text{10}}^{-\text{23}}\text{g}/\text{atom}$.

Interpretation Introduction

(c)

Interpretation:

The mass of sulfur trioxide is to be calculated.

Concept introduction:

A mole is the amount of substance that has Avogadro’s number of particles $\left(\text{6}\text{.02}\times {\text{10}}^{\text{23}}\right)$. Mathematically, the mole is the ratio of the mass and the molecular mass of the substances.

$\text{Mole}=\frac{\text{Mass}}{\text{Molecular mass}}$

One mole of atom or molecule is equal to $\text{6}\text{.02}\times {\text{10}}^{\text{23}}$ particles.

Answer to Problem 22E

The mass of sulfur trioxide is $13.29\times {\text{10}}^{-\text{23}}\text{g}/\text{molecule}$.

Explanation of Solution

The mass of sulfur trioxide is calculated by the formula shown below.

$\text{Mass}=M_{{\text{SO}}_3}\times \frac{\text{1}\text{mole}}{\text{6}\text{.023}\times {\text{10}}^{\text{23}}\text{molecule}}$ …(1)

Where,

• $M_{{\text{SO}}_3}$ is molar mass of sulfur trioxide.

The value of molar mass of sulfur trioxide is $80.07\text{g}/\text{mol}$.

Substitute the value of molar mass of sulfur trioxide in equation (1).

$\begin{array}{rll}\text{Mass}& =& M_{{\text{SO}}_3}\times \frac{\text{1}\text{mole}}{\text{6}\text{.023}\times {\text{10}}^{\text{23}}\text{molecule}}\\ & =& 80.07\text{g}/\text{mol}\times \frac{\text{1}\text{mole}}{\text{6}\text{.023}\times {\text{10}}^{\text{23}}\text{molecule}}\\ & =& \frac{80.07}{\text{6}\text{.023}}\times {\text{10}}^{-\text{23}}\text{g}/\text{molecule}\\ & =& 13.29\times {\text{10}}^{-\text{23}}\text{g}/\text{molecule}\end{array}$

Conclusion

The mass of sulfur trioxide is $13.29\times {\text{10}}^{-\text{23}}\text{g}/\text{molecule}$.

Interpretation Introduction

(d)

Interpretation:

The mass of nitric oxide is to be calculated.

Concept introduction:

A mole is the amount of substance that has Avogadro’s number of particles $\left(\text{6}\text{.02}\times {\text{10}}^{\text{23}}\right)$. Mathematically, the mole is the ratio of the mass and the molecular mass of the substances.

$\text{Mole}=\frac{\text{Mass}}{\text{Molecular mass}}$

One mole of an atom or molecule is equal to $\text{6}\text{.02}\times {\text{10}}^{\text{23}}$ particles.

Answer to Problem 22E

The mass of nitric oxide is $4.98\times {\text{10}}^{-\text{23}}\text{g}/\text{molecule}$.

Explanation of Solution

The mass of nitric oxide is calculated by the formula shown below.

$\text{Mass}=M_{\text{NO}}\times \frac{\text{1}\text{mole}}{\text{6}\text{.023}\times {\text{10}}^{\text{23}}\text{molecule}}$ …(1)

Where,

• $M_{\text{NO}}$ is molar mass of nitric oxide.

The value of molar mass of nitric oxide is $\text{30}\text{.01}\text{g}/\text{mol}$.

Substitute the value of molar mass of nitric oxide in equation (1).

$\begin{array}{rll}\text{Mass}& =& M_{\text{NO}}\times \frac{\text{1}\text{mole}}{\text{6}\text{.023}\times {\text{10}}^{\text{23}}\text{molecule}}\\ & =& \text{30}\text{.01}\text{g}/\text{mol}\times \frac{\text{1}\text{mole}}{\text{6}\text{.023}\times {\text{10}}^{\text{23}}\text{molecule}}\\ & =& \frac{\text{30}\text{.01}}{\text{6}\text{.023}}\times {\text{10}}^{-\text{23}}\text{g}/\text{molecule}\\ & =& 4.98\times {\text{10}}^{-\text{23}}\text{g}/\text{molecule}\end{array}$

Conclusion

The mass of nitric oxide is $4.98\times {\text{10}}^{-\text{23}}\text{g}/\text{molecule}$.