Microbiology With Diseases By Taxonomy (6th Edition)
6th Edition
ISBN: 9780134832302
Author: Robert W. Bauman Ph.D.
Publisher: PEARSON
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Chapter 8, Problem 9CT
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Describe how you would use replica plating of mutagenized, haploid yeast cells to identify temperature-sensitive (ts) mutations in essential genes needed for yeast growth and survival.
An integrated gene X inserted into the yeast genome near a telomere. Will this strategy result in the good expression of gene X? If not then why?
If you wanted to express a library of human proteins in yeast, there are several good reasons why it would be better to use a cDNA library instead of a genomic library from humans. Which one of the following options is not such a reason?
a. yeast may not initiate transcription or splicing of a human gene at the correct locations
b. some genes will have very high representation (many plasmids contain the gene), while others will have very low representation (few or no plasmids contain the gene) in the cDNA library
c. most genomic library clones would be useless, because only ~1.5% of the human genome actually encodes proteins
d. a cDNA library can contain multiple splice variants, which are common for human genes
e. introns are often very large in the human genome, making it impossible in many cases to contain a genomic version of an entire gene in a single plasmid
Chapter 8 Solutions
Microbiology With Diseases By Taxonomy (6th Edition)
Ch. 8 - Why did the discovery and development of...Ch. 8 - Why wasnt polymerase chain reaction (PCR)...Ch. 8 - Why dont doctors routinely insert genes into their...Ch. 8 - Why dont scientists who work with recombinant DNA...Ch. 8 - Which of the following statements is true...Ch. 8 - A DNA gene synthesized from an RNA template is...Ch. 8 - Prob. 3MCCh. 8 - Prob. 4MCCh. 8 - Prob. 5MCCh. 8 - Prob. 7MC
Ch. 8 - Prob. 9MCCh. 8 - Prob. 10MCCh. 8 - Prob. 1MTFCh. 8 - Prob. 2MTFCh. 8 - Prob. 3MTFCh. 8 - ________ Protoplast fusion is often used in the...Ch. 8 - Prob. 5MTFCh. 8 - Describe three artificial methods of introducing...Ch. 8 - Prob. 2SACh. 8 - Prob. 3SACh. 8 - List three potential problems of recombinant DNA...Ch. 8 - Examine the restriction sites listed in Table 8.1...Ch. 8 - Prob. 2CTCh. 8 - A thermocycler uses DNA polymerase from...Ch. 8 - How is the result of a Southern blot similar to...Ch. 8 - Prob. 6CTCh. 8 - Prob. 8CTCh. 8 - Prob. 9CTCh. 8 - Using the following terms, fill in the following...
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- You want to clone a eukaryotic gene and express the corresponding protein in yeast. However, the protein typically localizes within mitochondria. How will you perform your gene cloning so that the protein is secreted from the cell, rather than localized within yeast mitochondria?arrow_forwardWhat percentage of the DNA sites in yeast are accessible, assuming that the fraction of sites observed for GAL4 is typical? To how many base pairs of the 12-Mb yeast genome does this percentage correspond?arrow_forwardthe forward primer used in this experiment incorporates part of the cell recognition site, GGCC. How is this different from the sequence of the human TAS2R38 gene? What characteristic of this PCR reaction allows the primer sequence to override the natural gene sequence? Draw a diagram to support your contention.arrow_forward
- Below is a portion of an exon from a gene that encodes protein Y in the genome of the plant Brassica. Wildtype DNA3’ CTT AAT GCT CCG AAT CCA 5’ template strand5’ GAA TTA CGA GGC TTA GGT 3’ non-template strand A new strain (Strain X) of Brassica is identified with the same region of the gene coding for protein Y:3’ CTT AAT GCT GCG AAT CCA 5’ template strand5’ GAA TTA CGA CGC TTA GGT 3’ non-template strand Compare the sequence of Wildtype with Strain X DNA, and note the following: Whether there is a mutation. If there is a mutation, what is the type of mutation (be as specific as possible) and explain the rationale for your decision. Assuming this is the only difference between the Wildtype and Strain X, describe the potential impact of the mutation on the structure and function of the protein.arrow_forwardDiscuss how ultra violet light works as a mutagen. This could include: What is UV light and the Mutations commonly introduced by UV light? What are the Repair mechanisms in yeast that fix damage caused by UV light? Describe the phenotypes of Saccharomyces Cerevisiae plates, the first plate is the control yeast, while the second plate has been exposed to low UV light, the third plate has been exposed to high UV light. Normal yeast has round smooth white colonies. Are there any signinifcant differences?arrow_forwardThe DNA sequence of one strand of a gene from threeindependently isolated mutants is given here (5′ endsare at left). Using this information, what is the sequence of the wild-type gene in this region?mutant 1 ACCGTAATCGACTGGTAAACTTTGCGCGmutant 2 ACCGTAGTCGACCGGTAAACTTTGCGCGmutant 3 ACCGTAGTCGACTGGTTAACTTTGCGCGarrow_forward
- The sequence at one end of one strand of the Drosophilatransposon Mariner is shown below (dots indicatesequences within the transposon):5′ TTAGTTTGGCAAATATCTCCCTTCCGCCTTTTTGATCTTATGT... 3′You obtain a mutant bacterial strain tagged with anengineered Mariner transposon, cut the genomicDNA from this strain with the restriction enzymeMboI (whose recognition site is ^GATC), and circularize the resultant DNA fragments by diluting therestriction enzyme digest and adding DNA ligase.a. Design two 17 bp PCR primers that you could useto identify (by inverse PCR) the gene into whichthe transposon inserted.b. What DNA sequence will be amplified from thecircularized fragments of the mutant genome?Show the extent of this DNA sequence on a mapof the genome of the mutant strain, indicating thelocations of the transposon insertion and any relevant sites for the enzyme MboI.arrow_forwardn yeast cells, telomerase remains active and maintains telomeres of about 300 base pairs. Propose what would happen to the telomeres over time in a yeast lineage in which the following mutations were created. The template portion of the telomerase RNA is changed from 5’-ACACCCACA to 5’-ACAUCUACA.arrow_forwardBelow is a portion of an exon from a gene that encodes protein X in the genome of the plant Arabidopsis. Wildtype DNA3’ TTC AAT GCT CCG AAT ACC 5’ template strand5’ AAG TTA CGA GGC TTA TGG 3’ non-template strand A new strain (Strain B) of Arabidopsis is identified with the same region of the gene coding for protein X: 3’ TTC AAT GCT CCC AAT ACC 5’ template strand5’ AAG TTA CGA GGG TTA TGG 3’ non-template strand Compare the two DNA sequences and look for any differences. Based on what you find a. There is no mutation in Strain B compared to Strain A. b. After the point of the mutation, all the amino acids encoded by the Strain B template will be different than the Strain A protein X. c. Protein X made from the Strain B template will be much shorter than protein X made from the Strain A template d. Protein X from Strain B will have one amino acid difference that would not affect protein function. e. There is a mutation but there will not be any difference in the…arrow_forward
- Briefly describe the experiment that demonstrates that the transposition of the Ty1 element in yeast takes place through an RNA intermediate.arrow_forwardThe stringency of PCR amplification can be controlled by altering the temperature at which the primers and the target DNA undergo hybridization. How would altering the temperature of hybridization affect the amplification? Suppose that you have a particular yeast gene A and that you wish to see if it has a counterpart in humans. How would controlling the stringency of the hybridization help youarrow_forwardThe figure below shows the introns and exons found in gene X. The size of each exon and intron is shown as well. A study on this organism found that two mature mRNA molecules are produced for this gene. One is 457 nucleotides in length, and the other is 439 nucleotides in length. Name the process responsible for producing this variation. Also explain how these 457 and 439 nucleotide fragments were produced by referring to the information provided. Hint: This organism produces a poly-A tail of 120 nucleotides.arrow_forward
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