Explanation Given information: According to Maxwell’s Distribution law, in a gas molecular mass m, speed v of a molecule in a gas at temperature T (kelvins) is a random variable with density p ( v ) = 4 π ( m 2 π k T ) 3 2 v 2 e − m v 2 2 k T ( v ≥ 0 ) Where k is the Boltzmann’s constant. The average speed of oxygen molecule at room temperature isaround 450 m/s. Formula used: Mean, μ = ∫ − ∞ ∞ x p ( x ) d x Calculation: p ( v ) = 4 π ( m 2 π k T ) 3 2 v 2 e − m v 2 2 k T ( v ≥ 0 ) (Given) The average molecular speed formula is given by μ = ∫ − ∞ ∞ v p ( v ) d v = ∫ 0 450 v 4 π ( m 2 π k T ) 3 2 v 2 e − m v 2 2 k T d v = 4 π ( m 2 π k T ) 3 2 ∫ 0 450 v . v 2 e − m v 2 2 k T d v = 4 π ( m 2 π k T ) 3 2 ∫ 0 450 v 3 e − m v 2 2 k T d v = 4 π ( m 2 π k T ) 3 2 [ − ( m 2 k T v 2 + 1 ) e − m v 2 2 k T 2 ( m 2 k T ) 2

4th Edition

ISBN: 9781319379421

Author: Rogawski

Publisher: MAC HIGHER

See similar textbooks

Concept explainers

Continuous Probability Distributions

Probability distributions are of two types, which are continuous probability distributions and discrete probability distributions. A continuous probability distribution contains an infinite number of values. For example, if time is infinite: you could co…

Normal Distribution

Suppose we had to design a bathroom weighing scale, how would we decide what should be the range of the weighing machine? Would we take the highest recorded human weight in history and use that as the upper limit for our weighing scale? This may not be a…

Videos

Question

Chapter 8.1, Problem 24E

To determine

To prove:

The average molecular speed is equal to (8kTπm)12.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 8.1, Problem 23E

Chapter 8.1, Problem 25E

Students have asked these similar questions

According to the Maxwell-Boltzmann law of theoretical physics, the pdf of V, the velocity of a gas molecule is given by kv² e-av² v > 0 f,(0) = elsewhere where a is a constant depending on its mass and the absolute temperature and k is an appropriate constant. Show that the kinetic energy Y = mV² is a random variable having Gamma distribution.

x and y are random variables with joint PDF 2. fxiy (x.y)= other a) marginal PDF fx(x)? b) marginal POE fy(Y)?

According to the Maxwell–Boltzmann law of theoret-ical physics, the probability density of V, the velocity of a gas molecule, isf(v) =⎧⎨⎩kv2e−βv2for v > 00 elsewhere where β depends on its mass and the absolute tem-perature and k is an appropriate constant. Show that the kinetic energy E = 1 2mV2, where m the massof the molecule is a random variable having a gammadistribution.

Chapter 8 Solutions

CALCULUS 4E (HC) W/ ACHIEVE ACCESS

Ch. 8.1 - Prob. 1PQ Ch. 8.1 - Prob. 2PQ Ch. 8.1 - Prob. 3PQ Ch. 8.1 - Prob. 1E Ch. 8.1 - Prob. 2E Ch. 8.1 - Prob. 3E Ch. 8.1 - Prob. 4E Ch. 8.1 - Prob. 5E Ch. 8.1 - Prob. 6E Ch. 8.1 - Prob. 7E

Ch. 8.1 - Prob. 8E Ch. 8.1 - Prob. 9E Ch. 8.1 - Prob. 10E Ch. 8.1 - Prob. 11E Ch. 8.1 - Prob. 12E Ch. 8.1 - Prob. 13E Ch. 8.1 - Prob. 14E Ch. 8.1 - Prob. 15E Ch. 8.1 - Prob. 16E Ch. 8.1 - Prob. 17E Ch. 8.1 - Prob. 18E Ch. 8.1 - Prob. 19E Ch. 8.1 - Prob. 20E Ch. 8.1 - Prob. 21E Ch. 8.1 - Prob. 22E Ch. 8.1 - Prob. 23E Ch. 8.1 - Prob. 24E Ch. 8.1 - Prob. 25E Ch. 8.1 - Prob. 26E Ch. 8.1 - Prob. 27E Ch. 8.1 - Prob. 28E Ch. 8.1 - Prob. 29E Ch. 8.1 - Prob. 30E Ch. 8.1 - Prob. 31E Ch. 8.1 - Prob. 32E Ch. 8.2 - Prob. 1PQ Ch. 8.2 - Prob. 2PQ Ch. 8.2 - Prob. 3PQ Ch. 8.2 - Prob. 4PQ Ch. 8.2 - Prob. 5PQ Ch. 8.2 - Prob. 1E Ch. 8.2 - Prob. 2E Ch. 8.2 - Prob. 3E Ch. 8.2 - Prob. 4E Ch. 8.2 - Prob. 5E Ch. 8.2 - Prob. 6E Ch. 8.2 - Prob. 7E Ch. 8.2 - Prob. 8E Ch. 8.2 - Prob. 9E Ch. 8.2 - Prob. 10E Ch. 8.2 - Prob. 11E Ch. 8.2 - Prob. 12E Ch. 8.2 - Prob. 13E Ch. 8.2 - Prob. 14E Ch. 8.2 - Prob. 15E Ch. 8.2 - Prob. 16E Ch. 8.2 - Prob. 17E Ch. 8.2 - Prob. 18E Ch. 8.2 - Prob. 19E Ch. 8.2 - Prob. 20E Ch. 8.2 - Prob. 21E Ch. 8.2 - Prob. 22E Ch. 8.2 - Prob. 23E Ch. 8.2 - Prob. 24E Ch. 8.2 - Prob. 25E Ch. 8.2 - Prob. 26E Ch. 8.2 - Prob. 27E Ch. 8.2 - Prob. 28E Ch. 8.2 - Prob. 29E Ch. 8.2 - Prob. 30E Ch. 8.2 - Prob. 31E Ch. 8.2 - Prob. 32E Ch. 8.2 - Prob. 33E Ch. 8.2 - Prob. 34E Ch. 8.2 - Prob. 35E Ch. 8.2 - Prob. 36E Ch. 8.2 - Prob. 37E Ch. 8.2 - Prob. 38E Ch. 8.2 - Prob. 39E Ch. 8.2 - Prob. 40E Ch. 8.2 - Prob. 41E Ch. 8.2 - Prob. 42E Ch. 8.2 - Prob. 43E Ch. 8.2 - Prob. 44E Ch. 8.2 - Prob. 45E Ch. 8.2 - Prob. 46E Ch. 8.2 - Prob. 47E Ch. 8.2 - Prob. 48E Ch. 8.2 - Prob. 49E Ch. 8.2 - Prob. 50E Ch. 8.2 - Prob. 51E Ch. 8.2 - Prob. 52E Ch. 8.2 - Prob. 53E Ch. 8.2 - Prob. 54E Ch. 8.2 - Prob. 55E Ch. 8.2 - Prob. 56E Ch. 8.2 - Prob. 57E Ch. 8.2 - Prob. 58E Ch. 8.2 - Prob. 59E Ch. 8.2 - Prob. 60E Ch. 8.2 - Prob. 61E Ch. 8.2 - Prob. 62E Ch. 8.2 - Prob. 63E Ch. 8.2 - Prob. 64E Ch. 8.2 - Prob. 65E Ch. 8.3 - Prob. 1PQ Ch. 8.3 - Prob. 2PQ Ch. 8.3 - Prob. 3PQ Ch. 8.3 - Prob. 4PQ Ch. 8.3 - Prob. 5PQ Ch. 8.3 - Prob. 1E Ch. 8.3 - Prob. 2E Ch. 8.3 - Prob. 3E Ch. 8.3 - Prob. 4E Ch. 8.3 - Prob. 5E Ch. 8.3 - Prob. 6E Ch. 8.3 - Prob. 7E Ch. 8.3 - Prob. 8E Ch. 8.3 - Prob. 9E Ch. 8.3 - Prob. 10E Ch. 8.3 - Prob. 11E Ch. 8.3 - Prob. 12E Ch. 8.3 - Prob. 13E Ch. 8.3 - Prob. 14E Ch. 8.3 - Prob. 15E Ch. 8.3 - Prob. 16E Ch. 8.3 - Prob. 17E Ch. 8.3 - Prob. 18E Ch. 8.3 - Prob. 19E Ch. 8.3 - Prob. 20E Ch. 8.3 - Prob. 21E Ch. 8.3 - Prob. 22E Ch. 8.3 - Prob. 23E Ch. 8.3 - Prob. 24E Ch. 8.3 - Prob. 25E Ch. 8.3 - Prob. 26E Ch. 8.3 - Prob. 27E Ch. 8.3 - Prob. 28E Ch. 8.3 - Prob. 29E Ch. 8.3 - Prob. 30E Ch. 8.4 - Prob. 1PQ Ch. 8.4 - Prob. 2PQ Ch. 8.4 - Prob. 3PQ Ch. 8.4 - Prob. 4PQ Ch. 8.4 - Prob. 5PQ Ch. 8.4 - Prob. 6PQ Ch. 8.4 - Prob. 1E Ch. 8.4 - Prob. 2E Ch. 8.4 - Prob. 3E Ch. 8.4 - Prob. 4E Ch. 8.4 - Prob. 5E Ch. 8.4 - Prob. 6E Ch. 8.4 - Prob. 7E Ch. 8.4 - Prob. 8E Ch. 8.4 - Prob. 9E Ch. 8.4 - Prob. 10E Ch. 8.4 - Prob. 11E Ch. 8.4 - Prob. 12E Ch. 8.4 - Prob. 13E Ch. 8.4 - Prob. 14E Ch. 8.4 - Prob. 15E Ch. 8.4 - Prob. 16E Ch. 8.4 - Prob. 17E Ch. 8.4 - Prob. 18E Ch. 8.4 - Prob. 19E Ch. 8.4 - Prob. 20E Ch. 8.4 - Prob. 21E Ch. 8.4 - Prob. 22E Ch. 8.4 - Prob. 23E Ch. 8.4 - Prob. 24E Ch. 8.4 - Prob. 25E Ch. 8.4 - Prob. 26E Ch. 8.4 - Prob. 27E Ch. 8.4 - Prob. 28E Ch. 8.4 - Prob. 29E Ch. 8.4 - Prob. 30E Ch. 8.4 - Prob. 31E Ch. 8.4 - Prob. 32E Ch. 8.4 - Prob. 33E Ch. 8.4 - Prob. 34E Ch. 8.4 - Prob. 35E Ch. 8.4 - Prob. 36E Ch. 8.4 - Prob. 37E Ch. 8.4 - Prob. 38E Ch. 8.4 - Prob. 39E Ch. 8.4 - Prob. 40E Ch. 8.4 - Prob. 41E Ch. 8.4 - Prob. 42E Ch. 8.4 - Prob. 43E Ch. 8.4 - Prob. 44E Ch. 8.4 - Prob. 45E Ch. 8.4 - Prob. 46E Ch. 8.4 - Prob. 47E Ch. 8.4 - Prob. 48E Ch. 8.4 - Prob. 49E Ch. 8.4 - Prob. 50E Ch. 8.4 - Prob. 51E Ch. 8 - Prob. 1CRE Ch. 8 - Prob. 2CRE Ch. 8 - Prob. 3CRE Ch. 8 - Prob. 4CRE Ch. 8 - Prob. 5CRE Ch. 8 - Prob. 6CRE Ch. 8 - Prob. 7CRE Ch. 8 - Prob. 8CRE Ch. 8 - Prob. 9CRE Ch. 8 - Prob. 10CRE Ch. 8 - Prob. 11CRE Ch. 8 - Prob. 12CRE Ch. 8 - Prob. 13CRE Ch. 8 - Prob. 14CRE Ch. 8 - Prob. 15CRE Ch. 8 - Prob. 16CRE Ch. 8 - Prob. 17CRE Ch. 8 - Prob. 18CRE Ch. 8 - Prob. 19CRE Ch. 8 - Prob. 20CRE Ch. 8 - Prob. 21CRE Ch. 8 - Prob. 22CRE Ch. 8 - Prob. 23CRE Ch. 8 - Prob. 24CRE Ch. 8 - Prob. 25CRE Ch. 8 - Prob. 26CRE Ch. 8 - Prob. 27CRE Ch. 8 - Prob. 28CRE

Knowledge Booster

$Calculus$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.

To prove: The average molecular speed is equal to ( 8 k T π m ) 1 2 .

Solution Summary: The author explains Maxwell's distribution law, where speed v is a random variable with density. The average speed of oxygen molecule at room temperature is around 450 m/s.

Concept explainers

Videos

To prove:

The average molecular speed is equal to (8kTπm)12.

Want to see the full answer?

Chapter 8 Solutions

To prove: The average molecular speed is equal to ( 8 k T π m ) 1 2 .

Solution Summary: The author explains Maxwell's distribution law, where speed v is a random variable with density. The average speed of oxygen molecule at room temperature is around 450 m/s.

Concept explainers

Videos

To prove: The average molecular speed is equal to (8kTπm)12.

Want to see the full answer?

Chapter 8 Solutions

To prove:

The average molecular speed is equal to (8kTπm)12.