Explanation Given: ( − 1 , 2 ) ( 0 , − 1 ) ( 1 , 1 ) Formula used: b = ( ∑ i = 1 3 x i 2 ∑ i = 1 3 y i − ∑ i = 1 3 x i ∑ i = 1 3 x i y i ) 3 ∑ i = 1 3 x i 2 − ( ∑ i = 1 3 x i ) 2 m = 3 ( ∑ i = 1 3 x i y i − ∑ i = 1 3 x i ∑ i = 1 3 y i ) 3 ∑ i = 1 3 x i 2 − ( ∑ i = 1 3 x i ) 2 Calculation: We have the equation of the line as y = b + m x . In the equation, we are substituting x and y co-ordinates as below. Let, b = ( ∑ i = 1 3 x i 2 ∑ i = 1 3 y i − ∑ i = 1 3 x i ∑ i = 1 3 x i y i ) 3 ∑ i = 1 3 x i 2 − ( ∑ i = 1 3 x i ) 2 Here, n=3, ∑ i = 1 3 x i = − 1 + 0 + 1 = 0 ∑ i = 1 3 y i = 2 − 1 + 1 = 2 <

Applied Calculus, 6e WileyPLUS + Loose-leaf

6th Edition

ISBN: 9781119408901

Author: Deborah Hughes-Hallett, Andrew M. Gleason, Patti Frazer Lock, Daniel E. Flath

Publisher: Wiley (WileyPLUS Products)

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Equations and inequalities describe the relationship between two mathematical expressions.

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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.

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Question

Chapter 8, Problem 3FOT

To determine

The least-squares line for (−1,2)(0,−1)(1,1).

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Chapter 8, Problem 2FOT

Chapter 8, Problem 4FOT

Chapter 8 Solutions

Applied Calculus, 6e WileyPLUS + Loose-leaf

Ch. 8.1 - Prob. 1P Ch. 8.1 - Prob. 2P Ch. 8.1 - Prob. 3P Ch. 8.1 - Prob. 4P Ch. 8.1 - Prob. 5P Ch. 8.1 - Prob. 6P Ch. 8.1 - Prob. 7P Ch. 8.1 - Prob. 8P Ch. 8.1 - Prob. 9P Ch. 8.1 - Prob. 10P

Ch. 8.1 - Prob. 11P Ch. 8.1 - Prob. 12P Ch. 8.1 - Prob. 13P Ch. 8.1 - Prob. 14P Ch. 8.1 - Prob. 15P Ch. 8.1 - Prob. 16P Ch. 8.1 - Prob. 17P Ch. 8.1 - Prob. 18P Ch. 8.1 - Prob. 19P Ch. 8.1 - Prob. 20P Ch. 8.1 - Prob. 21P Ch. 8.1 - Prob. 22P Ch. 8.1 - Prob. 23P Ch. 8.1 - Prob. 24P Ch. 8.1 - Prob. 25P Ch. 8.1 - Prob. 26P Ch. 8.1 - Prob. 27P Ch. 8.1 - Prob. 28P Ch. 8.1 - Prob. 29P Ch. 8.1 - Prob. 30P Ch. 8.2 - Prob. 1P Ch. 8.2 - Prob. 2P Ch. 8.2 - Prob. 3P Ch. 8.2 - Prob. 4P Ch. 8.2 - Prob. 5P Ch. 8.2 - Prob. 6P Ch. 8.2 - Prob. 7P Ch. 8.2 - Prob. 8P Ch. 8.2 - Prob. 9P Ch. 8.2 - Prob. 10P Ch. 8.2 - Prob. 11P Ch. 8.2 - Prob. 12P Ch. 8.2 - Prob. 13P Ch. 8.2 - Prob. 14P Ch. 8.2 - Prob. 15P Ch. 8.2 - Prob. 16P Ch. 8.2 - Prob. 17P Ch. 8.2 - Prob. 18P Ch. 8.2 - Prob. 19P Ch. 8.2 - Prob. 20P Ch. 8.2 - Prob. 21P Ch. 8.2 - Prob. 22P Ch. 8.2 - Prob. 23P Ch. 8.2 - Prob. 24P Ch. 8.2 - Prob. 25P Ch. 8.2 - Prob. 26P Ch. 8.2 - Prob. 27P Ch. 8.2 - Prob. 28P Ch. 8.2 - Prob. 29P Ch. 8.2 - Prob. 30P Ch. 8.2 - 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Prob. 24P Ch. 8.6 - Prob. 25P Ch. 8.6 - Prob. 26P Ch. 8.6 - Prob. 27P Ch. 8 - Prob. 1SYU Ch. 8 - Prob. 2SYU Ch. 8 - Prob. 3SYU Ch. 8 - Prob. 4SYU Ch. 8 - Prob. 5SYU Ch. 8 - Prob. 6SYU Ch. 8 - Prob. 7SYU Ch. 8 - Prob. 8SYU Ch. 8 - Prob. 9SYU Ch. 8 - Prob. 10SYU Ch. 8 - Prob. 11SYU Ch. 8 - Prob. 12SYU Ch. 8 - Prob. 13SYU Ch. 8 - Prob. 14SYU Ch. 8 - Prob. 15SYU Ch. 8 - Prob. 16SYU Ch. 8 - Prob. 17SYU Ch. 8 - Prob. 18SYU Ch. 8 - Prob. 19SYU Ch. 8 - Prob. 20SYU Ch. 8 - Prob. 21SYU Ch. 8 - Prob. 22SYU Ch. 8 - Prob. 23SYU Ch. 8 - Prob. 24SYU Ch. 8 - Prob. 25SYU Ch. 8 - Prob. 26SYU Ch. 8 - Prob. 27SYU Ch. 8 - Prob. 28SYU Ch. 8 - Prob. 29SYU Ch. 8 - Prob. 30SYU Ch. 8 - Prob. 31SYU Ch. 8 - Prob. 32SYU Ch. 8 - Prob. 33SYU Ch. 8 - Prob. 34SYU Ch. 8 - Prob. 35SYU Ch. 8 - Prob. 36SYU Ch. 8 - Prob. 37SYU Ch. 8 - Prob. 38SYU Ch. 8 - Prob. 39SYU Ch. 8 - Prob. 40SYU Ch. 8 - Prob. 41SYU Ch. 8 - Prob. 42SYU Ch. 8 - Prob. 43SYU Ch. 8 - Prob. 44SYU Ch. 8 - Prob. 45SYU Ch. 8 - Prob. 46SYU Ch. 8 - Prob. 47SYU Ch. 8 - 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The least-squares line for ( − 1 , 2 ) ( 0 , − 1 ) ( 1 , 1 ) .

Solution Summary: The author calculates the least-squares line for (-1,2).

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The least-squares line for (−1,2)(0,−1)(1,1).

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Chapter 8 Solutions