In Problems 21–30 find the general solution of the given system.
28.
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- Problem 2. Consider the equation: x?y"(x) – xy' +y = 0. Given that yı(x) = x is a solution of this equation. Use the method of reduction of order, find the second solution y2(x) of the equation so that y1 and y2 are linearly independent. (Hint: y2(x) should be given in the form y2(x) = u(x)y1(x). Substitute it into the equation to find u(x).) %3Darrow_forwardQuestion. Solve: x" -x + 5y² = + 4" - 4y - 2x² = -2 with x (0) = y(0) = x²(0) = y₁ (0) = 0 Let & [ X (²) } = U (6) & & Gy (+) 2 = V(c) Evaluate U(2) Evaluate (²) Evaluate x(1) Evaluate y(1)arrow_forwardProblem 16 (#2.3.34).Let f(x) = ax +b, and g(x) = cx +d. Find a condition on the constants a, b, c, d such that f◦g=g◦f. Proof. By definition, f◦g(x) = a(cx +d) + b=acx +ad +b, and g◦f(x) = c(ax +b) + d=acx +bc +d. Setting the two equal, we see acx +ad +b=acx +bc +d ad +b=bc +d (a−1)d=(c−1)b That last step was merely added for aesthetic reasons.arrow_forward
- Determine the solution of (2x - 3y + 2)dx + (2x - 3y + 1)dy = 0. a. 10x + 10y + ln(10x - 15y + 8)2 = c b. 10x + 10y + ln(10x - 15y - 8)2 = c c. 10x - 10y + ln(10x + 15y + 8)2 = c d. 10x - 10y - ln(10x + 15y + 8)2 = carrow_forward1. Find the solution to the initial value problem 4x3 + 1 2у — 6 y(1) = 2. A. y = 3 – Vxª + x – 1 B. y = 2+ Vx³ + x – 2 C. y = 1+ Vx4 + x – 1 D. y = 4 – V4x³ + x – 1 E. y = V4³ + x – 1arrow_forward9arrow_forward
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