Concept explainers
(a)
Interpretation:
The percent by mass of the element whose symbol occurs first in the following compound’s formula should be calculated.
Concept Introduction:
Percent by mass of an element can be calculated by the following equation.
Answer to Problem 16CR
Percentage of C per mole of C6 H6 ( l ) by mass =
Explanation of Solution
Molar mass of C6 H6 ( l ) =
Mass of C present per mole of C6 H6 =
Percentage of C per mole of C6 H6 ( l ) by mass =
=
(b)
Interpretation:
The percent by mass of the element whose symbol occurs first in the following compound’s formula should be calculated.
Concept Introduction:
Percent by mass of an element can be calculated by the following equation.
Answer to Problem 16CR
Percentage of Na per mole of Na2 SO4 by mass =
Explanation of Solution
Molar mass of Na2 SO4 ( s ) =
Mass of Na present per mole of Na2 SO4 =
Percentage of Na per mole of Na2 SO4 by mass =
=
(c)
Interpretation:
The percent by mass of the element whose symbol occurs first in the following compound’s formula should be calculated.
Concept Introduction:
Percent by mass of an element can be calculated by the following equation.
Answer to Problem 16CR
Percentage of C per mole of CS2 ( l ) by mass =
Explanation of Solution
Molar mass of CS2 ( l ) =
Mass of C present per mole of CS2 ( l ) =
Percentage of C per mole of CS2 ( l ) by mass =
=
(d)
Interpretation:
The percent by mass of the element whose symbol occurs first in the following compound’s formula should be calculated.
Concept Introduction:
Percent by mass of an element can be calculated by the following equation.
Answer to Problem 16CR
Percentage of Al per mole of AlCl3 ( s ) by mass =
Explanation of Solution
Molar mass of AlCl3 ( s ) =
Mass of Al present per mole of AlCl3 ( s ) =
Percentage of Al per mole of AlCl3 ( s ) by mass =
=
(e)
Interpretation:
The percent by mass of the element whose symbol occurs first in the following compound’s formula should be calculated.
Concept Introduction:
Percent by mass of an element can be calculated by the following equation.
Answer to Problem 16CR
Percentage of Cu per mole of Cu2 O( s ) by mass =
Explanation of Solution
Molar mass of Cu2 O( s ) =
Mass of Cu present per mole of Cu2 O( s ) =
Percentage of Cu per mole of Cu2 O( s ) by mass =
=
(f)
Interpretation:
The percent by mass of the element whose symbol occurs first in the following compound’s formula should be calculated.
Concept Introduction:
Percent by mass of an element can be calculated by the following equation.
Answer to Problem 16CR
Percentage of Cu per mole of CuO( s ) by mass =
Explanation of Solution
Molar mass of CuO( s ) =
Mass of Cu present per mole of CuO( s ) =
Percentage of Cu per mole of CuO( s ) by mass =
=
(g)
Interpretation:
The percent by mass of the element whose symbol occurs first in the following compound’s formula should be calculated.
Concept Introduction:
Percent by mass of a element can be calculated by the following equation.
Answer to Problem 16CR
Percentage of Co per mole of Co2 O3 ( s ) by mass =
Explanation of Solution
Molar mass of Co2 O3 ( s ) =
Mass of Co present per mole of Co2 O3 ( s ) =
Percentage of Co per mole of Co2 O3 ( s ) by mass =
=
(h)
Interpretation:
The percent by mass of the element whose symbol occurs first in the following compound’s formula should be calculated.
Concept Introduction:
Percent by mass of a element can be calculated by the following equation.
Answer to Problem 16CR
Percentage of C per mole of C6 H1 2 O6 ( s ) by mass =
Explanation of Solution
Molar mass of C6 H1 2 O6 ( s ) =
Mass of C present per mole of C6 H1 2 O6 ( s ) =
Percentage of C per mole of C6 H1 2 O6 ( s ) by mass =
=
Want to see more full solutions like this?
Chapter 9 Solutions
Introductory Chemistry: A Foundation 8th Edition Access Code
- The empirical formula of a gaseous fluorocarbon is CF2 . At a certain temperature and pressure, a 1-L volume holds 8.93 g of this fluorocarbon, whereas under the same conditions, the 1-L volume holds only 1.70 g gaseous fluorine (F2) . Determine the molecular formula of this compound.arrow_forwardAn air bag is deployed by utilizing the following re tion the nitrogen gas produced inflates the air bag): :math>2NaN3(s)2Na(s)+3N2(g) 10.5 g of NaN1 is decomposed, what theoretical mass of sodium should be produced? If only 2.84 g of sodium is actually collected, what is the percent yield?arrow_forwardA chemist prepared a compound that she thought had the formula FeI3. When the compound was analyzed, it contained 18.0% Fe and 82.0% I. Calculate the mass percentage composition expected for FeI3 and compare the result with that found in the analysis. Is this the correct formula of the compound?arrow_forward
- Solid calcium carbide (CaC2)reacts with liquid water to produce acetylene gas (C2H2)and aqueous calcium hydroxide. l type='a'> Write the balanced equation for the reaction that is (occurring. including all phases. If a 100.0-g sample of calcium carbide (CaC2)is initially reacted with 50.0 g of water, which reactant is limiting? Prove that mass is conserved for the reactant amounts used in pan b.arrow_forwardA binary compound of magnesium and nitrogen is analyzed, and 1.2791 g of the compound ¡s found to contain 0.9240 g of magnesium. When a second sample of this compound is treated with water and heated, the nitrogen is driven off as ammonia, leaving a compound that contains 60.31% magnesium and 39.69% oxygen by mass. Calculate the empirical formulas of the two magnesium compounds.arrow_forwardSuppose that Si28(1428Si) is taken as the standard for expressing atomic masses and assigned an atomic mass of 10.00 amu. Estimate the molar mass of sodium nitride.arrow_forward
- Atoms of three different elements are represented by O, , and . Which compound is left over when three molecules of O. and three molecules of . react to form O. And O?arrow_forwardA mixture of CuSO4 and CuSO4.5 H2O has a mass of 1.245 g. After heating to drive off all the water, the mass is only 0.832 g. What is the mass percent of CuSO4.5H2O in the mixture? (See page 98.)arrow_forwardSuppose Avogadro’s number was 1000 instead of 6.0221023 . How, if at all, would this affect the relative masses on the periodic table? How, if at all, would this affect the absolute masses of the elements?arrow_forward
- It sodium peroxide is added to water, elemental oxygen gas is generated: :math>Na2O2(s)+H2O(l)NaOH(aq)+O2(g) ppose 3.25 g of sodium peroxide is added to a large excess of water. What mass of oxygen gas will be produced?arrow_forwardSodium borate decahydrate, Na2B4O710H2O is commonly known as borax. It is used as a deodorizer and mold inhibitor. A sample weighing 15.86 g is heated until a constant mass is obtained indicating that all the water has been evaporated off. (a) What percent, by mass of Na2B4O710H2O is water? (b) What is the mass of the anhydrous sodium borate, Na2B4O7?arrow_forward
- Introductory Chemistry: A FoundationChemistryISBN:9781285199030Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning