Chapter 8.6, Problem 41P

Factor each expression completely.

$41.28y^2+43y-48$

To determine

To find: The factorization of $28y^2+43y-48$

Answer to Problem 41P

  $(4y-3)(7y+16)$

Explanation of Solution

Given information: $28y^2+43y-48$

Calculation:

  $\begin{array}{l}28y^2+43y-48\\ =28y^2+(64-21)y-48\\ =28y^2+64y-21y-48\\ =(28y^2+64y)-(21y+48)\\ =4y(7y+16)-3(7y+16)\\ =(4y-3)(7y+16)\end{array}$

Thus, $28y^2+43y-48=(4y-3)(7y+16)$