Chapter 8, Problem 8.44E

Interpretation Introduction

(a)

Interpretation:

The reaction equation that corresponds to each of the given equilibrium expression is to be stated.

Concept introduction:

When any reaction is at equilibrium then a constant expresses a relationship between the reactant side and the product side. This constant is known as equilibrium constant. It is denoted by $K$. The equilibrium constant is independent of the initial amount of the reactant and product.

Answer to Problem 8.44E

The reaction equation that corresponds to given equilibrium expression is ${\text{CH}}_4+2{\text{O}}_{\text{2}}\rightleftarrows {\text{CO}}_{\text{2}}+2{\text{H}}_{\text{2}}\text{O}$.

Explanation of Solution

The value of equilibrium constant is equal to the product of the concentration of the products raised to the power of their stoichiometric coefficient divided by product of the concentration of reactants raised to the power of their stoichiometric coefficient in chemical equation.

The given equilibrium expression is shown below.

$K=\frac{\left[{\text{CO}}_{\text{2}}\right]{\left[{\text{H}}_{\text{2}}\text{O}\right]}^2}{\left[{\text{CH}}_4\right]{\left[{\text{O}}_{\text{2}}\right]}^2}$

Thus, the coefficient of ${\text{CO}}_{\text{2}}$ is one, ${\text{H}}_{\text{2}}\text{O}$ is two, ${\text{CH}}_4$ is one and ${\text{O}}_{\text{2}}$ is two. The reaction equation is shown below.

${\text{CH}}_4+2{\text{O}}_{\text{2}}\rightleftarrows {\text{CO}}_{\text{2}}+2{\text{H}}_{\text{2}}\text{O}$

Conclusion

The reaction equation that corresponds to given equilibrium expression is ${\text{CH}}_4+2{\text{O}}_{\text{2}}\rightleftarrows {\text{CO}}_{\text{2}}+2{\text{H}}_{\text{2}}\text{O}$.

Interpretation Introduction

(b)

Interpretation:

The reaction equation that corresponds to each of the given equilibrium expression is to be stated.

Concept introduction:

When any reaction is at equilibrium then a constant expresses a relationship between the reactant side and the product side. This constant is known as equilibrium constant. It is denoted by $K$. The equilibrium constant is independent of the initial amount of the reactant and product.

Answer to Problem 8.44E

The reaction equation that corresponds to given equilibrium expression is ${\text{3H}}_{\text{2}}+\text{CO}\rightleftarrows {\text{CH}}_4+{\text{H}}_{\text{2}}\text{O}$.

Explanation of Solution

The value of equilibrium constant is equal to the product of the concentration of the products raised to the power of their stoichiometric coefficient divided by product of the concentration of reactants raised to the power of their stoichiometric coefficient in chemical equation.

The given equilibrium expression is shown below.

$K=\frac{\left[{\text{CH}}_4\right]\left[{\text{H}}_{\text{2}}\text{O}\right]}{{\left[{\text{H}}_{\text{2}}\right]}^3\left[\text{CO}\right]}$

Thus, the coefficient of ${\text{CH}}_4$ is one, ${\text{H}}_{\text{2}}\text{O}$ is one, $\text{CO}$ is one and ${\text{H}}_{\text{2}}$ is three. The reaction equation is shown below.

${\text{3H}}_{\text{2}}+\text{CO}\rightleftarrows {\text{CH}}_4+{\text{H}}_{\text{2}}\text{O}$

Conclusion

The reaction equation that corresponds to given equilibrium expression is ${\text{3H}}_{\text{2}}+\text{CO}\rightleftarrows {\text{CH}}_4+{\text{H}}_{\text{2}}\text{O}$.

Interpretation Introduction

(c)

Interpretation:

The reaction equation that corresponds to each of the given equilibrium expression is to be stated.

Concept introduction:

When any reaction is at equilibrium then a constant expresses a relationship between the reactant side and the product side. This constant is known as equilibrium constant. It is denoted by $K$. The equilibrium constant is independent of the initial amount of the reactant and product.

Answer to Problem 8.44E

The reaction equation that corresponds to given equilibrium expression is ${\text{2O}}_3\rightleftarrows 3{\text{O}}_2$.

Explanation of Solution

The value of equilibrium constant is equal to the product of the concentration of the products raised to the power of their stoichiometric coefficient divided by product of the concentration of reactants raised to the power of their stoichiometric coefficient in chemical equation.

The given equilibrium expression is shown below.

$K=\frac{{\left[{\text{O}}_2\right]}^3}{{\left[{\text{O}}_3\right]}^2}$

Thus, the coefficient of ${\text{O}}_2$ is three and ${\text{O}}_3$ is two. The reaction equation is shown below.

${\text{2O}}_3\rightleftarrows 3{\text{O}}_2$

Conclusion

The reaction equation that corresponds to given equilibrium expression is ${\text{2O}}_3\rightleftarrows 3{\text{O}}_2$.

Interpretation Introduction

(d)

Interpretation:

The reaction equation that corresponds to each of the given equilibrium expression is to be stated.

Concept introduction:

When any reaction is at equilibrium then a constant expresses a relationship between the reactant side and the product side. This constant is known as equilibrium constant. It is denoted by $K$. The equilibrium constant is independent of the initial amount of the reactant and product.

Answer to Problem 8.44E

The reaction equation that corresponds to given equilibrium expression is ${\text{4NO}}_{\text{2}}+6{\text{H}}_2\text{O}\rightleftarrows 4{\text{NH}}_3+7{\text{O}}_{\text{2}}$.

Explanation of Solution

The value of equilibrium constant is equal to the product of the concentration of the products raised to the power of their stoichiometric coefficient divided by product of the concentration of reactants raised to the power of their stoichiometric coefficient in chemical equation.

The given equilibrium expression is shown below.

$K=\frac{{\left[{\text{NH}}_3\right]}^4{\left[{\text{O}}_{\text{2}}\right]}^7}{{\left[{\text{NO}}_{\text{2}}\right]}^4{\left[{\text{H}}_2\text{O}\right]}^6}$

Thus, the coefficient of ${\text{NH}}_3$ is four, ${\text{O}}_{\text{2}}$ is seven, ${\text{H}}_{\text{2}}\text{O}$ is six and ${\text{NO}}_{\text{2}}$ is four. The reaction equation is shown below.

${\text{4NO}}_{\text{2}}+6{\text{H}}_2\text{O}\rightleftarrows 4{\text{NH}}_3+7{\text{O}}_{\text{2}}$

Conclusion

The reaction equation that corresponds to given equilibrium expression is ${\text{4NO}}_{\text{2}}+6{\text{H}}_2\text{O}\rightleftarrows 4{\text{NH}}_3+7{\text{O}}_{\text{2}}$.