In Problems 11–16 verify that the
11.
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Chapter 8 Solutions
First Course in Differential Equations (Instructor's)
- 1. 2. 3. Write v as a linear combination of u and w, if possible, where u = (2, 3) and w = (1, -1). (Enter your answer in terms of u and w. If not possible, enter IMPOSSIBLE.) v = (-2, -3) V = Solve for w where u = (1, 0, -1, 1) and v = (2, 0, 3, -1). w + 2v = -4u W = Write each vector as a linear combination of the vectors in S. (If not possible, enter IMPOSSIBLE.) S = {(2, -1, 3), (5, 0, 4)) (a) z = (7, -6, 14). Z= (b) v = V = (c) w = (3,-9, 15) W = (d) v = (18, - 1, 59) )$₁ U= $₁ + u = (2, 1, -1) )$₁arrow_forward[1 1 1] 024. The system of equations | 0 0 1x=| b, | is solvable if |0 0 1 b, (c) b, = b, (d) b, = 0 (e) none (a) h, = b, = 0 (b) b, = b, # 0 025. If A = B+C and B= B' and C' =-C, then %3D %3D (1) C = A– A" »C=÷(4- A') (6) C=;(4+A") (4) C = A+ A" (e) none c=-(4-A') (0) C = (A+ A°) («)C= A+ A°arrow_forward4. (S.10). Use Gaussian elimination with backward substitution to solve the following linear system: 2.r1 + 12 – 13 = 5, 1 + 12 – 3r3 = -9, -I1 + 12 +2r3 = 9;arrow_forward
- 2. Which of the following is a general solution to the following: x²y" + xy' + (36x² - 1) y (Hint: As discussed in the lecture, use Y, only when J, and J-, are linearly dependent). A. y = c₁J₁(2x) + C₂J_1(2x) 6 B. y = C₁J₁(x) + C₂Y₁(x) 3 3 C. y = c₁₂/₁(6x) + C₂Y₁(6x) 0 D. y = c₁J₁(6x) + c₂] _1(6x) 2arrow_forward1. If y = (x + 1/x) (2x-3, then dy/dx will be ? 2. If matrix A is (2 5) (3 4) and f (x) = x2 +4 , what is the answer to f (A)?arrow_forward1. Find the linearization of x3 − x at a = 2.arrow_forward
- Question 9 Find all the roots of z3 – 3(5 +j) = 0 and give the answers in rectangular form. Question 10 Use Crammer's rule to solve the following linear system for y only. 2x – 3y = 3 – z 4x +y = -4 = 3y + z-2 İLIFE Digitalarrow_forward9. Solve the given (matrix) linear system: [1 X' = |1 1 X -31 5 L2 4arrow_forward2. Find if y=x +3x-7 and x 21+1. dtarrow_forward
- The matrix that projects onto the line y = -x is X 0.6 0.8 0.8 -0.6arrow_forward2. In the linear system Ax = b, 27 b = 2 A = 6 (a) Show that x = be a solution of the linear system. 7 (b) Show that b can be expressed as a linear combination of columns of A with scalars 1, -1, and 7. (c) Find x A if it is defined. Whey x is not a solution of ATx = b?arrow_forwardWrite the given linear system without the use of matrices. (1)-(1)-·-(-)) -t + 2 e 2 X d - D y. dt 1 Z 8 dx dt dy dt dz dt || = )-(-3 1 -1 9 X -6 -2 5 y 3arrow_forward
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