GENERAL,ORGANIC,+BIOLOG.CHEM. (LOOSE)
GENERAL,ORGANIC,+BIOLOG.CHEM. (LOOSE)
4th Edition
ISBN: 9781260194777
Author: SMITH
Publisher: MCG
Question
Book Icon
Chapter 8, Problem 73P
Interpretation Introduction

(a)

Interpretation:

The weight/volume percent concentration of vitamin C solution that has been diluted from 100 mL to 200 mL is to be calculated.

Concept introduction:

Several concentration units may be used to express the concentration. It is often useful to express the concentration in terms of percentage. This can be expressed as the amount of solute in grams dissolved in 100 mL of solution that is termed as weight by volume percentage. This is useful to express the concentration of solid solutes. The other way is to express the number of milliliters of solute per 100 mL of the solution. This is called the volume /volume percentage which is useful to express the concentrations of liquid solutes.

The formula to calculate the weight/volume percent is as follows:

  Weight/volume percent(mv)%=Mass of solute(g)Volume of solution(mL)×100%

The dilution formula is given as follows:

  C1V1=C2V2

Expert Solution
Check Mark

Answer to Problem 73P

The weight/volume percent concentration of vitamin C solution that has been diluted from 100 mL to 200 mL is 15 %.

Explanation of Solution

The dilution formula is given as follows:

  C1V1=C2V2

Where,

  • C1denotes the initial concentration before dilution.
  • V1denotes the initial volume of solution.
  • C2denotes the final concentration after dilution.
  • V2 denotes the final volume of solution.

Initial volume is given as 100 mL.

Initial weight/volume percent concentration is given as 30 %.

Final volume after dilution is given as 200 mL.

Final weight/volume percent concentration is to be calculated.

Substitute the values in the formula above.

  C1V1=C2V2(30 %)(100 mL)=C2(200 mL)

Rearrange the above expression to calculate the finalweight/volume percent concentrationof vitamin C.

  C2=( 30 %)( 100 mL)( 200 mL)=15 %

Interpretation Introduction

(b)

Interpretation:

The weight/volume percent concentration of vitamin C solution that has been diluted from 100 mL to 500 mL is to be calculated.

Concept introduction:

Several concentration units may be used to express the concentration. It is often useful to express the concentration in terms of percentage. This can be expressed as the amount of solute in grams dissolved in 100 mL of solution that is termed as weight by volume percentage. This is useful to express the concentration of solid solutes. The other way is to express the number of milliliters of solute per 100 mL of the solution. This is called the volume /volume percentage which is useful to express the concentrations of liquid solutes.

The formula to calculate the weight/volume percent is as follows:

  Weight/volume percent(mv)%=Mass of solute(g)Volume of solution(mL)×100%

The dilution formula is given as follows:

  C1V1=C2V2

Expert Solution
Check Mark

Answer to Problem 73P

The weight/volume percent concentration of vitamin C solution that has been diluted from 100 mL to 500 mL is 6 %.

Explanation of Solution

The dilution formula is given as follows:

  C1V1=C2V2

Where,

  • C1denotes the initial concentration before dilution.
  • V1denotes the initial volume of solution.
  • C2denotes the final concentration after dilution.
  • V2 denotes the final volume of solution.

Initial volume is given as 100 mL.

Initial weight/volume percent concentration is given as 30 %.

Final volume after dilution is given as 500 mL.

Final weight/volume percent concentration is to be calculated.

Substitute the values in above formula.

  C1V1=C2V2(30 %)(100 mL)=C2(500 mL)

Rearrange the above expression to calculate the finalweight/volume percent concentrationof vitamin C.

  C2=( 30 %)( 100 mL)( 500 mL)=6 %

Interpretation Introduction

(c)

Interpretation:

The weight/volume percent concentration of vitamin C solution that has been diluted from 250 mL to 1.5 L is to be calculated.

Concept introduction:

Several concentration units may be used to express the concentration. It is often useful to express the concentration in terms of percentage. This can be expressed as the amount of solute in grams dissolved in 100 mL of solution that is termed as weight by volume percentage. This is useful to express the concentration of solid solutes. The other way is to express the number of milliliters of solute per 100 mL of the solution. This is called the volume /volume percentage which is useful to express the concentrations of liquid solutes.

The formula to calculate the weight/volume percent is as follows:

  Weight/volume percent concentration(mv)%=Mass of solute(g)Volume of solution(mL)×100%

The dilution formula is given as follows:

  C1V1=C2V2

The conversion factor to convert the liters to milliliters is as follows:

  1 L=1000 mL

Expert Solution
Check Mark

Answer to Problem 73P

The weight/volume percent concentration of vitamin C solution that has been diluted from 250 mL to 1.5 L is 5 %.

Explanation of Solution

The conversion factor to convert the liters to milliliters is as follows:

  1 L=1000 mL

Hence, convert the volume in liters to milliliters as follows:

  Volume(mL)=(1.5 L)( 1000 mL 1 L)=1500 mL

The dilution formula is given as follows:

  C1V1=C2V2

Where,

  • C1denotes the initial concentration before dilution.
  • V1denotes the initial volume of solution.
  • C2denotes the final concentration after dilution.
  • V2 denotes the final volume of solution.

Initial volume is given as 250 mL.

Initial weight/volume percent concentration is given as 30 %.

Final volume after dilution is given as 1500 mL.

Final weight/volume percent concentration is to be calculated.

Substitute the values in above formula.

  C1V1=C2V2(30 %)(250 mL)=C2(1500 mL)

Rearrange the above expression to calculate the finalweight/volume percent concentrationof vitamin C.

  C2=( 30 %)( 250 mL)( 1500 mL)=5 %

Interpretation Introduction

(d)

Interpretation:

The weight/volume percent concentration of vitamin C solution that has been diluted from 0.35 L to 750 mL is to be calculated.

Concept introduction:

Several concentration units may be used to express the concentration. It is often useful to express the concentration in terms of percentage. This can be expressed as the amount of solute in grams dissolved in 100 mL of solution that is termed as weight by volume percentage. This is useful to express the concentration of solid solutes. The other way is to express the number of milliliters of solute per 100 mL of the solution. This is called the volume /volume percentage which is useful to express the concentrations of liquid solutes.

The formula to calculate the weight/volume percent is as follows:

  Weight/volume percent concentration(mv)%=Mass of solute(g)Volume of solution(mL)×100%

The dilution formula is given as follows:

  C1V1=C2V2

Expert Solution
Check Mark

Answer to Problem 73P

The weight/volume percent concentration of vitamin C solution that has been diluted from 0.35 L to 750 mL is 14 %.

Explanation of Solution

The conversion factor to convert the liters to milliliters is as follows:

  1 L=1000 mL

Hence convert the volume in liters to milliliters as follows:

  Volume(mL)=(0.35 L)( 1000 mL 1 L)=350 mL

The dilution formula is given as follows:

  C1V1=C2V2

Where,

  • C1denotes the initial concentration before dilution.
  • V1denotes the initial volume of solution.
  • C2denotes the final concentration after dilution.
  • V2 denotes the final volume of solution.

Initial volume is 350 mL.

Initial weight/volume percent concentration is given as 30 %.

Final volume after dilution is given as 750 mL.

Final weight/volume percent concentration is to be calculated.

Substitute the values in above formula.

  C1V1=C2V2(30 %)(350 mL)=C2(750 mL)

Rearrange the above expression to calculate the finalweight/volume percent concentrationof vitamin C.

  C2=( 30 %)( 350 mL)( 750 mL)=14 %

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 8 Solutions

GENERAL,ORGANIC,+BIOLOG.CHEM. (LOOSE)

Ch. 8.3 - Use the solubility rules to predict whether the...Ch. 8.3 - Use the solubility rules for ionic compounds to...Ch. 8.4 - Why does a soft drink become "flat" faster when it...Ch. 8.4 - Predict the effect each change has on the...Ch. 8.5 - A commercial mouthwash contains 4.3 g of ethanol...Ch. 8.5 - What is the weight/volume percent concentration of...Ch. 8.5 - Prob. 8.6PPCh. 8.5 - Prob. 8.7PPCh. 8.5 - A drink sold in a health food store contains 0.50%...Ch. 8.5 - Prob. 8.12PCh. 8.5 - What is the concentration in parts per million of...Ch. 8.6 - Prob. 8.10PPCh. 8.6 - Prob. 8.13PCh. 8.6 - Prob. 8.11PPCh. 8.6 - Prob. 8.12PPCh. 8.6 - How many grams of NaCl are contained in each of...Ch. 8.6 - How many milliliters of a 0.25 M sucrose solution...Ch. 8.7 - What is the concentration of a solution formed by...Ch. 8.7 - If the solution of A+B- in X is diluted, which...Ch. 8.7 - Prob. 8.15PPCh. 8.7 - Prob. 8.16PCh. 8.8 - What is the boiling point of a solution prepared...Ch. 8.8 - Representations A, B, and C each show an aqueous...Ch. 8.8 - Prob. 8.18PPCh. 8.8 - What is the melting point of a solution that is...Ch. 8.9 - Which solution in each pair exerts the greater...Ch. 8.9 - Prob. 8.19PCh. 8.9 - Consider the two aqueous solutions separated by a...Ch. 8.9 - What happens to a red blood cell when it is placed...Ch. 8 - Prob. 21PCh. 8 - Prob. 22PCh. 8 - Prob. 23PCh. 8 - Which representation of molecular art better shows...Ch. 8 - Classify each of the following as a solution,...Ch. 8 - Classify each of the following as a solution,...Ch. 8 - Prob. 27PCh. 8 - Label each diagram as a strong electrolyte, weak...Ch. 8 - Prob. 29PCh. 8 - Prob. 30PCh. 8 - Prob. 31PCh. 8 - Prob. 32PCh. 8 - Consider a mixture of two substances shown in blue...Ch. 8 - Which diagram (C or D) best represents what occurs...Ch. 8 - If the solubilityofKClin 100 mL of H2O is 34 g at...Ch. 8 - If the solubilityofsucrosein 100 mL of H2O is 204...Ch. 8 - Prob. 37PCh. 8 - Prob. 38PCh. 8 - Using the ball-and-stick model for methanol...Ch. 8 - Prob. 40PCh. 8 - Prob. 41PCh. 8 - Prob. 42PCh. 8 - Prob. 43PCh. 8 - Prob. 44PCh. 8 - Prob. 45PCh. 8 - Prob. 46PCh. 8 - Prob. 47PCh. 8 - How is the solubility of helium gas in water...Ch. 8 - Use the solubility rules listed in Section 8.3B to...Ch. 8 - Use the solubility rules listed in Section 8.3B to...Ch. 8 - Prob. 51PCh. 8 - Prob. 52PCh. 8 - Prob. 53PCh. 8 - Prob. 54PCh. 8 - Prob. 55PCh. 8 - Prob. 56PCh. 8 - Prob. 57PCh. 8 - Prob. 58PCh. 8 - How would you use a 250-mL volumetric flask to...Ch. 8 - How would you use a 250-mLvolumetric flask to...Ch. 8 - Prob. 61PCh. 8 - Prob. 62PCh. 8 - Prob. 63PCh. 8 - Prob. 64PCh. 8 - Prob. 65PCh. 8 - What is the molarity of a 20.0% (v/v) aqueous...Ch. 8 - Prob. 67PCh. 8 - Prob. 68PCh. 8 - Prob. 69PCh. 8 - Prob. 70PCh. 8 - Prob. 71PCh. 8 - Prob. 72PCh. 8 - Prob. 73PCh. 8 - Prob. 74PCh. 8 - Prob. 75PCh. 8 - Prob. 76PCh. 8 - Prob. 77PCh. 8 - Representations A (containing 1.0 mol ofNaCl) and...Ch. 8 - What is the boiling point of a solution that...Ch. 8 - Prob. 80PCh. 8 - If 150 g of ethylene glycol (C2H6O2) is added to...Ch. 8 - Prob. 82PCh. 8 - Prob. 83PCh. 8 - Prob. 84PCh. 8 - Which solution in each pair has the higher melting...Ch. 8 - Prob. 86PCh. 8 - A flask contains two compartments (A and B) with...Ch. 8 - A flask contains two compartments (A and B) with...Ch. 8 - The molecular art illustrates a red blood cell in...Ch. 8 - Prob. 90PCh. 8 - Prob. 91PCh. 8 - Explain why more sugar dissolves in a cup of hot...Ch. 8 - If the concentration of glucose in the blood is...Ch. 8 - Prob. 94PCh. 8 - Mannitol, a carbohydrate, is supplied as a 25%...Ch. 8 - A patient receives 750 ml, of a 10.% (w/v) aqueous...Ch. 8 - Explain why a cucumber placed in a concentrated...Ch. 8 - Explain why a cucumber placed in a concentrated...Ch. 8 - Prob. 99PCh. 8 - Prob. 100PCh. 8 - Prob. 101PCh. 8 - Prob. 102PCh. 8 - The therapeutic concentration—the concentration...Ch. 8 - Prob. 104CP
Knowledge Booster
Background pattern image
Recommended textbooks for you
Text book image
General, Organic, and Biological Chemistry
Chemistry
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:Cengage Learning
Text book image
Introductory Chemistry For Today
Chemistry
ISBN:9781285644561
Author:Seager
Publisher:Cengage
Text book image
Chemistry: Matter and Change
Chemistry
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Glencoe/McGraw-Hill School Pub Co
Text book image
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning
Text book image
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Text book image
Fundamentals Of Analytical Chemistry
Chemistry
ISBN:9781285640686
Author:Skoog
Publisher:Cengage