Physics for Scientists and Engineers
Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 8, Problem 58P
To determine

The velocity of each block after the collision.

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A 3.6 kg block moving with a velocity of +4.3 m/s makes an elastic collision with a stationary block of mass 2.5 kg. (a) Use conservation of momentum and the fact that the relative speed of recession equals the relative speed of approach to find the velocity of each block after the collision.   I'm having a hard time calculating using the cinservation of momentum, please explain steps.
For the same collision as above, motion sensors record the velocities as a function of time for both carts. The graph of this function for the heavier cart is this: 2 t What qualities can we expect to see for a graph of velocity vs. time coming from the motion sensor recording the lighter cart's motion during the same collision? [Note: In our lab, the motion sensors are looking at their respective carts from opposite directions, so the positive direction for one sensor is the negative direction for the other, but for the purposes of this question, we will assume that the sensors agree upon the positive direction .] O The graph goes no higher than dotted line #2. The graph crosses dotted line #2, but goes no higher than dotted line #1. The graph crosses both dotted lines. There is not enough information to determine whether the graph crosses either dotted line.
Problem No.2 - A bullet which has velocity 150 m/s and mass 4 kg sticks to the stationary block. They move together after collision. the h Voule=150m/s Find the height they have O Copyrigh www.physic Mbulet=200g mblock=4kg after the collision.

Chapter 8 Solutions

Physics for Scientists and Engineers

Ch. 8 - Prob. 11PCh. 8 - Prob. 12PCh. 8 - Prob. 13PCh. 8 - Prob. 14PCh. 8 - Prob. 15PCh. 8 - Prob. 16PCh. 8 - Prob. 17PCh. 8 - Prob. 18PCh. 8 - Prob. 19PCh. 8 - Prob. 20PCh. 8 - Prob. 21PCh. 8 - Prob. 22PCh. 8 - Prob. 23PCh. 8 - Prob. 24PCh. 8 - Prob. 25PCh. 8 - Prob. 26PCh. 8 - Prob. 27PCh. 8 - Prob. 28PCh. 8 - Prob. 29PCh. 8 - Prob. 30PCh. 8 - Prob. 31PCh. 8 - Prob. 32PCh. 8 - Prob. 33PCh. 8 - Prob. 34PCh. 8 - Prob. 35PCh. 8 - Prob. 36PCh. 8 - Prob. 37PCh. 8 - Prob. 38PCh. 8 - Prob. 39PCh. 8 - Prob. 40PCh. 8 - Prob. 41PCh. 8 - Prob. 42PCh. 8 - Prob. 43PCh. 8 - Prob. 44PCh. 8 - Prob. 45PCh. 8 - Prob. 46PCh. 8 - Prob. 47PCh. 8 - Prob. 48PCh. 8 - Prob. 49PCh. 8 - Prob. 50PCh. 8 - Prob. 51PCh. 8 - Prob. 52PCh. 8 - Prob. 53PCh. 8 - Prob. 54PCh. 8 - Prob. 55PCh. 8 - Prob. 56PCh. 8 - Prob. 57PCh. 8 - Prob. 58PCh. 8 - Prob. 59PCh. 8 - Prob. 60PCh. 8 - Prob. 61PCh. 8 - Prob. 62PCh. 8 - Prob. 63PCh. 8 - Prob. 64PCh. 8 - Prob. 65PCh. 8 - Prob. 66PCh. 8 - Prob. 67PCh. 8 - Prob. 68PCh. 8 - Prob. 69PCh. 8 - Prob. 70PCh. 8 - Prob. 71PCh. 8 - Prob. 72PCh. 8 - Prob. 73PCh. 8 - Prob. 74PCh. 8 - Prob. 75PCh. 8 - Prob. 76PCh. 8 - Prob. 77PCh. 8 - Prob. 78PCh. 8 - Prob. 79PCh. 8 - Prob. 80PCh. 8 - Prob. 81PCh. 8 - Prob. 82PCh. 8 - Prob. 83PCh. 8 - Prob. 84PCh. 8 - Prob. 85PCh. 8 - Prob. 86PCh. 8 - Prob. 87PCh. 8 - Prob. 88PCh. 8 - Prob. 89PCh. 8 - Prob. 90PCh. 8 - Prob. 91PCh. 8 - Prob. 92PCh. 8 - Prob. 93PCh. 8 - Prob. 94PCh. 8 - Prob. 95PCh. 8 - Prob. 96PCh. 8 - Prob. 98PCh. 8 - Prob. 99PCh. 8 - Prob. 100PCh. 8 - Prob. 101PCh. 8 - Prob. 102PCh. 8 - Prob. 103PCh. 8 - Prob. 104PCh. 8 - Prob. 105PCh. 8 - Prob. 106PCh. 8 - Prob. 107PCh. 8 - Prob. 108PCh. 8 - Prob. 109PCh. 8 - Prob. 110PCh. 8 - Prob. 111PCh. 8 - Prob. 112PCh. 8 - Prob. 113PCh. 8 - Prob. 114PCh. 8 - Prob. 115PCh. 8 - Prob. 116PCh. 8 - Prob. 117P
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Impulse Derivation and Demonstration; Author: Flipping Physics;https://www.youtube.com/watch?v=9rwkTnTOB0s;License: Standard YouTube License, CC-BY