Let S = { 0 , 1 } and consider the partial order relation R defined on S × S as follows: For all ordered pairs ( a , b ) and ( c , d ) S × S , ( a , b ) R ( c , d ) ⇔ a ≤ c and b ≤ d , Where ≤ denotes the usual “less than or equal to” relation for real numbers. Draw the Hasse digram for R .
Let S = { 0 , 1 } and consider the partial order relation R defined on S × S as follows: For all ordered pairs ( a , b ) and ( c , d ) S × S , ( a , b ) R ( c , d ) ⇔ a ≤ c and b ≤ d , Where ≤ denotes the usual “less than or equal to” relation for real numbers. Draw the Hasse digram for R .
Solution Summary: The author explains the Hasse diagram for R, which is made by elimination loops, arrows and transitive relation.
Let
S
=
{
0
,
1
}
and consider the partial order relation R defined on
S
×
S
as follows: For all ordered pairs
(
a
,
b
)
and
(
c
,
d
)
S
×
S
,
(
a
,
b
)
R
(
c
,
d
)
⇔
a
≤
c
and
b
≤
d
,
Where
≤
denotes the usual “less than or equal to” relation for real numbers. Draw the Hasse digram for R.
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RELATIONS-DOMAIN, RANGE AND CO-DOMAIN (RELATIONS AND FUNCTIONS CBSE/ ISC MATHS); Author: Neha Agrawal Mathematically Inclined;https://www.youtube.com/watch?v=u4IQh46VoU4;License: Standard YouTube License, CC-BY