FOUNDATIONS OF ASTRONOMY (LL)-W/MINDTAP
14th Edition
ISBN: 9780357000502
Author: Seeds
Publisher: CENGAGE L
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Chapter 8, Problem 3P
To determine
The ground-based solar telescope’s smallest detail visible is
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Calculate the total amount of radiative energy per second intercepted by Mars from the Sun using the flux of radiation from the Sun at Mars' orbital radius.
Flux of radiation from the Sun at Mars' orbital radius is 597 W m-2.
The luminosity of the Sun Ls = 3.8×1026 W.
Mars orbits at a distance of 2.25×1011 m (1.5 AU) from the Sun.
Note: Consider carefully the cross-sectional area Mars presents to the outwards flow of radiative energy when answering this question.
1. These images were taken six months apart, first when Earth was as far to one side of Alpha Centauri as it can get and again when Earth was as far to the other side of Alpha Centauri as it can get. Consequently, the baseline between the two observing positions is how many AU across? Answer: 1.7 arcsec
USE 1.7 arcsec NOT 2.946
2. First, convert this to kilometers using your measurement of how many kilometers are in an AU.
3. Now convert the baseline to kilometers using the true value for the number of kilometers in an AU.
4. Calculate the distance to Alpha Centauri using parallax and the true baseline in kilometers.
5. Google and record the true value.
6. Calculate your percent error
7. Discuss significant sources of error
Gusts of the solar wind travel as fast as 1000 km/s. How many days would the solar wind take to reach Earth at this speed? (Note: The average distance to the Sun is 1.496 ✕ 108 km.)
Chapter 8 Solutions
FOUNDATIONS OF ASTRONOMY (LL)-W/MINDTAP
Ch. 8 - Prob. 1RQCh. 8 - Prob. 2RQCh. 8 - Prob. 3RQCh. 8 - Prob. 4RQCh. 8 - Prob. 5RQCh. 8 - Prob. 6RQCh. 8 - What evidence can you give that granulation is...Ch. 8 - Prob. 8RQCh. 8 - Prob. 9RQCh. 8 - Prob. 10RQ
Ch. 8 - Prob. 11RQCh. 8 - Prob. 12RQCh. 8 - Prob. 13RQCh. 8 - Prob. 14RQCh. 8 - Energy can be transported by convection,...Ch. 8 - Prob. 16RQCh. 8 - Prob. 17RQCh. 8 - Prob. 18RQCh. 8 - Prob. 19RQCh. 8 - Meridional is derived from meridian. Look up the...Ch. 8 - Prob. 21RQCh. 8 - Prob. 22RQCh. 8 - How can solar flares affect Earth?Ch. 8 - Prob. 24RQCh. 8 - Why does nuclear fusion require high temperatures...Ch. 8 - Prob. 26RQCh. 8 - Four protons are combined in the proton-proton...Ch. 8 - Give an example of a charged subatomic particle...Ch. 8 - Prob. 29RQCh. 8 - Prob. 30RQCh. 8 - Prob. 31RQCh. 8 - Prob. 32RQCh. 8 - Prob. 33RQCh. 8 - The radius of the Sun is 0.7 million km. What...Ch. 8 - Prob. 2PCh. 8 - Prob. 3PCh. 8 - What is the angular diameter of a star the same...Ch. 8 - If a sunspot has a temperature of 4200 K and the...Ch. 8 - How many watts of radiation does a 1-meter-square...Ch. 8 - If a sunspot has a temperature of 4200 K and the...Ch. 8 - Prob. 8PCh. 8 - Prob. 9PCh. 8 - Prob. 10PCh. 8 - Prob. 11PCh. 8 - Prob. 12PCh. 8 - Prob. 13PCh. 8 - Prob. 14PCh. 8 - The United States consumes about 2.5 1019 J of...Ch. 8 - Prob. 16PCh. 8 - Prob. 1SOPCh. 8 - Prob. 2SOPCh. 8 - Whenever there is a total solar eclipse, you can...Ch. 8 - Prob. 2LTLCh. 8 - Prob. 3LTLCh. 8 - Prob. 4LTLCh. 8 - The two images here show two solar phenomena. What...Ch. 8 - Prob. 6LTL
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- If each square cm of the sun's surface radiates energy at the rate of 1.5x 103 cal/s/cm? and Stefan's constant is 5.7 x 108 J-s/m? K-4, calculate the temperature of the sun's surface in degree centigrade.arrow_forwardCan you answer the question?arrow_forwardIf there were a planet about 9 times as far from the Sun as Earth is, what would its solar constant be? The solar constant of the Earth is 1350 watts per square meter. This question is not multiple choice. Provide an answer that is in watts per square meter (round to the nearest 10 watts per square meter).arrow_forward
- Considering that Earth experiences an average intensity of sunlight of 1330 W/m? and is at a distance from the Sun of 1.0 AU = 150 million km, and considering that that the apparent magnitude of the Sun as seen from Earth is m = -26.7, (a) then how far from the Sun would a distant Kuiper- belt world need to be in order for the apparent magnitude of the Sun to be m = -11.0 as seen on that world? Give your answer in AU. (b) What would be the orbital period of this world? Give your answer in Earth years.arrow_forwardA distant galaxy has an apparent magnitude of 13 and is 5,000 kpc away. What is its absolute magnitude? (Round your answer to at least one decimal place.) The difference in absolute magnitude between two objects viewed from the same distance is related to their fluxes by the flux-magnitude relation. FA = 2.51(MB - MA) FB How does the absolute magnitude of this galaxy compare to the Milky Way (M = -21)? F, distant galaxy FMilky Wayarrow_forward1. These images were taken six months apart, first when Earth was as far to one side of Alpha Centauri as it can get and again when Earth was as far to the other side of Alpha Centauri as it can get. Consequently, the baseline between the two observing positions is how many AU across? Answer: 1.7 arcsec 2. First, convert this to kilometers using your measurement of how many kilometers are in an AU. 3. Now convert the baseline to kilometers using the true value for the number of kilometers in an AU. 4. Calculate the distance to Alpha Centauri using parallax and the true baseline in kilometers. 5. Google and record the true value. 6. Calculate your percent error 7. Discuss significant sources of errorarrow_forward
- Q1arrow_forwardNext you will (1) convert your measurement of the semi-major axis from arcseconds to AU, (2) convert your measurement of the period from days to years, and (3) calculate the mass of the planet using Newton's form of Kepler's Third Law. Use Stellarium to find the distance to the planet when Skynet took any of your images, in AU. Answer: 4.322 AU Use this equation to determine a conversion factor from 1 arcsecond to AU at the planet's distance. You will need to convert ? = 1 arcsecond to degrees first. Answer: 2.096e-5 AU (2 x 3.14 x 4.322 x (.000278/360) = 2.096e-5) Next, use this number to convert your measurement of the moon's orbital semi-major axis from arcseconds to AU. A) Calculate a in AU. B) Convert your measurement of the moon's orbital period from days to years. C) By Newton's form of Kepler's third law, calculate the mass of the planet. D) Finally, convert the planet's mass to Earth masses: 1 solar mass = 333,000 Earth masses.arrow_forwardDo the previous problem again, this time using the information that the Sun is 150,000,000 km away. You will get a very large number of km as your answer. To get a better feeling for how the distances compare, try calculating the time it takes light at a speed of 299,338 km/s to travel from the Sun to Earth and from Alpha Centauri to Earth. For Alpha Centauri, figure out how long the trip will take in years as well as in seconds.arrow_forward
- Which of the planets in our solar system have orbits that are smaller than the photospheric radius of Betelgeuse listed in in Table 22.2?arrow_forwardDuring a solar cycle, how long does it take (on average) for the Sun's magnetic field polarity to return to its original configuration? Provide your answer in years. On average, it takes: _____ years.arrow_forwardUsing a 8-m reflector telescope on Mars, what is the maximum distance we could measure using stellar parallax?arrow_forward
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