Chapter 8, Problem 8.40PP

Summary Introduction

To determine:

The volume of $0.45\%$ $\text{KCl}$ in $\text{mL}$ that can be prepared from $500\text{mL}$ of a $9.0\%$ stock solution.

Introduction:

In the case of solid solute it is convenient to express its concentration in mass/volume $\left(\text{m/v}\right)$. The concentration is expressed as,

$\text{m/v}\text{\%}=\frac{\text{Mass}\text{of}\text{solute}\left(g\right)}{\text{Volume}\text{of}\text{solution}}\times 100$

The dilution equation that relates the volumes of solute and solution with the concentrations $\left(\text{m/v}\text{\%}\right)$ of solute and solution is expressed as,

$C_{\text{initial}}\times V_{\text{initial}}=C_{\text{Final}}\times V_{\text{Final}}$