Concept explainers
Nitrous oxide (N2O) is also called “laughing gas.” It can be prepared by the thermal decomposition of ammonium nitrate (NH4NO3). The other product is H2O. (a) Write a balanced equation for this reaction, (b) How many grams of N2O are formed if 0.46 mole of NH4NO3 is used in the reaction?
(a)
Interpretation: Balanced equation of ammonium nitrate decomposition and the amount of
Concept introduction:
Balanced chemical equation: The mass of products should be equal to mass of its starting materials this is governed by law of conservation of mass.
In the above reaction 2 nitrogen atoms are there in reactant side but 1 nitrogen in product side, likewise 2 hydrogen’s in reactant side but 3 hydrogen’s in product side so this is unbalanced equation by putting coefficients for each elements in both sides we can balance this reaction as follows:
To write: Balanced chemical equation of
Answer to Problem 8.37QP
Balanced equation for ammonium nitrate decomposition is given below
Explanation of Solution
The mass of products should be equal to mass of its starting materials this is governed by law of conservation of mass this equation is known as balanced chemical equation.
Decomposition of ammonium nitrate:
Starting material: ammonium nitrate
Products:
We can write this chemical reaction as follows:
Above one is an unbalanced equation because the number of hydrogen and oxygen in starting material and products are not equal. So this equation balanced by putting coefficients to corresponding elements as follows:
(b)
Interpretation: Balanced equation of ammonium nitrate decomposition and the amount of
Concept introduction:
Balanced chemical equation: The mass of products should be equal to mass of its starting materials this is governed by law of conservation of mass.
In the above reaction 2 nitrogen atoms are there in reactant side but 1 nitrogen in product side, likewise 2 hydrogen’s in reactant side but 3 hydrogen’s in product side so this is unbalanced equation by putting coefficients for each elements in both sides we can balance this reaction as follows:
To calculate: The amount of
Answer to Problem 8.37QP
The amount of
Explanation of Solution
The above balanced equation shows 1 mole of
Molar mass of
Molar mass of
Moles to gram conversion of
Production of
The amount of
Balanced equation of ammonium nitrate decomposition and the amount of
(a) Balanced equation for ammonium nitrate decomposition is given below
(b) The amount of
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